1. From Ether to Matter to Ether by Francis Fernandes
CNPS 2018 International Conference
University of Connecticut, Storrs
© Francis Fernandes, 2018

2. In an unpublished paper entitled “Man’s Greatest Achievement”, Nikola Tesla, describes the concept of Ether as a primary substance, thrown into infinitesimal whirls of ‘prodigious’ velocity that becomes gross matter. Once these forces subside and the motion ceases, matter disappears, reverting to its primary substance. It is this primary substance or substance, discovered by Francis Fernandes through empirical physics and mathematical formulation that will provide a clear understanding of much of physics.
Ether
© Francis Fernandes, 2018

3. Bob Heaston The Assumption
You took a very imaginative, most intuitive, and quite coincidental step in equation 1 on page 2 of your paper. In taking this step you achieved the same result that Einstein did in applying the equivalence principle and equating the gravitational potential energy to the mass-energy equivalence m c 2 in his first step in deriving the GRT.
Bob Heaston
Senior Rocket Scientist NASA
The 186-ether mass
𝐸=𝐺 𝑚𝑚 𝑟 =𝑘 𝑒𝑒 𝑟
𝑚= × 10 −9 𝑘𝑔
The Assumption
© Francis Fernandes, 2018

4. Ether Mass and Radial Length
𝐺= 𝐵 ℘ × 𝑐 2 𝑜𝑟 𝐺= × 10 − × 10 −9 × 𝑐 2
𝑐 2 = × m s × m s
© Francis Fernandes, 2018

5. Gravitational Force is the strongest not the weakest as believed
The Ether Force: the cosmic gyration force, this GEM force is the strongest in the Universe
𝐸= × 10 −9 ×( × ) 2
𝐸= × 10 8
𝐸=𝐹×𝑅
𝐹= 𝐸 𝑅 = × × 10 −36
𝑭=𝟏.𝟐𝟏𝟎𝟐𝟕𝟑𝟕𝟎𝟖× 𝟏𝟎 𝟒𝟒 𝑵
Gravitational Force is the strongest not the weakest as believed
Ether Force
© Francis Fernandes, 2018

6. Bob Heaston s me in 2008 after my presentation via video link at an NPA conference at University of New Mexico
This superforce, which has the formula of the speed of light to the fourth power divided by the gravitational constant c4/G, is present in inverted form in the Einstein field equations of general relativity theory (GRT) along with the energy-density tensor form of the right-hand side of the GRT equations. - Bob Heaston Senior Rocket Scientist NASA
© Francis Fernandes, 2018

7. 𝑚 𝑃𝑙 ≡ ћc G =Planck Mass=2.176450474× 10 −8 kg
Planck Ether Mass
186 Ether Mass
Einstein actually predicts a collapse of matter to the superforce and the Planck scale. Just substitute the Planck length and the Planck mass into the Newton gravitational force. What you have derived in your paper is a direct link to the standard model and GRT. - Bob Heaston I introduced into Newton’s G the 186-ether magnitudes of mass and radial length at speed of light squared. - Francis Fernandes
𝑚 𝑃𝑙 ≡ ћc G =Planck Mass= × 10 −8 kg
or π B 2 × =π×(Planck length ) 2
I have discovered this correspondence in the dynamic living pulsation of ether
B= × 10 −36 m Torus radius
© Francis Fernandes, 2018

8. Ether Radial Distribution Constant
THE MATERIAL FABRIC of space is ether. The field is ether, and is expressed mathematically as
M / R = 1.34 x 1027 kg/radial m
Ether Radial Distribution Constant
© Francis Fernandes, 2018

