1. Emt 359/3 analog electronic ii Chapter 2: Op-amp Applications & Frequency Response

2. Content Op-amp Application Introduction Inverting Amplifier
Non-inverting Amplifier
Voltage Follower / Buffer Amplifier
Summing Amplifier
Differencing Amplifier
Integrator
Differentiator
Comparator
Summary
Frequency Response

3. Op-amp Application Introduction
Op-amps are used in many different applications. We will discuss the operation of the fundamental op- amp applications. Keep in mind that the basic operation and characteristics of the op-amps do not change — the only thing that changes is how we use them

4. Inverting Amplifier Circuit consists of an op-amp and three resistors.
The positive (+) input to the op-amp is grounded through R2.
The negative (-) input is connected to the input signal (via R1) and also to the feedback signal from the output (via RF).

5. Inverting Amplifier
Assume that amplifier operates in its linearly amplifying region.
For an ideal op-amp, the difference between the input voltages V+ and V to the op-amp is very small, essentially zero;

6. Inverting Amplifier
Hence;

7. Inverting Amplifier
The op-amp input resistance is large, so the current into the +ve and –ve op-amp inputs terminal will be small, essentially zero

8. Inverting Amplifier
Currents and voltages in the inverting op-amp

9. Inverting Amplifier - Example
Design an inverting amplifier with a specified voltage gain.
Specification: Design the circuit such that the voltage gain is Av = -5. Assume the op-amp is driven by an ideal sinusoidal source, vs = 0.1sin wt (V), that can supply a maximum current of 5 µA. Assume that frequency w is low so that any frequency effects can be neglected.

10. Inverting Amplifier – T-Network

11. Non-Inverting Amplifier
Circuit consists of an op-amp and three resistors.
The negative (-) input to the op-amp is grounded through R1 and also to the feedback signal from the output (via RF).
The positive (+) input is connected to the input signal.

12. Non-Inverting Amplifier
Input current to op-amp is very small. No signal voltage is created across R2 and hence
so it follows that;

13. Non-Inverting Amplifier
so RF and R1 carry the same current. Hence vout is related to V through a voltage-divider relationship

14. Non-Inverting Amplifier
The output has the same polarity as the input,
a positive input signal produces a positive output signal.
The ratio of R1 and RF determines the gain.
When a voltage is applied to the amplifier, the output voltage increases rapidly and will continue to rise until the voltage across R1 reaches the input voltage. Thus negligible input current will flow into the amplifier, and the gain depends only on R1 and RF

15. Non-Inverting Amplifier
The input resistance to the non-inverting amplifier is very high because the input current to the amplifier is also the input current to the op-amp, I+, which must be extremely small.

16. Non-Inverting Amplifier

17. Voltage Follower / Buffer Amplifier
This “buffer” is used to control
impedance levels in the circuit
– it isolates part of the overall
(measurement) circuit from the
output (driver).
The input impedance to the buffer is very high and its output impedance is low.
The output voltage from a source with high output impedance can, via the buffer, supply signal to one or more loads that have a low impedance.

18. Voltage Follower / Buffer Amplifier
High input impedance.
Low output impedance.
Voltage gain = 1

19. Summing Amplifier
The inverting amplifier can accept two or more inputs and produce a weighted sum.
Using the same reasoning as with the inverting amplifier, that V ≈ 0.
The sum of the currents through R1, R2,…,Rn is:

20. Summing Amplifier The op-amp adjusts itself to draw iin
through Rf (iin = if).
The output will thus be the sum of V1,V2,…,Vn, weighted by the gain factors, Rf/R1 , Rf/R2 ….., Rf/Rn respectively.

21. Summing Amplifier Special Cases for this Circuit:
1. If R1 = R2 =……= R then:

22. Summing Amplifier
2. If R1 = R2 = … = R and VIN1, VIN2, … are either 0V (digital “0”) or 5V (digital “1”) then the output voltage is now proportional to the number of (digital) 1’s input.

23. Summing Amplifier - Application
Digital to Analog Converter
- binary-weighted resistor DAC

24. Summing Amplifier - Application
Digital to Analog Converter
- R/2R Ladder DAC

25. Differencing Amplifier
This circuit produces an output which is proportional to the difference between the two inputs

26. Differencing Amplifier
The circuit is linear so we can look at the output due to each input individually and then add them (superposition theorem)

27. Differencing Amplifier
Set v1 to zero. The output due to v2 is the same as the inverting amplifier, so

28. Differencing Amplifier
The signal to the non-inverting output, is reduced by the voltage divider:

29. Differencing Amplifier
The output due to this is then that for a non-inverting amplifier:

30. Differencing Amplifier

31. Differencing Amplifier
Thus the output is:
Thus the amplifier subtracts the inputs and amplifies their difference.

32. Differencing Amplifier - Example
Determine voltage output, vo when vi1=+1 V, vi2=-1V, R1=R3=10 kΩ, R2=20 kΩ and R4=21 kΩ
When vi1=vi2=+1V
Solution: vo=
Solution: vo=0.0323

33. Integrator
The basic integrator is easily identified by the capacitor in the feedback loop.
A constant input voltage yields a ramp output. The input resistor and the capacitor form an RC circuit.

