1. Give Chapter 12 HW on Thursday test day
Then do 8 – Friday, 9 – Monday, 10 – Tuesday, 11 – Wednesday, 12 – Thursday the following week, then free review days Friday and Monday

2. R—05/31/12—HW #73: Pg 778-779: 1—11 all; Pg 825-826: 1—35 odd, 34
2) E 4) C 6) D 8) A 10) C
34) pi, pi

3. Chapter 12 Review

4. Is it a polyhedron. If so, count the faces, edges, and vertices
Is it a polyhedron? If so, count the faces, edges, and vertices. Also say whether or not it is convex.
Yes
7 faces, 15 edges
10 vertices
Convex
Yes
6 faces, 12 edges
8 vertices
Convex
Euler’s Theorem: F + V = E + 2
(Like FAVE two, or cube method)

5. Terms
P  Perimeter of one base
B  Area of base
b  base (side)
h  Height (relating to altitude)
l  Slant Height
TA  Total Area (Also SA for surface Area)
LA  Lateral Area
V  Volume

6. Lateral Area of a right prism is the sum of area of all the LATERAL faces.
= bh + bh + bh + bh
= (b + b + b + b)h LA
= Ph
Total Area is the sum of ALL the faces. TA
= 2B + Ph

7. Cylinder

8. Find the LA, SA of this rectangular prism.
Height = 8 cm
Radius = 4 cm 5 3 8
LA =
SA =
(22)5
= 110 units2

9. b l + b l + b l + b l + b l (b + b + b + b + b) l = Pl
Lateral Area of a regular pyramid is the area of all the LATERAL faces.
Total area is area of bases. TA = B Pl b l + b l + b l + b l + b l (b + b + b + b + b) l
= Pl

10. Cone

11. Find Lateral Area, Total Area
13 cm
10 cm
Slant Height = 15 in.
Radius = 9 in

12. Altitude is segment perpendicular to the parallel planes, also referred to as “Height”.
Volume of a right prism equals the area of the base times the height of the prism. V
= Bh
Prism

13. Find the V of this triangular prism.8 4 3 5

14. Find Volume
Height = 8 cm
Radius = 4 cm
Cylinder

15. Cone
Slant Height = 15 in.
Radius = 9 in
10 cm
13 cm

16. Find SA and V with radius 6 m.

17. Circumference of great circle
Radius of Sphere
Circumference of great circle
Surface Area of Sphere
Volume of sphere
3 m
4π in2
6π cm
9π ft3 2

18. Two shapes are similar if all the the sides have the same scale factor.
If the scale factor of two similar solid is a:b, then
The ratio of the corresponding perimeters is a:b
The ratio of the base areas, lateral areas, and total areas is a2:b2
The ratio of the volumes is a3:b3
There be a problem where they give you area or volume, you must convert correctly to other ratio, set up proportion, then solve. We will talk about these.

19. R—05/31/12—HW #73: Pg 778-779: 1—11 all; Pg 825-826: 1—35 odd, 34