9. Wave-Particle Duality Particles ripple Waves in the Field
© Francis Fernandes, 2018

10. Richard Feynman on the Hand of God
“There is a most profound and beautiful question associated with the observed coupling constant, e - the amplitude for a real electron to emit or absorb a real photon. It is a simple number that has been experimentally determined to be close to (My physicist friends won't recognize this number, because they like to remember it as the inverse of its square: about with about an uncertainty of about 2 in the last decimal place. It has been a mystery ever since it was discovered more than fifty years ago, and all good theoretical physicists put this number up on their wall and worry about it.) Immediately you would like to know where this number for a coupling comes from: is it related to pi or perhaps to the base of natural logarithms? Nobody knows. It's one of the greatest damn mysteries of physics: a magic number that comes to us with no understanding by man. You might say the "hand of God" wrote that number, and "we don't know how He pushed his pencil." We know what kind of a dance to do experimentally to measure this number very accurately, but we don't know what kind of dance to do on the computer to make this number come out, without putting it in secretly!”
Richard Feynman on the Hand of God
― Richard Feynman, QED: The Strange Theory of Light and Matter
© Francis Fernandes, 2018

11. 𝐦−𝐦 γ=2 Rydberg photon masses
I/II GAMMA Factor Here, Fernandes resolves Feynman’s query on the amplitude for a real electron to emit or absorb a real photon
𝐆𝐚𝐦𝐦𝐚 𝐅𝐚𝐜𝐭𝐨𝐫
γ=1− 𝑣 2 𝑐 2
𝑣= 𝑐
γ=1− 𝑣 2 𝑐 2 =
Mass of an electron, m times the Gamma factor yields a new measure of electron mass, m γ
Pair Production
𝐦−𝐦 γ=2 Rydberg photon masses
× 10 −31 kg− × 10 −31 kg=2× × 10 −35 kg
(Two Rydberg photon)
© Francis Fernandes, 2018

12. Source of the Bohr Radius Two Rydberg photons each of mass 2
Source of the Bohr Radius Two Rydberg photons each of mass × 10 −35 kg whose radius equals the Bohr Radius, r 𝑞 2 =2× × 10 −35 ×𝑟× 10 7 𝑟= × 10 −11 m Bohr radius Source of the Rydberg Constant: DeBroglie Equation: 𝑚 𝑐 𝜆= ℎ × 10 −35 ×𝑐×𝜆= ℎ The inverse of wavelength is the Rydberg constant or the wave number of the Rydberg photon observed in H-spectra.
II/II GAMMA Factor
© Francis Fernandes, 2018

13. The Rydberg Wave Number, v
Mass, m: × 10 −35 𝑘𝑔 Radius, R: × 10 −3 𝑚 𝑞 2 = × 10 −35 × × 10 −10 × 10 7 𝐶 2 Wavelength λ=2π×𝑅× 10 −7 × 𝑚 = × 10 −8 𝑚 Wavenumber, 𝑣= 𝑚 −1
© Francis Fernandes, 2018

14. G= B ℘ × c 2 or G= × 10 − × 10 −9 × c 2
Entrained Ether for Earth’s Gravity
The acceleration of entrained ether produces an acceleration of 9.8 m/ s 2
Radius of Earth 6.371× 𝑚
Ether= × ×6.371× = × kg
Force of entrained ether F=ma
F= × ×9.82, F= × N
Force, F of earth mass, m oscillators, 𝐹=𝑚𝑎
𝐹=𝑚× 𝑐 2 𝑟 , 𝐹= × =𝑚× 𝑐 × ,
𝑚=5.9748× 𝑘𝑔 mass of earth
Earth’s
Ether Gravity
© Francis Fernandes, 2018

15. Energy of Earth is balanced by Energy of Ether
𝑀 𝐸𝑎𝑟𝑡ℎ × 𝑐 2 = 𝑀 𝐸𝑡ℎ𝑒𝑟 × 𝑣 2
𝑣=7.911× 𝑚 𝑠
𝑎=𝑔= 𝑣 2 𝑅
𝑔= × × 10 6
Energy of Earth is balanced by Energy of Ether
All matter is already at the speed of light
© Francis Fernandes, 2018

