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? AP Chemistry Electronic Structure of Atoms

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1 ? AP Chemistry Electronic Structure of Atoms
electronic structure: the arrangement of electrons in an atom quantum mechanics: the physics that correctly describes atoms ?

2 electromagnetic radiation (i.e., light)
-- waves of oscillating electric (E) and magnetic (B) fields -- source is… vibrating electric charges E B

3 Characteristics of a Wave
crest amplitude A trough wavelength l frequency: the number of cycles per unit time (usually sec) -- unit is Hz, or s–1

4 electromagnetic spectrum: contains all of the “types” of
light that vary according to frequency and wavelength IR UV visible X-rays radio waves microwaves gamma rays cosmic rays ROYGBV 750 nm 400 nm large l small l -- visible spectrum ranges from only ~400 to 750 nm (a very narrow band of spectrum) low f high f low energy high energy

5 first to get an accurate value for speed of light
Albert Michelson (1879) -- first to get an accurate value for speed of light Albert Michelson (1852–1931) The speed of light in a vacuum (and in air) is constant: c = 3.00 x 108 m/s -- Equation: c = n l = f l

6 that energy can be absorbed or released only in certain
In 1900, Max Planck assumed that energy can be absorbed or released only in certain discrete amounts, which he called quanta. Later, Albert Einstein dubbed a light “particle” that carried a quantum of energy a photon. Max Planck (1858–1947) -- Equation: E = h n = h f E = energy, in J h = Planck’s constant Albert Einstein = 6.63 x 10–34 J-s (i.e., J/Hz) (1879–1955)

7 A radio station transmits
at 95.5 MHz (FM 95.5). Calculate the wavelength of this light and the energy of one of its photons. 3.00 x 108 m/s = 95.5 x 106 Hz c = f l = m E = h f = x 10–34 J/Hz (95.5 x 106 Hz) = x 10–26 J

8 In 1905, Einstein explained the photoelectric effect
using Planck’s quantum idea. -- only light at or above a threshold freq. will cause e– to be ejected from a metal surface ROYGBV e– light source metal surface e– Frequency (i.e., energy) of light determines IF e– are ejected or not, and with what KE. e– Intensity/brightness of light determines HOW MANY e– are ejected.

9 ? Einstein also expanded Planck’s idea, saying that
energy exists only in quanta. Light has both wavelike and particle-like qualities, and... so does matter. ?

10 “continuous” spectrum.
Line Spectra Ordinary white light is dispersed by a prism into a... “continuous” spectrum. From the gas in a nearly-evacuated gas-discharge tube, we instead get a... line spectrum. H2 absorption spectrum H2 emission spectrum (if the H2 is absorbing light from an external source) (if the H2 has been energized and is emitting light)

11 Niels Bohr took Planck’s quantum idea and applied
it to the e– in atoms. -- e– could have only certain amounts of energy -- e– could be only at certain distances from nucleus Niels Bohr (1885–1962) e– found here e– never found here planetary (Bohr) model N

12 -- Bohr assumed that the e– in his circular orbits
had particular energies, given by: RH = Rydberg constant = 2.18 x 10–18 J n = 1, 2, 3, ... (the principal quantum number) The more/less (–) an electron’s energy is... i.e., the energy level the more/less stable the atom is. “barely” (if at all) stable When n is very large, En goes to zero, which is the most energy an e– can have because… “barely” (–) E energy “well” e– e– “a bit” stable zero is larger than anything (–). “a bit” (–) E (e– has escaped completely from atom.) e– very (–) E very stable

13 -- Bohr stated that e– could move from one level to
another, absorbing light of a particular freq. to “jump up” and releasing light of a particular freq. to “fall down.” He: 1s1 2s1 He: 1s2 EMITTED LIGHT ENERGY (HEAT, LIGHT, ELEC., ETC.) -- Bohr’s model (i.e., its specific equation) worked only for atoms with… a single e–.

14 Find the wavelength, frequency,
and energy of a photon of the emission line produced when an e– in a hydrogen atom makes the transition from n = 5 to n = 2. For n = 5… = –8.72 x 10–20 J For n = 2… E2 = –5.45 x 10–19 J DE = 4.58 x 10–19 J = energy of photon E = h f = x 1014 Hz c = f l = x 10–7 m

15 The Wave Behavior of Matter
Since light (traditionally thought of as a wave) was found to behave as both a wave and a particle, Louis de Broglie suggested that matter (traditionally thought of as particles) might also behave like both a wave and a particle. He called these… matter waves. Louis de Broglie (1892–1987) -- The wavelength of a moving sample of matter is given by: m = mass (kg) v = speed (m/s)

16 A proton moving at 1200 m/s would be associated with a matter wave
of how many nanometers? In the absence of further info… mp ~ 1 amu = 1.66 x 10–27 kg (actual p+ mass is ~1.673 x 10–27 kg) = 3.3 x 10–10 m = nm

