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1 Chapter 1

2 Passive Components Welcome to the Principles of Electric Circuits. You will study important ideas that are used in electronics. You may already be familiar with a few of the important parts used in electronic circuits. Resistors are introduced in Chapter 2. Resistors

3 Summary Passive Components
Capacitors will be introduced in Chapter 12. Capacitors

4 Summary Passive Components Inductors will be introduced in Chapter 13.

5 Summary Passive Components
Transformers will be introduced in Chapter 14. Transformers

6 Summary Active Components
Passive components are used in conjunction with active components to form an electronic system. Active components will be the subject of future courses. Transistors Integrated Circuits

7 Summary SI Fundamental Units Quantity Unit Symbol length meter
kilogram second ampere Kelvin candela mole m kg s A K cd mol mass time electric current temperature luminous intensity amount of substance

8 Summary Some Important Electrical Units
Except for current, all electrical and magnetic units are derived from the fundamental units. Current is a fundamental unit. Quantity Unit Symbol current ampere coulomb volt ohm watt A C V W charge voltage resistance power

9 Summary Some Important Magnetic Units
All magnetic units are derived from the fundamental units. Quantity Unit Symbol flux density tesla weber ampere-turns/meter ampere-turn webers/ampere-turns-meter ampere-turns/weber T Wb At/m At Wb/Atm At/Wb magnetic flux magnetizing force magnetomotive force permeability reluctance

10 Summary Example-1 Scientific and Engineering Notation
Very large and very small numbers are represented with scientific and engineering notation. Example-1 47,000,000 = 4.7 x 107 (Scientific Notation) = 47. x 106 (Engineering Notation)

11 Summary Example-2 Example-3 Scientific and Engineering Notation
= 2.7 x 10-5 (Scientific Notation) = 27 x 10-6 (Engineering Notation) Example-3 0.605 = 6.05 x 10-1 (Scientific Notation) = 605 x 10-3 (Engineering Notation)

12 Summary Large Engineering Metric Prefixes P T G M k peta tera giga
mega kilo 1015 1012 109 106 103 Can you name the prefixes and their meaning?

13 Summary Small Engineering Metric Prefixes m  n p f milli micro nano
pico femto 10-3 10-6 10-9 10-12 10-15 Can you name the prefixes and their meaning?

14 Summary Example-1 Metric Conversions Smaller unit 0.47 M = 470 k
When converting from a larger unit to a smaller unit, move the decimal point to the right. Remember, a smaller unit means the number must be larger. Smaller unit Example-1 0.47 M = 470 k Larger number

15 Summary Example-2 Metric Conversions Larger unit 10,000 pF = 0.01 F
When converting from a smaller unit to a larger unit, move the decimal point to the left. Remember, a larger unit means the number must be smaller. Larger unit Example-2 10,000 pF = 0.01 F Smaller number

16 Summary Example-1 Metric Arithmetic 10,000  + 22 k =
When adding or subtracting numbers with a metric prefix, convert them to the same prefix first. Example-1 10,000  + 22 k = 10,000  + 22,000  = 32,000  Alternatively, 10 k + 22 k = 32 k

17 Summary Example-2 Metric Arithmetic 200  + 1.0 mA =
When adding or subtracting numbers with a metric prefix, convert them to the same prefix first. Example-2 200  mA = 200 A + 1,000 A = 12,000 A Alternatively, 0.200 m mA = 1.2 mA

18 Selected Key Terms Engineering notation Exponent  Metric prefix
Scientific notation A system for representing any number as a one-, two-, or three-digit number times a power of ten with an exponent that is a multiple of three. The number to which a base is raised. A symbol that is used to replace the power of ten in numbers expressed in scientific or engineering notation. A system for representing any number as a number between 1 and 10 times a power of ten.

