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“Théorie Analytique des Probabilités”, 1812

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1 “Théorie Analytique des Probabilités”, 1812
“It is remarkable that a science which began with the consideration of games of chance should have become the most important object of human knowledge.” Pierre Simon Laplace “Théorie Analytique des Probabilités”, 1812

2 General Discussion of Mean Values

3 P(u1), P(u2), P(u3),….., P(uM-1), P(uM)
The Binomial Distribution is only one example of a discrete probability distribution. Now, a brief discussion of a General Distribution. Most of the following is valid for ANY discrete probability distribution. Let u = a variable which can take on any of M discrete values: u1,u2,u3,…,uM-1,uM with probabilities P(u1), P(u2), P(u3),….., P(uM-1), P(uM)

4 So, μ ≡ ū ≡ <u> ū ≡ <u> ≡ (S2/S1)
The Mean (average) value of u is: ū ≡ <u> ≡ (S2/S1) Here, S1 ≡ ∑iP(ui) or S1 ≡ P(u1) + P(u2) + P(u3) +…+ P(uM-1) + P(uM) For a properly normalized distribution, we must have: S1 = ∑iP(ui) = 1. We assume this from now on. Also, S2 ≡ ∑iuiP(ui) or S2 ≡ u1P(u1) + u2P(u2) + u3P(u3) + …+ uM-1P(uM-1) + uMP(uM) Note: μ ≡ Standard notation for the mean value. So, μ ≡ ū ≡ <u>

5 <Δu> = <u - ū> = ū – ū = 0
Sometimes, ū is called the 1st moment of P(u). If F(u) is any function of u, the mean value of F(u) is: <F> ≡ ∑iF(ui)P(ui) Some simple mean values that are useful for describing any probability distribution P(u): 1. The Mean Value, μ ≡ ū ≡ <u> This is a measure of the central value of u about which the various values of ui are distributed. Consider the quantity Δu ≡ u - ū (deviation from the mean). It’s mean is: <Δu> = <u - ū> = ū – ū = 0  The mean value of the deviation from the mean is always zero!

6 <(Δu)2> = <(u - <u>)2> = <u2 -2uū – (ū)2>
Now, look at (Δu)2 = (u - <u>)2 (square of the deviation from the mean). It’s mean value is: <(Δu)2> = <(u - <u>)2> = <u2 -2uū – (ū)2> = <u2> - 2<u><u> – (<u>)2  <u2> - (<u>)2 This is called the “Mean Square Deviation” (from the mean). It is also called several different (equivalent!) other names: The Dispersion or The Variance or the 2nd Moment of P(u) about the mean. 1 σ2 = <(Δu)2> is a measurel of the spread of the u values about ū. Also <(Δu)2> = 0 if & only if ui = ū for all i. It can easily be shown that, <(Δu)2> ≥ 0, or <u2> ≥ (<u>)2 Note: σ2 ≡ Standard notation for the variance.

7 <(Δu)n> ≡ <(u - <u>)n>
Could also define the nth moment of P(u) about the mean: <(Δu)n> ≡ <(u - <u>)n> In Physics this is rarely used beyond n = 2 & almost never beyond n = 3 or 4. NOTE: From math: A knowledge of the probability distribution function P(u) gives complete information about the distribution of the values of u. But, a knowledge of only a few moments, like knowing just ū & <(Δu)2> implies only partial, though useful knowledge of the distribution. A knowledge of only some moments is not enough to uniquely determine P(u). Math Theorem In order to uniquely determine a distribution P(u), we need to know ALL moments of it. That is we need all moments for n = 0,1,2,3….  .

8 Mean Values for the Random Walk Problem
In the following, as before, the results will only be summarized. See other sources for derivation details. The Binomial Distribution is: WN(n1) = [N!/(n1!n2!)]pn1qn2 p = the probability of a step to the right, q = 1 – p = the probability of a step to the left. It is easily shown that this is properly normalized: ∑(n1 = 0N) WN(n1) = 1

9 <n1> + <n2> = N(p + q) = N μ = <n1> = Np
What is the mean number of steps to the right? <n1> ≡ ∑(n1 = 0N) n1WN(n1) = ∑(n1 = 0N) n1[N!/(n1!(N-n1)!] pn1qN-n (1) After derivation, the results are: Similarly, we can also easily show that the mean number of steps to the left is: Of course, <n1> + <n2> = N(p + q) = N as it should! μ = <n1> = Np <n2> = Nq

10 <m> = <n1> - <n2> = N( p – q)
What is the mean displacement, <x> = <m>ℓ? Clearly, m = n1 – n2, so <m> = <n1> - <n2> = N( p – q) & <x> = <m> ℓ = N( p – q)ℓ If p = q = ½, <m> = 0 so, <x> = <m>ℓ = = 0

11 σ2 = <(Δn1)2> = <(n1 - <n1>)2>
What is the dispersion (variance)? σ2 = <(Δn1)2> = <(n1 - <n1>)2> in the number of steps to the right? That is, what is the spread in n1 values about <n1>? After some math, we find: ; This is the dispersion or variance of the binomial distribution. The root mean square (rms) deviation from the mean is defined in general as: σ  [<(Δn1)2>]½. For the binomial distribution, this is σ = [Npq]½ Note that σ  Distribution Width σ2 = <(Δn1)2> = Npq

12 σ2 = <(Δn1)2> = Npq Summary: For the Binomial Distribution
Dispersion or variance in number of steps to the right: Root mean square (rms) deviation from the mean: σ  [<(Δn1)2>]½ = [Npq]½ and σ  Distribution Width Again note that: μ = <n1> = Np. So, the relative width of the distribution, / is: (/ ) = [Npq]½(Np) = (q½)(pN)½ If p = q, this is: (/) = 1(N)½ = (N)-½  As N increases, the mean value increases  N but the relative width decreases  (N)-½ σ2 = <(Δn1)2> = Npq

13 <(Δm)2> = 4<(Δn1)2>
What is the dispersion in the displacement x? <x2> = <(Δm)2>ℓ2 = <(m - <m>)2>ℓ2 Or, what is the spread in m values about <m>? Some math gives: <(Δm)2> = 4<(Δn1)2> Using <(Δn1)2> = Npq, this becomes: L If p = q = ½, we have <(Δm)2> = N <(Δm)2> = 4Npq

14 Relative Width: (/ ) = (q½)(pN)½
For the 1 Dimensional Random Walk Problem The Probability Distribution is Binomial: WN(n1) = [N!/(n1!n2!)]pn1qn2 Mean number of steps to the right:  = <n1> = Np Dispersion in n1: 2 = <(Δn1)2> = Npq Relative Width: (/ ) = (q½)(pN)½ for N increasing, the mean value increases  N, & the relative width decreases  (N)-½ N = 20 p = q = ½ q = 1 – p n2 = N - n1


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