17 A wave is smeared out through space, i.e., its location
is not precisely defined. Since matter exhibits wave characteristics, there are limits to how precisely we can define a particle’s (e.g., an e–’s) location. -- the limitation also applies to a particle’s... momentum -- Heisenberg’s uncertainty principle: It is impossible to know simultaneously BOTH the exact momentum of a particle AND its exact location in space. D = “uncertainty in” h = Planck’s const. Werner Heisenberg (It is inappropriate to imagine an e– as a solid particle moving in a well-defined orbit.) (1901–1976)

18 Schrodinger’s wave equation (1926) accounts for
both wave and particle behaviors of e–. (for a non-relativistic particle of mass m w/no electric charge and zero spin, where h-bar is the reduced Planck’s constant (=h/2p), V is the potential energy, and Y is the wave function) -- Solutions to the wave equation yield wave functions, symbolized by Y, which have no physical meaning, but Y2 at any point in space gives the probability that you’ll find an e– at that point. Y2 is called the probability density, which gives the electron density. Erwin Schrodinger (1887–1961)

19 -- Orbitals describe a specific distribution of electron
density in space. Each orbital has a characteristic shape and energy.

20 (“Not.”) (Well, theory says that there ARE g orbitals, but they don’t look like this.) We also think g orbitals exist, and they look like this… The lanthanides and actinides contain f orbitals.

21 Quantum numbers are used to describe where an e–
is in an atom. 1. principal quantum number, n (n = integers 1, 2, 3,...) -- correspond to the energy level of the electrons -- All orbitals having the same n are called an electron shell (e.g., 2s and 2p). 2. angular momentum quantum number, l (l = integers from 0 up to (n – 1)) -- This number defines the type of subshell: s = 0, p = 1, d = 2, f = 3 -- For a given shell, the energies of orbitals go: s < p < d < f

22 shapes and orientations
Quantum numbers (cont.) 3. magnetic quantum number, ml (ml = integers from –l to l) -- describes the orientation of an orbital in space -- You should know the shapes and orientations of the s, p, and d orbitals: s, px, py, pz, dyz, dxz, dxy, dx2– y2, dz2 shapes and orientations of d orbitals

23 4. electron spin quantum number, ms
-- only two values: +½ or –½ (“spin-up” and “spin-down”) -- Pauli exclusion principle: No two electrons in an atom may have the same set of four quantum numbers (i.e., an orbital may hold only two electrons, and they must have opposite spins). Wolfgang Pauli (1900–1958)

24 (a) Predict the number of subshells in the third shell.
n = 3, so… l could be 0, 1, or 2 3 subshells (b) Give the label for each of these subshells. For: l = 0… 3s l = 1… 3p l = 2… 3d (c) How many orbitals are in each of these subshells? For: l = 0… ml = 0 3s: 1 orbital l = 1… ml = –1, 0, +1 3p: 3 orbitals l = 2… ml = –2, –1, 0, +1, +2 3d: 5 orbitals

25 What are the values of n and l
for the following sublevels? 2s 3d 4p 5s 4f n = 2 n = 3 n = 4 n = 5 n = 4 l = 0 l = 2 l = 1 l = 0 l = 3 Write the possible sets of the four quantum numbers for a 4p electron. 4p orbitals ml : – 4, 1, –1, 4, 1, 0, 4, 1, +1, 4, 1, –1, –½ 4, 1, 0, –½ 4, 1, +1, –½

26 ? Write the four quantum numbers of each of the
six 3d electrons of an iron atom. 3d orbitals ml : –2 – 3, 2, –2, ? 3, 2, –1, 3, 2, 0, 3, 2, +1, 3, 2, +2, 3, 2, ?, –½

27 Brief Review of the Periodic Table
metals: left side of Table; form cations properties: ductile (can pull into wire) malleable (can hammer into shape) lustrous (shiny) good conductors (heat and electricity)

28 Brief Review of the Periodic Table (cont.)
nonmetals: right side of Table; form anions properties: good insulators gases or brittle solids neon sulfur iodine bromine Ne S8 I2 Br2

29 Brief Review of the Periodic Table (cont.)
metalloids (semimetals): “stair” between metals and nonmetals (B, Si, Ge, As, Sb, Te, Po, At) metals nonmetals computer chips Si and Ge properties: in-between those of metals and nonmetals; “semiconductors” computer chips Ge and Si 

30 alkaline earth metals:
alkali metals: group 1 (except H); 1+ charge; very reactive alkaline earth metals: group 2; 2+ charge; less reactive than alkalis transition elements: groups 3–12; variable charges chalcogens: group 16; 2– charge; reactive halogens: group 17; 1– charge; very reactive noble gases: group 18; no charge; unreactive lanthanides: elements 58–71 contain f orbitals actinides: elements 90–103 main block (representative) elements: groups 1, 2, 13–18

31 What family of elements has an ns2 valence electron
configuration? alkaline earth metals

32 Anomalies in the Electron Configurations
Your best guide to writing e– configs is “The Table,” but there are a few exceptions. e.g., Cr: [ Ar ] 4s1 3d5 Cu: [ Ar ] 4s1 3d10 These exceptions are due to the closeness in energy of the upper-level orbitals. “RuRh…!!” Other exceptions are… Mo, Ru, Rh, and Ag. All of these exceptions have a single valence-level s electron.


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