19 Quiz 1. A resistor is an example of a. a passive component
b. an active component c. an electrical circuit d. all of the above

20 Quiz 2. The electrical unit that is fundamental is the a. volt b. ohm
c. coulomb d. ampere

21 Quiz 3. In scientific notation, the number 0.000 56 is written
a. 5.6 x 104 b. 5.6 x 10-4 c. 56 x 10-5 d. 560 x 10-6

22 Quiz 4. In engineering notation, the number 0.000 56 is written
a. 5.6 x 104 b. 5.6 x 10-4 c. 56 x 10-5 d. 560 x 10-6

23 Quiz 5. The metric prefix nano means a. 10-3 b. 10-6 c. 10-9 d

24 Quiz 6. The metric prefix pico means a. 10-3 b. 10-6 c. 10-9 d

25 Quiz 7. The number 2700 MW can be written a. 2.7 TW b. 2.7 GW
c. 2.7 kW d. 2.7 mW

26 Quiz 8. The value 68 k is equal to a. 6.8 x 104  b. 68, 000 
c M d. All of the above

27 Quiz 9. The sum of 330 mW + 1.5 W is a. 331.5 mW b. 3.35 W c. 1.533 W
d W

28 Quiz 10. The quantity 200 V is the same as a. 0.000 200 V b. 20 mV
c V d. all of the above

29 Quiz Answers: 1. a 2. d 3. b 4. d 5. c 6. d 7. b 8. d 9. d 10. a

30 Chapter 2

31 Summary The Bohr atom is a tool for visualizing atomic structure.
The nucleus is positively charged and has the protons and neutrons. Electrons are negatively charged and in discrete shells. The atomic number is the number of protons and determines the particular element. In the neutral atom, the number of electrons is equal to the number of protons.

32 Summary The outer shell is called the valence shell. Electrons in this shell are involved in chemical reactions and in metals they account for electrical and thermal conductivity. A neutral Si atom is shown. There are 4 electrons in the valence shell. Question: Is Si a conductor, insulator, or semiconductor? Semiconductor

33 Summary There is a force (F) between charges. Like charges repel; unlike charges attract. The force is directly proportional to charge. The force is inversely proportional to square of distance.

34 Summary Voltage (V) is the work (W) per charge (Q); it is responsible for establishing current. Work is done as a charge is moved in the electric field from one potential to another. Voltage is the work per charge done against the electric field.

35 Summary Definition of voltage
One volt is the potential difference (voltage) between two points when one joule of work is used to move one coulomb of charge from one point to the other.

36 Summary Voltage Voltage is responsible for establishing current.
Sources of voltage include batteries, solar cells, and generators. A Cu-Zn battery, such as you might construct in a chemistry class, is shown.

37 Summary Current (I) is the amount of charge (Q) that flows past a point in a unit of time (t). One ampere is a number of electrons having a total charge of 1 C move through a given cross section in 1 s. Question: What is the current if 2 C passes a point in 5 s? 0.4 A

38 Summary Resistance is the opposition to current.
One ohm (1 ) is the resistance if one ampere (1 A) is in a material when one volt (1 V) is applied. Conductance is the reciprocal of resistance. Components designed to have a specific amount of resistance are called resistors.

39 Summary

40 Summary Question What is the resistance and tolerance of each of the four-band resistors? 5.1 k± 5% k± 5% 47  ± 10% 1.0  ± 5%

41 Summary Alphanumeric Labeling
Two or three digits, and one of the letters R, K, or M are used to identify a resistance value. The letter is used to indicate the multiplier, and its position is used to indicate decimal point position.

42 Summary Variable resistors include the potentiometer and rheostat. A potentiometer can be connected as a rheostat. The center terminal is connected to the wiper

43 Summary A basic circuit consists of 1) a voltage source, 2) a path and 3) a load. An example of a basic circuit is the flashlight, which has each of these.

44 Summary An important multipurpose instrument is the DMM, which can measure voltage, current, and resistance. Many include other measurement options.

