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Structures & MaterialsHigher Technological Studies Technological Studies Structures & Materials Required Knowledge.

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Presentation on theme: "Structures & MaterialsHigher Technological Studies Technological Studies Structures & Materials Required Knowledge."— Presentation transcript:

1 Structures & MaterialsHigher Technological Studies Technological Studies Structures & Materials Required Knowledge

2 Structures & MaterialsHigher Technological Studies Learning Outcome 1 Reactions at supports. Moments about a beam; and Resolution of Forces;

3 Structures & MaterialsHigher Technological Studies The HAND! Vertical Forces Moments Pythagoras Horizontal Forces Trigonometry Remember & Apply the following in order

4 Structures & MaterialsHigher Technological Studies Three conditions that will ALWAYS be true: ΣM = 0 ΣFv = 0 ΣFh = 0 Equilibrium The sum of all Moments = 0 The sum of all Vertical Forces = 0 The sum of all Horizontal Forces = 0

5 Structures & MaterialsHigher Technological Studies Three conditions that will ALWAYS be true: ΣM = 0 ΣFv = 0 ΣFh = 0 Equilibrium The sum of all Moments = 0 The sum of all Vertical Forces = 0 The sum of all Horizontal Forces = 0

6 Structures & MaterialsHigher Technological Studies Moments A MOMENT is a force - that causes a turning motion. Moment = Force x Distance

7 Structures & MaterialsHigher Technological Studies Moments A MOMENT is a force - that causes a turning motion. Moment = Force x Distance

8 Structures & MaterialsHigher Technological Studies Forces A Forces has: 20NMAGNATUDE DIRECTION 20N Positive Forces are: Negative Forces are:

9 Structures & MaterialsHigher Technological Studies Forces Put together: Positive Forces are: Negative Forces are:

10 Structures & MaterialsHigher Technological Studies Vertical Forces ΣFv = 0 The sum of all Vertical Forces = 0 Positive Forces Negative Forces 20N 40N 20N + 40N - 20N

11 Structures & MaterialsHigher Technological Studies Horizontal Forces ΣFh = 0 The sum of all Horizontal Forces = 0 20N 40N Positive Forces Negative Forces 20N 40N + 20N - 40N

12 Structures & MaterialsHigher Technological Studies Pythagoras Pythagoras’ Theorem: For a right angle triangle; The square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. c 2 = a 2 +b 2 c =  (a 2 +b 2 ) c a b

13 Structures & MaterialsHigher Technological Studies Pythagoras Pythagoras’ Theorem: c 2 = a 2 +b 2 c a b C A B

14 Structures & MaterialsHigher Technological Studies Trigonometry 30 o ACB b c a SOH CAH TOAFor right angle triangles only sin A = Opposite (a) Hypotenuse (c) cos A = Adjacent (b) Hypotenuse (c) tan A = Opposite (a) Adjacent (b)

15 Structures & MaterialsHigher Technological Studies Supports There are 3 types that will be used in this module Knife-edge: This is a fixed support that only provides a vertical reaction Roller: This support is not fixed and can only provides a vertical reaction Hinge: This support is fixed but will allow movement and provides a reaction in any direction

16 Structures & MaterialsHigher Technological Studies Answer & units Problem Solving Technique The RECIPE (for any calculation): State formula This will focus your thoughts and often get you marks Transpose Re-arrange formula to suite need SubstituteInsert the numbers Calculate Do the Maths Lose marks if no units

17 Structures & MaterialsHigher Technological Studies Problem Solving Technique Example: To find the horizontal force (F H ) State formula = cos A x Hyp.FHFH Transpose cos A = Adjacent (b) Hypotenuse (c) FHFH Hyp. = Substitute = cos 30 o x 90NFHFH Calculate Answer & units = 77.94NFHFH 30 o 90N FHFH


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