16. Works at the atomic and galactic scales
Einstein’s Equation:
𝐸= 𝑀 0 × 𝑐 2
𝐸= × 10 −31 × × 10 16
𝐸= × 10 −14 𝐽
Coulomb’s equation:
𝐸=𝑘× 𝑞 1 × 𝑞 2
𝐸= × 10 9 ×( × 10 −19 ) × 10 15
𝐸= × 10 −14 𝐽
Newton’s equation:
𝐸=𝐺× 𝑀 1 × 𝑀 2
𝐸= × 10 −11 ×( × 10 −9 ) × 10 15
Newton’s
Ether Gravity
Works at the atomic and galactic scales
Example of an electron as a test particle
© Francis Fernandes, 2018

17. Newton’s Gravitational Constant
Energy is expressed in the various structures that constitute the H-molecule.
  𝑚 𝐻 2 × = 𝑚 𝑇𝑒𝑚𝑝 × 𝑐 2 = 𝑚 186 × 𝑣 2 =3𝑘×300=ℎ𝑓
Notice that there are 3 masses involved- The hydrogen molecule, the temperature photon and 186-ether.
𝐺= 𝑟 𝑚 𝑇𝑒𝑚𝑝 × 𝑣 2 = × 10 − × 10 −37 × 𝑣 2
𝑞 2 =𝑚×𝑟× 10 7
Utilizing the charge squared formula above, the corresponding radii for the 3 masses are,
  𝑟 𝐻 2 = × 10 −19 𝑚
𝑟 186 = × 10 −36 𝑚
𝑟 𝑡𝑒𝑚𝑝 = × 10 −8 𝑚
Newton’s Gravitational Constant
© Francis Fernandes, 2018

18. Source of Acceleration
F=1.21× N
Ether Mass=1.86× 10 −9 Kg
Ether Radius=1.38× 10 −36 m
Speed of light=2.998× m/s
Source of Acceleration
𝑒𝑉 𝑒 =𝑉 and eVe=m c 2 Joules and Ether force=mass×acceleration
Voltage, V= 𝑐 2 𝑟 = acceleration
© Francis Fernandes, 2018

19. Angular Momentum of Ether the cloak of Boltzmann constant
𝑄 2 = 𝑒 2 squared×[ × 10 −5 ] 2 {Q=Boltzmann constant}
𝑃𝑉=𝐸𝑛𝑒𝑟𝑔𝑦, 𝐸=𝑘 𝑇
𝐸= 2𝜋× 10 −7 × ×𝑒 × 𝑒×𝑎 =𝑘×𝑇
𝐼 2 𝑅 1 × 𝑅 2 × 𝑅 1 × 𝑅 2 × 𝑅 3 = 2𝜋× 10 −7 × ×𝑒 × 𝑒×𝑎
𝐹 𝐴 ×𝑉=2𝜋× 10 −7 × ×𝐸
Atmospheric pressure is 𝐹 𝐴 or 𝐼 2 𝑅 1 × 𝑅 2
Angular Momentum of Ether the cloak of Boltzmann constant
© Francis Fernandes, 2018

20. Ether as Elementary Charge
𝑞 2 =𝑀×𝑅× 10 7
( × 10 −19 ) 2 = × 10 −9 × × 10 −36 × 10 7
© Francis Fernandes, 2018

21. Ether Current, I Current can be defined as ether or photon momentum per one coulomb of 6.24× particles of 186-ether or photons 𝐼=1.16× ×𝑣 per coulomb of ether where v is drift velocity 𝐺= 𝑟 𝑚 ×(𝑐𝑣)where r is the ether electromagnetic, em radius and m photon mass which can be obtained from the measured current and validated by electrolysis 𝐼= 𝑚 𝑒 ×𝑐 for photon mass where c is light speed or slowed velocity v for atomic mass
Electric Current Defined Electrons do not contribute to Electric current, I
© Francis Fernandes, 2018

22. Voltage is acceleration It is not EMF It is not PD It is not Energy
Idiocy of energy units – It’s too bad, but I have already apologized, and there is nothing else I can do….
- Richard P. Feynman (1961)
Consider 511 keV for an electron 𝑒𝑉 𝑒 =𝑉 × 10 −19 =3.1894× 𝑉𝑜𝑙𝑡𝑠 𝐴𝑐𝑐𝑒𝑙𝑒𝑟𝑎𝑡𝑖𝑜𝑛= 𝑐 2 𝑟 (2.998× 10 8 ) × 10 −8 =3.1894× 𝑚 𝑠 2 Voltage, V= 𝑐 2 𝑟
Voltage is acceleration It is not EMF It is not PD It is not Energy
© Francis Fernandes, 2018

