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X  X = 20m = diagonal = diameter x x

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Presentation on theme: "X  X = 20m = diagonal = diameter x x"— Presentation transcript:

1 X  X = 20m = diagonal = diameter x x
You want to use chalk to create the outline of the center circle of the school soccer field. The circle must span from the left to right wing positions, which are 20m apart. You will need 1kg of chalk to cover 4m of ground effectively. How much chalk will you need? X  X = 20m = diagonal = diameter x x

2 Diameter = 20m perimeter = distance around = circumference = ? x x
You want to use chalk to create the outline of the center circle of the school soccer field. The circle must span from the left to right wing positions, which are 20m apart. You will need 1kg of chalk to cover 4m of ground effectively. How much chalk will you need? Diameter = 20m perimeter = distance around = circumference = ? x x

3 Ratio = perimeter / diagonal Diameter = 20m pi = Circumference /
You want to use chalk to create the outline of the center circle of the school soccer field. The circle must span from the left to right wing positions, which are 20m apart. You will need 1kg of chalk to cover 4m of ground effectively. How much chalk will you need? Ratio = perimeter / diagonal Diameter = 20m pi = Circumference / Diameter Circumference = ? 3.14 = ? / 20m x x

4 C = pi * d = pi Circumference / Diameter Ratio = perimeter diagonal
3.14 = ? / 20m * 3.14 20m ? = Circumference 62.8m = C = pi * d

5 How much chalk will you need?
You want to use chalk to create the outline of the center circle of the school soccer field. The circle must span from the left to right wing positions, which are 20m apart. You will need 1kg of chalk to cover 4m of ground effectively. How much chalk will you need? Circumference 62.8m = How much chalk will you need? 62.8m / 4m = amount of chalk 15.7 kg = amount of chalk

6 Therefore, I will need 15.7 kg of chalk to create the outline of the center circle of the school soccer field. x x


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