1. Section 2 Equation or inequalitiy

2. Monday October 2
Supplies –notebook- pencil- pen
Warm-up

3. The algebraic statement can be true with
1 solution
No solutions or
Infinite solution

4. Solving Equations Basics
Use properties of equality to UNDO operations and ISOLATE the variable
Addition property of equality
use to UNDO subtraction
Subtraction
use to UNDO addition
Multiplication
use to UNDO division
Division
use to UNDO multiplication

5. 𝑥 3 = 5 3∙ 𝑥 3 = 5∙ 3 X = 15 Use multiplication to UNDO division
𝑥 3 = 5
Use multiplication to UNDO division
Multiplication property of equality
3∙ 𝑥 3 = 5∙ 3
X = 15

6. 𝑥 = 4
Addition property of equality to undo subtraction
Multiplication property of equality to undo division
𝑥 = 4
𝑥 2 = 10
2∙ 𝑥 2 = 10∙2
X = 20

7. Solving equations with variables on both sides
1. Use distributive property to remove grouping symbols
2. SIMPLIFY the expressions on both sides of the equal sign
3. Use properties of equality to get the variables on one side of the equal
sign and the numbers with out variables on the other side of the equal sign
**** NEVER get everything to 1 side
4. Use properties of equality to solve

8. 3t - 2(t+3) = t -3(2n – 5) = ½(-12n + 30)
Warm- Up Tuesday Oct 3 Remind 4th period
3t - 2(t+3) = t
Distributive property
Combine like term (simplify)
Subtraction property of equality
-3(2n – 5) = ½(-12n + 30)
Distributive property on both sides
Addition property of equality

9. Review Oct 2 TRUTH STATEMENTS – Copy into your notes

10. Review Properties
From Oct 2
COPY into your notes
Place a check mark next
to all that apply.

11. (x-3)(x+2) = 0 (x-3) and (x+2) are factors of zero a ∙ b = 0
Zero Product Property – Oct 3 NOTES
(x-3)(x+2) = 0 (x-3) and (x+2) are factors of zero
a ∙ b = 0
Either “a” or “b” is zero so we can set them equal to zero to solve.
MP8 – look for the pattern
x - 3 = x + 2 = 0
x = x = -2

12. There are 3 factors in the above equation so we solve all 3!
2x = x + 4 = x + 5 = 0
x = x = x = -5
Truth statements – check your answers
2x(x+4)(x+5) = 0 replace all x’s with 0
2(0) (0 + 4)(0+5) = 0
0(4)(5) = 0
0 (20) = 0
0 = 0 TRUE! So x =0
2x(x+4)(x+5) replace all x’s with -4
2(-4)(-4 + 4)(-4 + 5) = 0
-8(0)(1) = 0
0(1) = 0
0 = 0 TRUE so x =-4
2x(x+4)(x+5) = 0 replace x with -5
2(-5)(-5 + 4)(-5 + 5) = 0
-10(-1)(0) = 0
10(0) = 0
0 = 0 TRUE! X = -5

13. x = -11 and x = 5 2