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POWER ENERGY WORK WHEN ENERGY IS TRANSFORMED FROM ONE FORM TO ANOTHER WORK IS DONE WHEN ? WHEN ? WHEN ENERGY IS TRANSFORMED FROM ONE FORM.

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Presentation on theme: "POWER ENERGY WORK WHEN ENERGY IS TRANSFORMED FROM ONE FORM TO ANOTHER WORK IS DONE WHEN ? WHEN ? WHEN ENERGY IS TRANSFORMED FROM ONE FORM."— Presentation transcript:

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7 POWER ENERGY WORK

8 WHEN ENERGY IS TRANSFORMED FROM ONE FORM TO ANOTHER
WORK IS DONE WHEN ? WHEN ? WHEN ENERGY IS TRANSFORMED FROM ONE FORM TO ANOTHER

9 UNITS OF WORK & ENERGY ? mJ kJ JOULES GJ MJ Symbol J

10 FORMS OF ENERGY ENERGY IS A SCALAR ELECTRICITY Gravitational &
MAGNETISM Gravitational Potential HEAT Chemical Potential Sound LIGHT Nuclear kinetic ENERGY IS A SCALAR

11 THE PRINCIPLE OF CONSERVATION OF ENERGY ENERGY CAN BE CHANGED FROM ONE FORM TO ANOTHER, BUT CAN NEVER BE DESTROYED

12 heat heat potential chemical electromagnetism kinetic sound light

13 What energy changes occur here?

14 WORK DONE = FORCE X DISPLACEMENT
Work (W) is done when a force (F) moves an object between two positions. WORK DONE = FORCE X DISPLACEMENT W = F d Force F Force F Displacement d

15 W = F·d·Cosθ Force F θ Displacement d

16 Eg = mgh Work done = Potential Energy change h mg
Formula for (gravitational) Potential Energy Eg h Work done = Potential Energy change Eg = mgh mg

17 EK = ½ m v2 Formula for Kinetic Energy - EK d F Final velocity vf
Mass m Initial velocity vi=0 F EK = work done in accelerating to velocity, vf. i.e EK = Fd vf2 = vi2 + 2 ad = 2 ad [as vi = 0] EK = m a d as F = ma EK = ½ m v2

18 JOULES / SECOND = WATTS ( W )
POWER is the RATE OF DOING WORK = RATE OF CONVERTING ENERGY UNITS JOULES / SECOND = WATTS ( W )

19 The efficiency [ e ] of a machine is the power output (or energy output) divided by the power input (or energy input), usually expressed as a percentage. If a kW electric motor lifts a load 2.00 kg though a distance of 3.00 m in 2.00 seconds, its efficiency is given by:

20 P = F v For a vehicle moving at constant velocity, v.
Where F is the driving force of the engine. F The power to maintain this velocity is given by : P = F v

21 s FINDING ONE’S POWER x (Sx) m Height of step = x m Height of steps =
My weight in Newtons = y N Time to ascend = z s MY POWER = (ySx/z) W 746 W = 1 hp


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