1. Warm-up:
1) Find the standard form of the equation of the parabola given:
the vertex is (3, 1) and focus is (5, 1)
2) Graph a sketch of (x – 3)2 = 16y

2. 17) (x – 1)2 + 8(y + 2) = 0 or (x – 1)2 = -8(y + 2)
HW: pg. 372 (17, 18, 25, 26) Answers
17) (x – 1)2 + 8(y + 2) = 0 or (x – 1)2 = -8(y + 2)
Vertex: (1, -2)
Focus: (1, -4)
Directrix: y = 0 V F

3. 18) (x + 3) + (y – 2)2 = 0 or (y – 2)2 = -1(x + 3)
Vertex: (-3, 2)
Focus: (-13/4, 2)
Directrix: x = -11/12 F V

4. Vertex: (3, 2)
Focus: (1, 2)
(y – 2)2 = -8(x – 3)
26)Vertex: (-1, 2)
Focus: (-1, 0)
(x + 1)2 = -8(y – 2)

5. Sneedlegrit:
Find the standard form of the equation of the parabola given:
the vertex is (2, -1) and focus is (2, 0)
CW: Equations of Parabolas