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Z.E. Z.E. Z.E. IE 211 INTRODUCTION TO ENGINEERING THERMODYNAMICS

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Presentation on theme: "Z.E. Z.E. Z.E. IE 211 INTRODUCTION TO ENGINEERING THERMODYNAMICS"— Presentation transcript:

1 Z.E. Z.E. Z.E. IE 211 INTRODUCTION TO ENGINEERING THERMODYNAMICS
Chapter 6 Part2 ‘’The Second Law of Thermodynamics’’ Z.E. Z.E. Z.E.

2 Z.E. Z.E. Z.E. CARNOT CYCLE + 2 isothermal processes
Heat engines are cyclic devices that converts heat into work and cycle efficiency depends on reversibility of the processes Reversible cycles provide upper limits on the performance of real engines Best known reversible cycle is CARNOT CYCLE (cannot be achieved in reality) Z.E. CARNOT CYCLE composed of 4 reversible processes; 2 isothermal processes 2 adiabatic processes + occur either in a closed or steady-flow system Z.E.

3 Z.E. Z.E. Z.E. 4 reversible processes REVERSIBLE ISOTHERMAL EXPANSION
Frictionless piston-cylinder Z.E. REVERSIBLE ISOTHERMAL EXPANSION Constant TH Reversible heat transfer during expansion (system and reservoir temp. is nearly the same) WORK IS DONE BY THE SYSTEM REVERSIBLE ADIABATIC EXPANSION Expansion with insulation (Q=0) TH drops to TL Reversible process(frictionless piston-cylinder) Z.E. REVERSIBLE ISOTHERMAL COMPRESSION Constant TL Reversible heat transfer during compression (system and sink temp. is nearly the same) WORK IS DONE BY THE SURROUNDINGS REVERSIBLE ADIABATIC COMPRESSION Compression with insulation (Q=0) TL increases to TH Reversible process(frictionless piston-cylinder) Z.E.

4 Z.E. Z.E. Z.E. Z.E. Z.E. Z.E. CARNOT CYCLE REVERSED CARNOT CYCLE
Area under : work done by gas Area under : work done on the gas Z.E. Z.E. REVERSED CARNOT CYCLE Carnot cycle is reversible Processes may occur in the reverse direction Z.E. Z.E. Refrigeration Carnot Cycle

5 Z.E. Z.E. Z.E. THE CARNOT PRINCIPLES
Related to thermal efficiency of reversible and irreversible (actual) heat engines QH QL Wnet,out Z.E. Wnet,out= QH-QL 1) th,2 (reversible) > th,1 (irreversible) (for heat engines operating between the same reservoirs) 2) th,2 (reversible) = th,3 (reversible) Z.E. (for heat engines operating between the same reservoirs) Violation of either statement results in the violation of 2nd Law of Thermodynamics

6 Z.E. Z.E. Z.E. THE THERMODYNAMIC TEMPERATURE SCALE
Temp. Scale that is independent of properties of substances According 2nd Carnot Principle thermal efficiency of a reversible heat engine, th; DEPENDS ON; Only on the temperature of reservoirs th, rev. = f(TH, TL) INDEPENDENT OF; Working fluid and its properties The way the cycle is executed The type of reversible engine used Z.E. Z.E.

7 For reversible cycles, the heat transfer ratio can be replaced by the absolute temperature functions; Z.E. Kelvin proposed to define a temp. scale On Kelvin scale, temperature ratios depends on the ratios of heat transfer between a reversible heat engine and reservoirs only! Z.E. Absolute temp.s Z.E. Water triple point was assigned the value K

8 Z.E. Z.E. Z.E.  CARNOT HEAT ENGINE
The theoretical heat engine that operates on the reversible Carnot cycle Z.E. Efficiency of any heat engine Efficiency of reversible heat engine Z.E. CARNOT EFFICIENCY Z.E. Highest efficiency of a heat engine can have An irreversible (actual) heat engines cannot reach this maximum value due to irreversibilities

9 COMPARISON of EFFICIENCIES OF REVERSIBLE AND IRREVERSIBLE HEAT ENGINES
Z.E. Z.E. The thermal efficiency of actual heat engines can be maximized by supplying heat to at the highest possible temperature (TH) (limited by material strength) and rejecting it at the lowest temperature possible(TL) (limited by the temp. of river, lake, etc,..) Z.E.

