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William Stallings Computer Organization and Architecture 8th Edition

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Presentation on theme: "William Stallings Computer Organization and Architecture 8th Edition"— Presentation transcript:

1 William Stallings Computer Organization and Architecture 8th Edition
Chapter 15 Control Unit Operation

2 A computer executes a program Fetch/execute cycle
Micro-Operations A computer executes a program Fetch/execute cycle Each cycle has a number of steps see pipelining Called micro-operations Each step does very little Atomic operation of CPU

3 Constituent Elements of Program Execution

4 Memory Address Register (MAR)
Fetch - 4 Registers Memory Address Register (MAR) Connected to address bus Specifies address for read or write op Memory Buffer Register (MBR) Connected to data bus Holds data to write or last data read Program Counter (PC) Holds address of next instruction to be fetched Instruction Register (IR) Holds last instruction fetched

5 Fetch Sequence Address of next instruction is in PC Address (MAR) is placed on address bus Control unit issues READ command Result (data from memory) appears on data bus Data from data bus copied into MBR PC incremented by 1 (in parallel with data fetch from memory) Data (instruction) moved from MBR to IR MBR is now free for further data fetches

6 Fetch Sequence (symbolic)
t1: MAR <- (PC) t2: MBR <- (memory) PC <- (PC) +1 t3: IR <- (MBR) (tx = time unit/clock cycle) or t3: PC <- (PC) +1 IR <- (MBR)

7 Rules for Clock Cycle Grouping
Proper sequence must be followed MAR <- (PC) must precede MBR <- (memory) Conflicts must be avoided Must not read & write same register at same time MBR <- (memory) & IR <- (MBR) must not be in same cycle Also: PC <- (PC) +1 involves addition Use ALU May need additional micro-operations

8 Indirect Cycle MAR <- (IRaddress) - address field of IR MBR <- (memory) IRaddress <- (MBRaddress) MBR contains an address IR is now in same state as if direct addressing had been used (What does this say about IR size?)

9 t2: MAR <- save-address PC <- routine-address
Interrupt Cycle t1: MBR <-(PC) t2: MAR <- save-address PC <- routine-address t3: memory <- (MBR) This is a minimum May be additional micro-ops to get addresses N.B. saving context is done by interrupt handler routine, not micro-ops

10 Execute Cycle (ADD) Different for each instruction e.g. ADD R1,X - add the contents of location X to Register 1 , result in R1 t1: MAR <- (IRaddress) t2: MBR <- (memory) t3: R1 <- R1 + (MBR) Note no overlap of micro-operations

11 ISZ X - increment and skip if zero
Execute Cycle (ISZ) ISZ X - increment and skip if zero t1: MAR <- (IRaddress) t2: MBR <- (memory) t3: MBR <- (MBR) + 1 t4: memory <- (MBR) if (MBR) == 0 then PC <- (PC) + 1 Notes: if is a single micro-operation Micro-operations done during t4

12 BSA X - Branch and save address
Execute Cycle (BSA) BSA X - Branch and save address Address of instruction following BSA is saved in X Execution continues from X+1 t1: MAR <- (IRaddress) MBR <- (PC) t2: PC <- (IRaddress) memory <- (MBR) t3: PC <- (PC) + 1

13 Each phase decomposed into sequence of elementary micro-operations
Instruction Cycle Each phase decomposed into sequence of elementary micro-operations E.g. fetch, indirect, and interrupt cycles Execute cycle One sequence of micro-operations for each opcode Need to tie sequences together Assume new 2-bit register Instruction cycle code (ICC) designates which part of cycle processor is in 00: Fetch 01: Indirect 10: Execute 11: Interrupt

14 Flowchart for Instruction Cycle

15 Functional Requirements
Define basic elements of processor Describe micro-operations processor performs Determine functions control unit must perform

16 Basic Elements of Processor
ALU Registers Internal data pahs External data paths Control Unit

17 Types of Micro-operation
Transfer data between registers Transfer data from register to external Transfer data from external to register Perform arithmetic or logical ops

18 Functions of Control Unit
Sequencing Causing the CPU to step through a series of micro-operations Execution Causing the performance of each micro-op This is done using Control Signals

19 Control Signals Clock Instruction register Flags From control bus
One micro-instruction (or set of parallel micro-instructions) per clock cycle Instruction register Op-code for current instruction Determines which micro-instructions are performed Flags State of CPU Results of previous operations From control bus Interrupts Acknowledgements

