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Empirical & Molecular Formula
SCH4C Ms. Richardson
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Empirical & Molecular Formula
In Dalton’s atomic theory, he stated that atoms will combine with one another in simple, whole number ratios to form compounds. An example of a molecular formula (the actual formula) is C6H6. This is Benzene. An example of a simple whole number ratio, or the empirical formula for Benzene would be CH.
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Comparing molecular and empirical formulas
Name of Compound Molecular Formula Empirical Formula hydrogen peroxide H2O2 HO glucose C6H12O6 CH2O benzene C6H6 CH ethyne C2H2 water H2O
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Determining Empirical Formula
You already know how to calculate percent composition. In this section, you will use percent composition to find the formula of the compound. These are the 3 steps to determining empirical formula. Determine the mass of the elements present. Determine the moles of the elements present. Divide the # of moles of each element by the lowest number of moles
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Empirical formula example
What is the empirical formula of a compound with 79.9 g of Cu and g of S? “Percent to mass Mass to mole Divide by small Multiply ‘til whole”
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Another example Calculate the empirical formula of a compound that has 85.6% carbon and 14.4% hydrogen. HINT: Assume that the percentage composition is based on 100g of the compound.
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A tricky Example What happens when the mole ratio does not give you nice whole numbers? The percent composition of a fuel is 81.7% carbon and 18.3% hydrogen. What is the empirical formula?
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Getting to whole numbers
0.2, 1.2, 2.2, 3.2……. Multiply by 5 0.25, 1.25, 2.25 … …Multiply by 4 0.3, 1.3, 2.3, 3.3…… Multiply by 3 0.5, 1.5, 2.5, 3.5…… Multiply by 2
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Molecular Formula Once we have determined the empirical formula (the smallest whole number ratio), we can determine the compound’s actual formula: Determine the molar mass of the empirical formula Divide the given molar mass by the molar mass of the empirical formula.
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