10 Z.E. Z.E. Z.E. CARNOT REFRIGERATOR AND HEAT PUMP 
A refrigerator or heat pump operating on the reversed Carnot cycle COP of any refrigerator COP of any heat pump Z.E. COP of reversible refrigerator COP of reversible heat pump Z.E. Highest coefficient of performance (COP) of refrigerator or heat pump operating between TH and TL can have

11 COMPARISON of EFFICIENCIES OF REVERSIBLE AND IRREVERSIBLE REFRIGERATORS
Z.E. Z.E. Z.E.

12 Thermal Efficiencies(th) and Coefficient of Performance (COP)
SUMMARY 2nd Law Thermal Efficiencies(th) and Coefficient of Performance (COP) Z.E. IRREVERSIBLE; REVERSIBLE; HEAT ENGINE Z.E. REFRIGERATOR HEAT PUMP Z.E.

13 STUDY QUESTIONS 1) A coal-burning steam power plant produces a net power of 300 MW with an overall thermal efficiency of 32 percent. The actual gravimetric air–fuel ratio in the furnace is calculated to be 12 kg air/kg fuel. The heating value of the coal is 28,000 kJ/kg. Determine (a) the amount of coal consumed and heat rejected during a 24-hour period (b) the rate of air flowing through the furnace. 2) An air conditioner removes heat steadily from a house at a rate of 750 kJ/min while drawing electric power at a rate of 6 kW. Determine; (a) the COP of this air conditioner (it works as a refrigerator) (b) the rate of heat transfer to the outside air.

14 3) A heat pump is used to maintain a house at a constant temperature of 23°C. The house is losing heat to the outside air through the walls and the windows at a rate of 60,000 kJ/h while the energy generated within the house from people, lights, and appliances amounts to 4000 kJ/h. For a COP of 2.5, determine the required power input to the heat pump. 4) Refrigerant-134a enters the condenser of a residential heat pump at 800 kPa and 35°C at a rate of kg/s and leaves at 800 kPa as a saturated liquid. If the compressor consumes 1.2 kW of power, determine (a) the COP of the heat pump (b) the rate of heat absorption from the outside air.

15 5) A Carnot heat engine receives 650 kJ of heat from a source of unknown temperature and rejects 250 kJ of it to a sink at 24°C. Determine, Work output Determine the thermal efficiency of the heat engine. 6) An inventor claims to have developed a heat engine that receives 700 kJ of heat from a source at 500 K and produces 300 kJ of net work while rejecting the waste heat to a sink at 290 K. Is this a reasonable claim? Why?

16 7) A refrigerator is to remove heat from the cooled space at a rate of 300 kJ/min to maintain its temperature at -8°C. If the air surrounding the refrigerator is at 25°C, determine the minimum power input required for this refrigerator. 8) The structure of a house is such that it loses heat at a rate of 5400 kJ/h per °C difference between the indoors and outdoors. A heat pump that requires a power input of 6 kW is used to maintain this house at 21°C. Determine the lowest outdoor temperature for which the heat pump can meet the heating requirements of this house.

17 9) A Carnot heat engine receives heat from a reservoir at 900°C at a rate of 800 kJ/min and rejects the waste heat to the ambient air at 27°C. The entire work output of the heat engine is used to drive a refrigerator that removes heat from the refrigerated space at -5°C and transfers it to the same ambient air at 27°C. Determine (a) the maximum rate of heat removal from the refrigerated space and (b) the total rate of heat rejection to the ambient air.


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