34. Integrator
The slope of the ramp is determined by the RC time constant.
The integrator can be used to change a square wave input into a triangular wave output.

35. Integrator
The capacitive impedance:

36. Integrator
The input current:

37. Integrator

38. Integrator
Thus the output in time domain:

39. Differentiator

40. Differentiator
The differentiator does the opposite of the integrator in that it takes a sloping input and provides an output that is proportional to the rate of change of the input.
Note the capacitor is in the input circuit.
The output voltage can be determined by the formula below:

41. Comparator
The comparator is an op-amp circuit that compares two input voltages and produces an output indicating the relationship between them.
The inputs can be two signals (such as two sine waves) or a signal and a fixed dc reference voltage.
Comparators are most commonly used in digital applications.

42. Comparator
Digital circuits respond to rectangular or square waves, rather than sine waves.
These waveforms are made up of alternating (high and low) dc levels and the transitions between them.

43. Comparator
Example:
Assume that the digital system is designed to perform a specific function when a sine wave input reaches a value of 10 V

44. Comparator

45. Comparator
With nonzero-level detection the voltage divider or zener diode sets the reference voltage at which the op-amp turns goes to the maximum voltage level.

46. Comparator

47. Comparator
Remember that the comparator is configured in open-loop, making the gain very high. This is open-loop configuration.
This makes the comparator very susceptible to unwanted signals (noise) that could cause the output to arbitrarily switch states.

48. Comparator
If the level of the pulse must be less than the output of a saturated op-amp, a zener-diode can be used to limit the output to a particular voltage. This is called output bounding.
Either positive, negative, or both halves of the output signal can be bounded by use of one or two zener diodes respectively

49. Comparator - Application
Over-Temperature Sensing circuit

50. Comparator - Application
Analog to Digital Converter

51. Summary The summing amplifier’s output is the sum of the inputs.
An averaging amplifier yields an output that is the average of all the inputs.
The scaling adder has inputs of different weight with each contributing more or less to the input.
Integrators change a constant voltage input to a sloped output.
Differentiators change a sloping input into a step voltage proportional to the rate of change.
The op-amp comparator’s output changes state when the input voltage exceeds the reference voltage.

52. Frequency Response of Op-amp
The “frequency response” of any circuit is the magnitude of the gain in decibels (dB) as a function of the frequency of the input signal.
The decibel is a common unit of measurement for the relative magnitude of two power levels. The expression for such a ratio of power is:
Note: A decibel is one-tenth of a "Bel", a seldom-used unit named for Alexander Graham Bell, inventor of the telephone.
Power level in dB = 10log10(P1/P2)

53. Frequency Response of Op-amp
The voltage or current gain of an amplifier expressed in dB is 20 log10|A|, where A = Vout/Vin.
The frequency response of an op-amp has a low-pass characteristic (passing low-frequency signals, attenuating high-frequency signals).

54. Frequency Response of Op-amp
The bandwidth is the frequency at which the power of the output signal is reduced to half that of the maximum output power.
This occurs when the power gain A drops by 3 dB. In Figure shown before, the bandwidth is fc Hz.
For all op-amps, the Gain*Bandwidth product is a constant.
Hence, if the gain of an op-amp is decreased, its operational bandwidth increases proportionally.

55. Frequency Response of Op-amp
Another parameter reflecting the op-amp’s ability to varying signals is the slew rate.
Slew rate provides a parameter specifying the maximum rate of change of the output voltage when driven by a large step-input signal.
If one tried to drive the output at a rate of voltage change greater than the slew rate:
Output would not be able to change fast enough and would not vary over the full range expected
Clipping or distortion

56. Frequency Response of Op-amp
The maximum frequency at which an op-amp may operate depends on both the bandwidth (BW) and SR parameters of the op-amp.
Sinusoidal signal:
Signal maximum rate of change: 2πfK
To prevent distortion at the output, the rate of change must also be less than SR:

57. Example 1
For the signal and circuit below, determine the maximum frequency that may be used. Op-amp slew rate is SR = 0.5 V/µs.

58. Solution
Since the signal frequency, ω = 300 x 103 rad/s is less than the maximum value, no output distortion will result.

59. Exercise 1
Calculate the output voltage for the circuit below: