Presentation is loading. Please wait.

Presentation is loading. Please wait.

FAST FOURIER TRANSFORM ALGORITHMS

Similar presentations


Presentation on theme: "FAST FOURIER TRANSFORM ALGORITHMS"— Presentation transcript:

1 FAST FOURIER TRANSFORM ALGORITHMS
UNIT-II FAST FOURIER TRANSFORM ALGORITHMS

2 INTRODUCTION All Periodic Waves Can be Generated by Combining Sin and Cos Waves of Different Frequencies Number of Frequencies may not be finite Fourier Transform Decomposes a Periodic Wave into its Component Frequencies

3 DFT Definition Sample consists of n points, wave amplitude at fixed intervals of time: (p0,p1,p2, ..., pn-1) (n is a power of 2) Result is a set of complex numbers giving frequency amplitudes for sin and cos components Points are computed by polynomial: P(x)=p0+p1x+p2x pn-1xn-1

4 DFT Definition, continued
The complete DFT is given by P(1), P(w), P(w2), ... ,P(wn-1) w Must be a Primitive nth Root of Unity wn=1, if 0<i<n then wi ¹ 1

5 Divide and Conquer Method
Compute an n-point DFT using one or more n/2-point DFTs Need to find Terms involving w2 in following polynomial P(w)=p0+p1w+p2w2+p3w3+p4w pn-1wn-1 Even/Odd Separation P(w)= P1(w)+P2(w) P1(w)=p0+p2w2+p4w pn-2wn-2 P1(w)=Pe (w2)=p0+p2w+p4w1+...+pn-2w(n-2)/2

6 Even/Odd Separation Contd.
P(w)= P1(w)+P2(w) P1(w)=p0+p2w2+p4w pn-2wn-2 P1(w)=Pe (w2)=p0+p2w+p4w1+...+pn-2w(n-2)/2 P2(w)=p1w+p3w3+p5w pn-1wn-1 P2(w)= w P3(w)=p1+p3w pn-1wn-2 P3(w)=Po(w2)= p1+p3w+... +pn-1w(n-2)/2 P(w)= Pe(w2)+ wPo(w2) Pe & Po come from n/2 point FFTs

7 Fast Fourier Transform Algorithms
Consider DTFT Basic idea is to split the sum into 2 subsequences of length N/2 and continue all the way down until you have N/2 subsequences of length 2 Log2(8) N

8 Radix-2 FFT Algorithms - Two point FFT
We assume N=2^m This is called Radix-2 FFT Algorithms Let’s take a simple example where only two points are given n=0, n=1; N=2 Butterfly FFT y0 y0 y1 Advantage: Less computationally intensive: N/2.log(N)

9 General FFT Algorithm First break x[n] into even and odd
Let n=2m for even and n=2m+1 for odd Even and odd parts are both DFT of a N/2 point sequence Break up the size N/2 subsequent in half by letting 2mm The first subsequence here is the term x[0], x[4], … The second subsequent is x[2], x[6], …

10 Example Let’s take a simple example where only two points are given n=0, n=1; N=2 Same result

11 FFT Algorithms - Four point FFT
First find even and odd parts and then combine them: The general form:

12 FFT Algorithms - 8 point FFT


Download ppt "FAST FOURIER TRANSFORM ALGORITHMS"

Similar presentations


Ads by Google