1. Chapter 15 Chemical Equilibrium
Chemistry, The Central Science, 11th edition
Theodore L. Brown; H. Eugene LeMay, Jr.;
Bruce E. Bursten and Catherine J. Murphy
Chapter 15 Chemical Equilibrium
Donna Narsavage Heald
Siena College
Loudonville, NY
 2009, Prentice-Hall

2. What is Kp in terms of Kc for the following reaction ?
What is Kp in terms of Kc for the following reaction ?
2 NO(g) O2(g) NO2(g)
Kp = KcRT
Kp = Kc/RT
Kp = KcR/T
Kp = Kc
Kp = Kc/(RT)2

3. What is Kp in terms of Kc for the following reaction ?
What is Kp in terms of Kc for the following reaction ?
2 NO(g) O2(g) NO2(g)
Kp = KcRT
Kp = Kc/RT
Kp = KcR/T
Kp = Kc
Kp = Kc/(RT)2

4. What is the correct equilibrium constant expression for the reaction:
P4(s) Cl2(g) PCl3(l)

5. What is the correct equilibrium constant expression for the reaction:
P4(s) Cl2(g) PCl3(l)

6. Which accurately reflects the changes in concentration that will occur if O2 is added to disturb the equilibrium?
2 NO(g) O2(g) NO2(g)
[NO]
[O2] 1.
Increase 2.
Decrease 3. 4. 5.

7. Which accurately reflects the changes in concentration that will occur if O2 is added to disturb the equilibrium?
2 NO(g) O2(g) NO2(g)
[NO]
[O2]
[NO2] 1.
Increase 2.
Decrease 3. 4. 5.

8. PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol
Which of the following will result in an equilibrium shift to the right?
PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol
Increase temperature/increase volume
Increase temperature/decrease volume
Decrease temperature/increase volume
Decrease temperature/decrease volume
None of the above
PCl5

9. PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol
Which of the following will result in an equilibrium shift to the right?
PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol
Increase temperature/increase volume
Increase temperature/decrease volume
Decrease temperature/increase volume
Decrease temperature/decrease volume
None of the above
PCl5

10. What is the value of Kc for the reaction?
What is the value of Kc for the reaction?
2 CO(g) + O2 (g) CO2(g) Kc = 5.0 x 1018 at 25 °C
CO2(g) CO(g) /2 O2(g) Kc = ?? at 25 °C
Kc = 1/(5.0 x 1018)1/2
Kc = 1/(2.5 x 1018)
Kc = –(5.0 x 1018)/2
Kc = –(5.0 x 1018)1/2
Kc = 2/(5.0 x 1018)1/2

11. What is the value of Kc for the reaction?
What is the value of Kc for the reaction?
2 CO(g) + O2(g) CO2(g) Kc = 5.0 x 1018 at 25 °C
CO2(g) CO(g) /2 O2(g) Kc = ?? at 25 °C
Kc = 1/(5.0 x 1018)1/2
Kc = 1/(2.5 x 1018)
Kc = –(5.0 x 1018)/2
Kc = –(5.0 x 1018)1/2
Kc = 2/(5.0 x 1018)1/2