1. Forces
What did you pull ?

2. Remember Pythagoras ? He had a lot to do with these things c
a2 + b2 = c2 b a

3. Remember SOHCAHTOA ? c b  a So in terms of cos a= in terms of sin b=
Hint :write the word theta
in terms of sin b=

4. Lets find the missing lengths on it.
Here’s a triangle
Lets find the missing lengths on it. 25
 = 25º
Opposite =
Type in the equations you got
Use the word theta
Adjacent =
And your answers to 3 d.p.
Opposite =
Adjacent =

5. Find the missing lengths
You have 5 mins to do as many as you can
Click here for answers

6. Forces acting at a point can be treated as right angled triangles
When these 2 forces act on the same point
marks the spot
these 2 forces can be replaced by one pink force
No Chris the colour isn’t important !
With right angled triangles you can use Pythagoras to find missing sides and angles. The same is true for forces.
?2 = ? = 8.06 ? 4
So the resultant force is 8.06N 7

7. Find the resultant of these forces answers in Newtons to 1 d.p.
Check here 6N
32N
15N
58N 1N
21N

8. What angle are these forces acting at ? The first one is done for you.θ 9N 8N
11N
tanθ= 7 ÷ 8
θ = tan-1(7÷8)
θ = 41.2º
Your Turn Now Go!
Answers to 1 d.p. No degree symbol 6N
32N
15N 1N
58N
21N

9. Of course you can ! This time we use trigonometry.
What if you get the resultant and an angle ! Can you find the horizontal and vertical components of the force ?
Of course you can ! This time we use trigonometry.
Look back to your answers for this question.
Equation =
Answer =
So the vertical component of the force is: equation =
answer =
12N V
And the horizontal force is ? ? ? ?
38º
equation = H
answer =

10. Easy isn’t it. Now lets add some direction to your lives!
Find the horizontal and vertical components of these resultants. 4N
15N 7N
85º
48º
21º
32N
18N 9N
22º
35º 9º
Click here for answers

11. You’ve finished Or have you ?
Consolidation exercises can be found in 4d aqa M1exercise