23. Temperature is in absolute fact electron volts
All Experimental Data I have added one step to Wien’s Law: Empirical evidence as to why two different frequencies (wavelength) represent the same associated temperature A rotational factor of explains why the same Kelvin temperature of a body radiates two differently measured frequencies.
Temperature is in absolute fact electron volts
Electron volt eV = Temperature, T
Kelvin, K = Temperature, T 2
2.9× 10 −3 = λ 1 ×𝑇
2.9× 10 −3 = λ 1 ×𝑒𝑉
λ 1 ×(2π× 10 −7 × )= λ 2
Example: eV= and λ 3 the Compton wavelength for an electron of mass m
2.9× 10 −3 = λ 1 × 𝑇 2
Apply Planck’s Law,
0.0144= λ 3 × 𝑇 2
The photon mass m at wavelength obeys de Broglie’s equation
𝑚×𝑐× λ 3 =ℎ
© Francis Fernandes, 2018

24. Magnetic Flux Quantum - The Magnetic flux quantum is 186-Ether
𝐼= × 𝑎𝑚𝑝
Փ 0 = × × 10 −36 ×𝐴
Փ 0 = × ×𝐴
𝐴= × 10 −70
𝐴=𝜋× 𝑅 2 ×
This formula for area, A was arrived at by dividing the area in the above equation by the area of a circle,
𝐴=𝜋×( × 10 −36 ) 2 × 𝑚 2
Փ=𝐼×𝜋×𝑟× 10 −7 ×
Magnetic Flux Quantum - The Magnetic flux quantum is 186-Ether
© Francis Fernandes, 2018

25. Gravitational force = Electric current squared
Let us consider current generated by the magnetic field, B, of 0.4 T on 0.5m length of the conductor 𝐼=0.4 𝑇×0.5 𝑚=0.2 𝐴 𝐹=0.008 𝑘𝑔× 9.8 𝑁 𝑘𝑔 = 𝑁 𝐹𝑔𝑟𝑎𝑣= 𝐼 𝑁=0.392 𝐴×0.2 𝐴 A magnetic field, B, contributes 0.2 A and additional input current of A is the reason for levitation
Gravitational force = Electric current squared
© Francis Fernandes, 2018

26. Magnetic Permeability – U o is a Solid Angle
U o =4π× 10 −7 N A −2
However Force = Current squared
And thus yields a dimensionless constant, U o
Coulomb's constant, the electric force constant in electrodynamics equations in SI units, is roughly equaling 8.99×109 N·m2·C−2.
A consequence of this fact changes the units of the Coulomb constant to velocity squared
N·m2·C−2 = 𝑣2
𝑚∗ 𝑣 𝑡 ∗𝑟2 𝑚∗ 𝑟 =𝑣2
Magnetic Permeability – U o is a Solid Angle
© Francis Fernandes, 2018

27. Ether toroid The Structure of an Atom The radius of an atom and experimental wavelength The magnetic permeability of free space, μo has no units. What this means is that the magnetic permeability of free space is a tiny solid angle subtended by the photon body pulsating about a central fixed point.
186 Ether ×Velocity × Torus radius = Planck’s Constant, h
1.86×1 0 −9 × × × 10 −29 =ℎ
186-Ether or Intrinsic charge =737 𝐴𝑖𝑡ℎ𝑒𝑟𝑜𝑛×𝑓
Solid Angle=4π× 10 −7
One 186-Photon Torus or One Atom
The ether toroid is composed of × ETHER TORI.
This is the reason for the Coulomb constant.
𝑓2×1.86× 10 −9 𝑘𝑔 × 𝑘𝑔/𝑚 =Radius R of Toroid=Radius, R of an atom
λ=2π𝑅×
© Francis Fernandes, 2018

