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Electrical Machines LSEGG216A 9080V.

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Presentation on theme: "Electrical Machines LSEGG216A 9080V."— Presentation transcript:

1 Electrical Machines LSEGG216A 9080V

2 Transformer

3 Basic of Transformer A basic transformer consists of two sets of coils or windings. Each set of windings is simply an inductor. AC voltage is applied to one of the windings, called the primary winding. The other winding, called the secondary winding, is positioned in close proximity to the primary winding, but is electrically isolated from it.

4 Transformer Losses & Efficiency

5 Objectives Describe the power losses which occur in a transformer
Describe the tests which allow the power losses of a transformer to be calculated Calculate transformer losses and efficiency using test results Define the all day efficiency of a transformer Calculate the all day efficiency of a transformer Describe the relationship between transformer cooling and rating

6 Objectives Calculate the all day efficiency of a transformer
Describe the relationship between transformer cooling and rating Describe the methods of cooling List the properties of transformer oil Describe the tests conducted on transformer oil

7 Transformer Ratings Volt Amps VA
Transformers are rated to supply a given output in Volt Amps or VA at a specified frequency and terminal voltage.

8 Transformer Ratings They are NOT rated in Watts
The load power factor is unknown

9 Transformer Ratings They are NOT rated in Watts
The load power factor is unknown

10 Student Exercise 1

11 Ratio between Input power and Output Power
Efficiency Ratio between Input power and Output Power

12 Efficiency is normally expressed as a percentage

13 Transformer Efficiency
Power In Power Out Overcome Copper Losses Overcome Iron Losses Some Power is used to:

14 Transformer Losses Copper Losses (Cu) Varies with load current
Produces HEAT Created by resistance of windings Short circuit test supplies copper losses

15 Transformer loaded at 50%
Short Circuit Test Copper Losses (Cu) Finds Cooper losses at full load Copper losses vary with the square of the load Full load Cu loss = 100 W Transformer loaded at 50% PCu = 25 W

16 Copper Losses (Cu) Cu Losses (W) % Load

17 Transformer Losses Iron Losses (Fe) Fixed Always present
Related to transformers construction Eddy Currents Hysteresis Reduced by laminations Produces HEAT Reduced by using special steels in laminations

18 Wattmeter indicates Iron Losses (Fe)
Open Circuit Test Finds Iron Losses (Fe) Full Supply Voltage Secondary Open Circuit Wattmeter indicates Iron Losses (Fe)

19 Cu FL= 840 W Fe = 220 W Sout = 30 kVA Calculate η%at 75%Load η% = 97%

20 η% Cu Losses Fe Losses Losses (W) η% % Load Fe = Cu =Max η

21 Air Oil Forced Natural Transformer Cooling and/or and/or
Transformer ratings can be increased if their windings are cooled by some external means The most common cooling mediums are in direct with transformer windings; Air Oil and/or The most common methods of circulation are Forced Natural and/or

22

23 Transformer Classification
Transformers are allocated symbols which indicate the type of cooling used Can consist of up to 4 letters indicating the cooling system 1st Letter 2nd Letter 3rd Letter 4th Letter The cooling medium in contact with the windings The cooling medium in contact with the external cooling system Kind of Medium Circulation type

24 Transformer Classification
Type AN Air Natural Dry Transformer with Natural Air Flow

25 Transformer Classification
Type AF Air Forced Dry Transformer with Forced Air Flow

26 Transformer Classification
Type ONAF Oil Natural Air Forced Oil Tank Cooling Natural Oil Flow - Forced Air Flow

27 Transformer Classification
Type OFAF Oil Forced Air Forced Oil Tank Cooling Forced Oil Flow – Forced Air Flow

28 Acts as Coolant & Insulator
Transformer Oil Acts as Coolant & Insulator Low Viscosity High Flash point Chemically inert Good insulator

29 THE END


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