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Drawing Quadratic Curves

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Presentation on theme: "Drawing Quadratic Curves"β€” Presentation transcript:

1 Drawing Quadratic Curves
Slideshow 27, Mathematics Mr. Richard Sasaki

2 Objectives Understand how to draw graphs in the form 𝑦=π‘Ž π‘₯ 2 +𝑏
Learn how to draw graphs in the form 𝑦=π‘Ž π‘₯βˆ’β„Ž 2 +π‘˜ where π‘Žβ‰ 0

3 Review We know that for a graph in the form 𝑦=π‘Ž π‘₯ 2 … For π‘Ž>0…
When π‘Ž is small it looks like… When π‘Ž is large it looks like… When π‘Ž is small it looks like… When π‘Ž is large it looks like… π‘₯ 2 4 βˆ’ π‘₯ 2 3 𝑦= 𝑦= 5 π‘₯ 2 𝑦= 𝑦= βˆ’6 π‘₯ 2

4 𝑦=π‘Ž π‘₯ 2 +𝑏 If we add a constant 𝑏 to the statement, what effect does it have? 𝑦= π‘₯ Example Draw the graph 𝑦= π‘₯ We know its vertex is at ( , ) and the line is within Quadrants and . 0 1 𝐼 𝐼𝐼 𝒙 βˆ’πŸ 𝟎 𝟐 𝑦 1 3 3

5 Answers – Easy (Top) 𝑦= π‘₯ 2 βˆ’1 𝑦= 2π‘₯ 2 +2

6 Answers – Easy (Bottom)
𝑦= π‘₯ 𝑦= βˆ’π‘₯ 2 +5 For a graph in the form 𝑦=π‘Ž π‘₯ 2 +𝑏, it’s vertex is at ( , ). 0 𝑏

7 Answers – Hard (Top) 𝑦= 2π‘₯ 2 βˆ’ 1 2 𝑦= 4π‘₯ 2 βˆ’3

8 Answers – Hard (Bottom)
𝑦= π‘₯ 𝑦= βˆ’3π‘₯ 2 βˆ’2 If both axes range from βˆ’100 to 100, the rate of change will appear greater (line looks steeper).

9 In the form 𝑦=π‘Ž π‘₯βˆ’β„Ž 2 +π‘˜ For a graph with the equation 𝑦=π‘Ž π‘₯βˆ’β„Ž 2 +π‘˜, what are the co-ordinates of its vertex? In this form, and are constants. This makes the curve positive if is positive and negative if is negative. β„Ž π‘˜ π‘Ž π‘Ž The vertex must be a minimum if and a maximum if π‘Ž>0 π‘Ž<0 What is the smallest value 𝑦 can be if π‘Ž>0? π‘˜ What is the highest value 𝑦 can be if π‘Ž<0? π‘˜ Both of the above occur when = . π‘₯ β„Ž So the co-ordinates when π‘₯=β„Ž and 𝑦=π‘˜ are ( , ). β„Ž π‘˜

10 𝑦=π‘Ž π‘₯βˆ’β„Ž 2 +π‘˜ (Vertex Form)
Example 𝑦=2 π‘₯βˆ’3 2 βˆ’1 Draw the graph 𝑦=2 π‘₯βˆ’3 2 βˆ’1 and state its vertex. We know its vertex is at ( , ) and its shape is positive. 3 βˆ’1 𝒙 𝟐 πŸ‘ πŸ’ 𝑦 βˆ’1 1 1

11 Answers – Easy (Top) 𝑦= π‘₯βˆ’2 2 +1 𝑦= π‘₯βˆ’6 2 +4
A graph in the form 𝑦=π‘Ž π‘₯βˆ’β„Ž 2 +π‘˜ has a vertex at point ( , ) . β„Ž π‘˜ 𝑦= π‘₯βˆ’ 𝑦= π‘₯βˆ’

12 Answers – Easy (Bottom)
𝑦= 2 π‘₯βˆ’3 2 βˆ’1 𝑦= 3 π‘₯βˆ’

13 Answers – Medium (Top) Write down the vertex as a pair of co-ordinates for 𝑦=2 π‘₯+1 2 βˆ’3. (βˆ’1, βˆ’3) 𝑦= βˆ’ π‘₯βˆ’ 𝑦= 2 π‘₯

14 Answers – Medium (Bottom)
𝑦= π‘₯βˆ’ βˆ’3 𝑦= π‘₯ βˆ’4

15 Answers – Hard 1. 2 π‘₯+2 2 βˆ’1, (βˆ’2, βˆ’1) 2. A higher value of β„Ž shifts the graph to the right and a lower value shifts it to the left. 3. The axis of symmetry exists where π‘₯=β„Ž.


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