1. 3 + 2c³ Finding Areas of Triangles 4c
Formula: Area = ½ (base) (height) or ½ bh
The height of a triangle is a line that runs from the highest point PERPENDICULAR to the base, meaning that it intersects that base at a right angle. 4c
This
Is the
Height since this is a right triangle
Area of this right triangle:
Multiply ½ times the base times the height
(1/2)(4c)( 3 + 2c³)
So (1/2)(4c) = 2c
Distribute 2c(3 + 2c³)
(2c)(3) + (2c)(2c³)
6c+ 4c⁴ units²
3 + 2c³
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2. Find the area and the perimeter of this triangle
Find the area and the perimeter of this triangle. This is an isosceles triangle which means it has two sides that are equal. The height of this triangle is given.
Formula: Area = ½ (base) (height) or ½ bh
Perimeter = distance around
To solve for the perimeter, simply add all of the sides:
4x + 4x + 4x +2 = 12x + 2 UNITS
To solve for area, multiply ½ times base times height:
(1/2)(4x + 2)( y²)
(1/2y²) (4x + 2)
Distribute:2xy² + y² units²
Click here to listen to an explanation of how to solve this problem. 4x 4x
Height = y²
This is as simple as you can get since you have two different terms you are adding together!
4x + 2