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Non-Mendelian Genetics

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Presentation on theme: "Non-Mendelian Genetics"— Presentation transcript:

1 Non-Mendelian Genetics

2 Mendelian Genetics: Dominant & Recessive Review
One allele is DOMINANT over the other (because the dominant allele can “mask” the recessive allele) genotype: PP genotype: pp genotype: Pp phenotype: purple phenotype: white phenotype: purple

3 Review Problem: Dominant & Recessive
In pea plants, purple flowers (P) are dominant over white flowers (p). Show the cross between two heterozygous plants. P p GENOTYPES: - PP (25%) Pp (50%) pp (25%) - ratio 1:2:1 P p PP Pp Pp pp PHENOTYPES: - purple (75%) white (25%) - ratio 3:1

4 Non-Mendelian Genetics
Incomplete Dominance Codominance Multiple Alleles Polygenic Traits Sex-Linked Traits

5 Incomplete Dominance a third (new) phenotype appears in the heterozygous condition as a BLEND of the dominant and recessive phenotypes. Ex - Dominant Red (R) + Recessive White (r) = Hybrid Pink (Rr) RR = red rr = white Rr = pink

6 Problem: Incomplete Dominance
Show the cross between a pink and a white flower. GENOTYPES: R r - RR (0%) Rr (50%) rr (50%) - ratio 1:1 r Rr rr Rr rr PHENOTYPES: - pink (50%); white (50%) - ratio 1:1

7 Codominance NS = some of each NN = normal cells SS = sickle cells sick
in the heterozygous condition, both alleles are expressed equally with NO blending! Represented by using two DIFFERENT capital letters. Example: Dominant Black (B) + Dominant White (W) = Speckled Black and White Phenotype (BW) Sickle Cell Anemia - NS = some of each NN = normal cells SS = sickle cells sick

8 Codominance Example: Speckled Chickens
BB = black feathers WW = white feathers BW = black & white speckled feathers Notice – NO GRAY! NO BLEND! Each feather is either black or white

9 Codominance Example: Rhodedendron
R = allele for red flowers W = allele for white flowers Cross a homozygous red flower with a homozygous white flower.

10 Codominance Example: Roan cattle
cattle can be red (RR – all red hairs) white (WW – all white hairs) roan (RW – red and white hairs together)

11 Codominance Example: Appaloosa horses
Gray horses (GG) are codominant to white horses (WW). The heterozygous horse (GW) is an Appaloosa (a white horse with gray spots). Cross a white horse with an appaloosa horse. W W G W GW GW WW WW

12 Problem: Codominance Show the cross between an individual with sickle-cell anemia and another who is a carrier but not sick. N S GENOTYPES: - NS (50%) SS (50%) - ratio 1:1 S NS SS PHENOTYPES: - carrier (50%) sick (50%) - ratio 1:1

13 Multiple Alleles there are more than two alleles for a gene. Ex – blood type consists of two dominant and one recessive allele options. Allele A and B are dominant over Allele O (i)

14 Multiple Alleles: Lab Mouse Fur Colors
Fur colors (determined by 4 alleles): black agouti yellow

15 Multiple Alleles: Rabbit Fur Colors
Fur colors (determined by 4 alleles): full, chinchilla, himalayan, albino

16 Multiple Alleles: Blood Types (A, B, AB, O)
Rules for Blood Types: A and B are co-dominant (Both show) AA or IAIA = type A BB or IBIB = type B AB or IAIB = type AB A and B are dominant over O (Regular dom/rec) AO or IAi = type A BO or IBi = type B OO or ii = type O

17 Multiple Alleles: Blood Types (A, B, AB, O)

18 Allele (antigen) on RBC surface
Phenotype Possible Genotype(s) Allele (antigen) on RBC surface Can Donate Blood To Can Receive Blood From A IAi IAIA A, AB A, O B IBi IBIB B, AB B, O AB IAIB A, B, AB, O O ii

19 Problem: Multiple Alleles
Show the cross between a mother who has type O blood and a father who has type AB blood. GENOTYPES: i i - Ai (50%) Bi (50%) - ratio 1:1 A B Ai Bi PHENOTYPES: - type A (50%) type B (50%) - ratio 1:1

20 Problem: Multiple Alleles
Show the cross between a mother who is heterozygous for type B blood and a father who is heterozygous for type A blood. GENOTYPES: A i AB (25%); Bi (25%); Ai (25%); ii (25%) - ratio 1:1:1:1 B i AB ii Bi Ai PHENOTYPES: type AB (25%); type B (25%) type A (25%); type O (25%) - ratio 1:1:1:1

21 Polygenic Traits traits produced by multiple genes example: skin color

22 Sex-Linked Traits Gene is attached to the X chromosome only, not found on the Y chromosome at all. (women have XX, men have XY chromosomes). These disorders are more common in boys. examples: red-green colorblindness

23 Sex-Linked Traits in males, there is no second X chromosome to “mask” a recessive gene. If they get an X with the disorder, they have it. Girls must inherit defective X’s from both parents.

24

25 Sex-Linked Traits A: 29, B: 45, C: --, D: 26  Normal vision
 Red-green color blind A: 70, B: --, C: 5, D: 6  Red color blind A: 70, B: --, C: 5, D: 2  Green color blind


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