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12.6: Vector Magnitude & Distance

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Presentation on theme: "12.6: Vector Magnitude & Distance"β€” Presentation transcript:

1 12.6: Vector Magnitude & Distance

2 Warmup If velocity of a particle is given by 𝑣 𝑑 =arcsin⁑(2π‘₯), calculate the distance the particle traveled over the interval (0,.5).

3 A vector is a quantity have both ______________ and ______________.
So if we wanted to find the magnitude of both the x(t) and y(t) vectors together. What would we do? (Campbell: for visual help draw a graph with two vectors)

4 π‘₯ 𝑑 ,𝑦 𝑑 = (π‘₯ 𝑑 ) 2 +(𝑦(𝑑) ) 2 Determining vector magnitude
π‘₯ 𝑑 ,𝑦 𝑑 = (π‘₯ 𝑑 ) 2 +(𝑦(𝑑) ) 2 Does this vector magnitude give you direction?

5 π‘₯β€²β€² 𝑑 ,𝑦′′ 𝑑 = (π‘₯β€²β€² 𝑑 ) 2 +(𝑦′′ 𝑑 ) 2 =
So what would each of these vector magnitudes give you? π‘₯ 𝑑 ,𝑦 𝑑 = (π‘₯ 𝑑 ) 2 +(𝑦 𝑑 ) 2 = π‘₯β€² 𝑑 ,𝑦′ 𝑑 = (π‘₯β€² 𝑑 ) 2 +(𝑦′ 𝑑 ) 2 = π‘₯β€²β€² 𝑑 ,𝑦′′ 𝑑 = (π‘₯β€²β€² 𝑑 ) 2 +(𝑦′′ 𝑑 ) 2 =

6 π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’= π‘Ž 𝑏 (π‘₯β€² 𝑑 ) 2 +(𝑦′ 𝑑 ) 2 𝑑π‘₯
How would you calculate distance traveled? π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’= π‘Ž 𝑏 (π‘₯β€² 𝑑 ) 2 +(𝑦′ 𝑑 ) 2 𝑑π‘₯

7 A particle moves along a curve defined by the function 𝑦=(π‘₯βˆ’3 ) βˆ™ π‘₯+2 . The x-coordinate of the particle is given by the function π‘₯(𝑑), which is satisfied by the equation 𝑑π‘₯ 𝑑𝑑 = 2 π‘‘βˆ’3 for 𝑑β‰₯0 with the initial condition π‘₯ 4 =1. Find the particular solution for π‘₯ 𝑑 . (by hand) Find 𝑑𝑦 𝑑𝑑 in terms of t. (by hand)

8 Find the speed of the particle at t=6 (calculator)
Find the total distance traveled by the particle from 4,6 . (calculator) Find the acceleration vector at t=6. (calculator)


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