20 Model of Control Unit

21 Control Signals - output
Within CPU Cause data movement Activate specific functions Via control bus To memory To I/O modules

22 Example Control Signal Sequence - Fetch
MAR <- (PC) Control unit activates signal to open gates between PC and MAR MBR <- (memory) Open gates between MAR and address bus Memory read control signal Open gates between data bus and MBR

23 Data Paths and Control Signals

24 Internal Organization
Usually a single internal bus Gates control movement of data onto and off the bus Control signals control data transfer to and from external systems bus Temporary registers needed for proper operation of ALU

25 CPU with Internal Bus

26 Hardwired Implementation (1)
Control unit inputs Flags and control bus Each bit means something Instruction register Op-code causes different control signals for each different instruction Unique logic for each op-code Decoder takes encoded input and produces single output n binary inputs and 2n outputs

27 Hardwired Implementation (2)
Clock Repetitive sequence of pulses Useful for measuring duration of micro-ops Must be long enough to allow signal propagation Different control signals at different times within instruction cycle Need a counter with different control signals for t1, t2 etc.

28 Control Unit with Decoded Inputs

29 Hardwired Control Unit Logic
For each control signal, to derive a Boolean expression of that signal as a function of the inputs Let us consider a single control signal, C5, signal causes data to be read from the external data bus into the MBR Let us define two new control signals, P and Q, that have the following interpretation: PQ = 00 Fetch Cycle PQ = 11 Interrupt Cycle PQ = 10 Execute Cycle PQ = 01 Indirect Cycle

30 Hardwired Control Unit Logic
Then C5 can be defined as: C5 = P # Q # T2 + P # Q # T2 That is, the control signal C5 will be asserted during the second time unit of both the fetch and indirect cycles. C5 is also needed during the execute cycle. For our simple example, let us assume that there are only three instructions that read from memory: LDA,ADD, and AND. Now we can define C5 as C5 = P # Q # T2 + P # Q # T2 + P # Q # (LDA + ADD + AND) # T2

31 Hardwired Control Unit Logic
This same process could be repeated for every control signal generated by the processor. The result would be a set of Boolean equations that define the behavior of the control unit and hence of the processor.

32 Hardwired Control Unit Logic
To tie everything together, the control unit must control the state of the instruction cycle. As was mentioned, at the end of each subcycle (fetch, indirect, execute, interrupt), the control unit issues a signal that causes the timing generator to reinitialize and issue T1. The control unit must also set the appropriate values of P and Q to define the next subcycle to be performed

33 Problems With Hard Wired Designs
Complex sequencing & micro-operation logic Difficult to design and test Inflexible design Difficult to add new instructions

34 Chapter 16 Micro-programmed Control

35 Control Unit Organization

36 Micro-programmed Control
Use sequences of instructions (see earlier notes) to control complex operations Called micro-programming or firmware

37 Implementation (1) All the control unit does is generate a set of control signals Each control signal is on or off Represent each control signal by a bit Have a control word for each micro-operation Have a sequence of control words for each machine code instruction Add an address to specify the next micro-instruction, depending on conditions

38 Today’s large microprocessor
Implementation (2) Today’s large microprocessor Many instructions and associated register-level hardware Many control points to be manipulated This results in control memory that Contains a large number of words co-responding to the number of instructions to be executed Has a wide word width Due to the large number of control points to be manipulated

39 Micro-program Word Length
Based on 3 factors Maximum number of simultaneous micro-operations supported The way control information is represented or encoded The way in which the next micro-instruction address is specified

40 Micro-instruction Types
Each micro-instruction specifies single (or few) micro-operations to be performed (vertical micro-programming) Each micro-instruction specifies many different micro-operations to be performed in parallel (horizontal micro-programming)

41 Horizontal Micro-programming
Wide memory word High degree of parallel operations possible Little encoding of control information

42 Typical Microinstruction Formats

43 Organization of Control Memory

44 Control Unit

45 Control Unit Function Sequence login unit issues read command
Word specified in control address register is read into control buffer register Control buffer register contents generates control signals and next address information Sequence login loads new address into control buffer register based on next address information from control buffer register and ALU flags

46 Depending on ALU flags and control buffer register
Next Address Decision Depending on ALU flags and control buffer register Get next instruction Add 1 to control address register Jump to new routine based on jump microinstruction Load address field of control buffer register into control address register Jump to machine instruction routine Load control address register based on opcode in IR

47 Functioning of Microprogrammed Control Unit


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