28. I/II Unification of Gravity with Electromagnetism (GEM)
Mass
Mass is an attribute of an oscillator measured differently by eV, 𝑅=𝐼/𝑚 and 𝐹=𝑚𝑎. These experimental mass measures differ by a rotational factor of 2𝜋× 10 −7 ×
This is the unification of gravity with electromagnetism which is being searched for because no one cared about the units of eV
- Francis Fernandes
It’s too bad, but I have already apologized, and there is nothing else I can do….
- Richard Feynman (1961)
I/II Unification of Gravity with Electromagnetism (GEM)
© Francis Fernandes, 2018

29. II/II Unification of Gravity with Electromagnetism (GEM)
𝑇=2π 𝑚𝑙 𝑚𝑔
𝑇=2𝜋 𝑞 2 𝐼 2
𝑇=2𝜋 𝑞 𝐼
𝑞=𝐼×𝑇
I was born in the year Feynman uttered the apologies for the units of energy. Now, I have solved the problem at the swing of a pendulum.
II/II Unification of Gravity with Electromagnetism (GEM)
© Francis Fernandes, 2018

30. Matter reverts to Ether
𝑅 𝑠𝑐ℎ = 2𝐺𝑀 𝑐 2
For an electron 𝑅 𝑠𝑐ℎ = 2×6.6742× 10 −11 × × 10 −31 ( × ) 2
𝑅 𝑠𝑐ℎ = × 10 −57 𝑚 𝑀 𝑅 = × 𝑘𝑔 𝑚
𝑅= × 10 − × ×𝑅= × 10 −57 𝑚
Thus, the Schwarzchild radius is proven to be the diameter of an electron when it vanishes into and as ether. A mini electron black hole is created. Electron mass is conserved.
INVOLUTION
Schwarzschild Radius
Black Holes
Matter reverts to Ether
© Francis Fernandes, 2018

31. Proton Structure – Ether Model
The yellow to blue to purple to green toroidal rings represent ether to matter.
The black graviton sphere nested in a torus spun by another graviton at ten to the power 48 Hz depicted in yellow is ether.

32. Atomic Frequency (I/II)
The ether model mathematically apportions a distribution of ether tori within a time-period of one second. A graviton pulsates at a frequency, f. There is a curious relationship between frequency, f, and “f-number” of aitheron particles. In other words, factor f, if multiplied by a single aitheron mass would yield the proton. The wave frequency of rippled ether, f, finds its origins in this aitheron quantum, f. The aitheron is comprised of 10 million gravitons.
Atomic Frequency
(I/II)
𝑓 ∗ =𝑓1×𝑓2×𝑓3= × Hz
𝑓1= Hz
𝑓2= × Hz 𝐸=ℎ×𝑓2 for a proton
𝑓3= × Hz
© Francis Fernandes, 2018

33. Atomic Frequency (II/II) The ratio of
Particle
f (Hz)
Graviton (Matter)
Mass m (kg)
Radial length (m)
Graviton
× 10 −58
× 10 −85
Aitheron f1
10 −58 ×𝑓1= 7.37×10 −51
× 10 −78
Proton f2
7.37× 10 −51 ×𝑓2=1.67× 10 −27
× 10 −54
Ether Oscillator f3
1.67× 10 −27 ×𝑓3=1.86× 10 −9
× 10 −36
Atomic Frequency
(II/II)
The ratio of
Toroid radius : Radial length is f*
for each particle respectively
f3 × × 10 −36 𝑚 𝑖𝑠
× 10−18𝑚
𝑡ℎ𝑒 𝑟𝑎𝑑𝑖𝑢𝑠 𝑜𝑓 𝑎 𝑝𝑟𝑜𝑡𝑜𝑛 torus
The source of Wavelength
λ = 2π×1.5347×10-18×
E = mc2 = G m M / R
The radial length × × kg m =the particle mass
Example: × 10 −54 m× × kg m = × 10 −27 kg proton mass
Particle f
(Hz)
Graviton (Ether Toroid)
Mass M (kg)
Toroid radius R (m)
Graviton f*
7.37× 10 −58 × 𝑓 ∗ =1.86× 10 −9
× 10 −36
Aitheron f1
1.86× 10 −9 ×𝑓1=0.0186
× 10 −29
Proton f2
0.0186×𝑓2= × 10 21
× 10 −6
Ether Oscillator f3
× ×𝑓3
= × 10 39
× 10 12
𝑓 ∗ =𝑓1×𝑓2×𝑓3= × Hz
𝑓1= Hz
𝑓2= × Hz 𝐸=ℎ×𝑓2 for a proton
𝑓3= × Hz
© Francis Fernandes, 2018

