3. 1a.
The thermal energy store of the ball and the surroundings increases.
The gravitational energy store of the ball decreases.
1b i) ∆GPE = weight x ∆h
∆GPE = N x ( 2.5m m )
∆GPE = N x ( 0.8 m)
∆GPE = J
1bii) Air resistance and in elastic deformation of the ball causes a rise in the thermal store
of the ball and its surroundings.

4. 2a i) ∆GPE = weight x ∆h
∆GPE = N x ( 0.2m )
∆GPE = J
2bi) ∆GPE = J x times
2bii) ∆GPE = , J

5. 3a i) ∆GPE = mass x gravitational field strength x ∆h
∆GPE = kg x N/kg x m
∆GPE = J
3b ii) ∆ GPE = mass x gravitational field strength x ( 1.8m – 0.3m )
∆ GPE = kg x N/kg x ( 1.8 – 0.3 ) m
∆ GPE = kg x N/kg x ( 1.8 – 0.3 ) m
∆ GPE = J or J ( to 2 sig figs )

6. 4.
The thermal energy store of the surroundings increases.