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Inference Rules: Tautologies

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1 Inference Rules: Tautologies
(p  (p  q))  q Modus Ponens (q  (p  q))  p Modus Tollens p  (p  q) Addition (p  q)  p Simplification ((p)  (q))  p  q Conjunction ((p  q)  q)  p Disjunctive Syllogism ((p  q)  (q  r))  (p  r) Hypothetical Syllogism (aka, the transitive rule) ((p  q )  ( p  r))  (q  r) Resolution ((p  q )  (p  r)  (q  r))  r Cases

2 Fallacies (q  (p  q))  p. Fallacy of Affirming the Conclusion
(p  (p  q))  q. Fallacy of Denying the Hypothesis

3 Inference Rules: Quantified Statements
Universal Instantiation (for an individual object c from UoD) x P(x)  P(c) Universal Generalization (for any arbitrary element c from UoD) P(c)___  x P(x) x P(x)  P(c) Existential Instantiation (for some specific object c from UoD) Existential Generalization (for some object c from UoD) P(c)__  x P(x)

4 Proof Methods Trivial Proof of p  q given q (see truth table).
Vacuous Proof of p  q given p (see truth table). Direct Proof of p  q given p, show q. Indirect Proof of p  q (proof by contraposition, so show q  p starting with q). Proof of p  q by Contradiction: recall that p  q Ξ p  q. Assume the negation, p  q, is true and show a contradiction. Proof of p1  p2  p3  … pn  q by Cases: show that pi  q is true for all i, where 1 ≤ i ≤ n. Proof of x P(x) by example: just find an instance. Proof that x P(x) is false by counterexample: just find an instance c where P(c) is false.


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