34. 186-Photon Torus with an oscillator is An Atom
Be= × 10 −29 m
Atomic Mass =737 Oscillator×frequency, 𝑓
737-AITHERON as SPOTS on the TORUS surface Be
The Fractal Structure of Light & Emanation of Matter There is only ONE mass in the Universe – the 737 AITHERON that emanates matter The Periodic Table will be rewritten
A pulsating ether sphere rolling in a spinning pulsating ether torus
7.37× 10 −51 𝑘𝑔 is the mass of one point mass called Aitheron;
The frequency of which determines atomic mass.
Mass of a proton, 𝑘𝑔 Mass of Aitheron × 10 −51 𝑘𝑔 =Frequency f of a proton with energy, 𝐸=ℎ𝑓
The Planck length is the upper radial pulsate limit of the torus by a factor of
© Francis Fernandes, 2018

35. 186 Ether ×Velocity × Torus radius = Planck’s Constant, h
1.86×1 0 −9 × × × 10 −29 =ℎ
186-Ether or Intrinsic charge =737 𝐴𝑖𝑡ℎ𝑒𝑟𝑜𝑛×𝑓
Ether toroid The Structure of an Atom The radius of an atom and experimental wavelength
Solid Angle=4π× 10 −7
One 186-Photon Torus or One Atom
The ether toroid is composed of × ETHER TORI.
This is the reason for the Coulomb constant.
𝑓2×1.86× 10 −9 𝑘𝑔 × 𝑘𝑔/𝑚 =Radius R of Toroid=Radius, R of an atom
λ=2π𝑅×
© Francis Fernandes, 2018

36. And is the emanation of Matter
𝑐 2 = × m s × m s
Mass×Velocity×Distance=h
𝐀] 1.86× 10 −9 ×3.4818× × 1.38× 10 −29 × 2𝜋× 10 −7 × × 2𝜋× 10 −7 × =ℎ
Boltzmann constant Q where Q2 = 1.86× 10 −9 × 1.38× 10 −29 × 2𝜋× 10 −7 × 𝜋× 10 −7 × × 2𝜋× 10 −7 ×
𝐁] 1.86× 10 −9 × ×1.38× 10 −29 =ℎ
The product of the velocities in A and B is speed of light squared
Speed of Light
Squared is NOT c×c
And is the emanation of Matter
© Francis Fernandes, 2018

37. Involution and Evolution
× m s ×( × 10 −5 ) 2 = m s
Graviton 𝑄 2 =7.37× 10 −58 × × 10 7
Aitheron 𝑒 2 =7.37× 10 −51 × × × 10 7
Matter ℎ= 𝑚  [𝐴𝑖𝑡ℎ𝑒𝑟𝑜𝑛]× × × 10 12
Ether ℎ= 𝑚 ∗ [𝐺𝑟𝑎𝑣𝑖𝑡𝑜𝑛]× × × × 10 7
Evolution:Matter emanates at a slowed speed limit of m s
Involution:Ether mass at faster than light speed limit of × m s
Coulombs Constant
Speed of Light, c2
Involution and Evolution
Two Precessions
© Francis Fernandes, 2018

38. The Birth of Elements: From FTL [Pulsation] to Slowed Light speed [Rotation] by two precessions × m s ×( × 10 −5 ) 2 = m s Black Hole Ether Toroid Twin Gravitons
© Francis Fernandes, 2018

39. THANK YOU
© Francis Fernandes, 2018