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Oxidation Reduction.

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Presentation on theme: "Oxidation Reduction."— Presentation transcript:

1 Oxidation Reduction

2 Redox OIL of electrons RIG of electrons Oxidation Is Loss Reduction Is
Gain of electrons

3 Rxns Oxidation Mg(s) + S(s) MgS(s) Reduction

4 Cont Mg(s) + S(s) MgS(s)
Reducing agent – substance in redox rxn that loses electrons is called a reducing agent. Oxidation Mg(s) + S(s) MgS(s) Reducing Agent Reduction

5 Cont. Mg(s) + S(s) MgS(s)
Oxidizing agent – substance in redox rxn that accepts electrons is called an oxidizing agent. Oxidation Mg(s) + S(s) MgS(s) Reduction Oxidizing Agent

6 Assigning Oxidation #’s
Rules Monatomic ion = to ionic charge Hydrogen (in compound) Metal Hydrides –1 (NaH) Oxygen (in compound) – Peroxides –1 (H2O2) Oxidation # of an atom in elemental form = 0

7 Cont. Neutral compound must = 0
Polyatomic ion – sum of oxidation #’s must = ionic charge

8 Half Reactions Way of showing either the reduction or the oxidation of a species in an redox reaction.

9 Acid Half RXN Step 1: Write the unbalanced equation in ionic form

10 Cont. Step 2: Write separate rxns for the oxidation and reduction processes

11 Cont. Step 3: Balance the atoms in the half-rxns

12 Cont. Step 4: Balance charges

13 Cont. Step 5: Multiply each half-rxn by the appropriate number

14 Cont. Step 6: Add the half rxns

15 Base Half RXN Step 1: Write the unbalanced equation in ionic form

16 Cont. Step 2: Write separate half-reactions for the oxidation and reduction processes

17 Cont. Step 3: Balance the atoms

18 Cont. Step 4: Balance charges

19 Cont. Step 5: Multiply each half reaction by the appropriate number

20 Cont. Step 6: Add the half reactions

21 Practice!!!!!!!


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