45 Summary You need to recognize safety hazards and know what to do in an emergency. Read and review all of the precautions given in the text. Some key ones are: Electrical Shock - know the location of emergency shutoff. Know and follow safety rules in the lab. Use Class-C extinguisher for electrical fires. Be aware of burn hazards with jewelry. Electrical safety A safe area is neat. The area should be inspected regularly for hazards. Work area

46 Selected Key Terms Ampere AWG  Charge Circuit
The unit of electrical current (American Wire Gauge) A standardization based on wire diameter An electrical property of matter that exists because of an excess or a deficiency of electrons. Charge can be either + or . An interconnection of electronic components designed to produce a desired result. A basic circuit consists of a source, a load, and an interconnecting path.

47 Selected Key Terms Conductance Coulomb  Current Electron Ground
Ohm () The ability of a circuit to allow current. The unit is the siemans (S). The unit of electrical charge. The rate of flow of electrical charge. A basic particle of electrical charge in matter. The electron possesses a negative charge. The common or reference point in a circuit. The unit of resistance.

48 Selected Key Terms Conductance Coulomb  Current Electron Ground
Ohm () The ability of a circuit to allow current. The unit is the siemans (S). The unit of electrical charge. The rate of flow of electrical charge. A basic particle of electrical charge in matter. The electron possesses a negative charge. The common or reference point in a circuit. The unit of resistance.

49 Selected Key Terms Potentiometer  Resistance Rheostat Siemens Volt
Voltage A three-terminal variable resistor. The opposition to current. the unit is the ohm (). A two-terminal variable resistor. The unit of conductance The unit of voltage or electromotive force. The amount of energy per charge available to move electrons from one point to another in an electric circuit.

50 Quiz 1. The atomic number is the number of a. protons in the nucleus
b. neutrons in the nucleus c. protons plus neutrons in the nucleus d. electrons in the outer shell

51 Quiz 2. Valence electrons are a. in the outer shell
b. involved in chemical reactions c. relatively loosely bound d. all of the above

52 Quiz 3. The atomic particle responsible for electrical current in solid metallic conductors is the a. proton b. electron c. neutron d. all of the above

53 Quiz 4. The symbol for charge is a. C b.  c. Q d. W

54 Quiz 5. The definition for voltage is a. b. c. d.

55 Quiz 6. A battery stores a. electrons b. protons c. ions
d. chemical energy

56 Quiz 7. The unit of conductance is the a. ohm b. coulomb c. siemen
d. ampere

57 Quiz 8. A four-color resistor with the color bands gray-red- black-gold is a. 73  b. 82  c. 680  d. 820 

58 Quiz 9. A 330 k ± 5% resistor has the color bands
a. red-red-brown-gold b. orange-orange-yellow-gold c. yellow-yellow-red-gold d. yellow-yellow-green-gold

59 Quiz 10. The circular mil is a unit of a. length b. area c. volume
d. resistance

60 Quiz Answers: 1. a 2. d 3. b 4. c 5. c 6. d 7. c 8. b 9. b 10. b

61 Chapter 3

62 Summary Review of V, I, and R
the amount of energy per charge available to move electrons from one point to another in a circuit. Voltage is the rate of charge flow and is measured in amperes. Current is the opposition to current and is measured in ohms. Resistance is

63 Summary The most important fundamental law in electronics is Ohm’s law, which relates voltage, current, and resistance. Georg Simon Ohm ( ) studied the relationship between voltage, current, and resistance and formulated the equation that bears his name. Question: What is the current in from a 12 V source if the resistance is 10 ? 1.2 A

64 Summary Question: Ohm’s law
If you need to solve for voltage, Ohm’s law is: Question: What is the voltage across a 680  resistor if the current is 26.5 mA? 18 V

65 Summary Question: Ohm’s law
If you need to solve for resistance, Ohm’s law is: What is the (hot) resistance of the bulb? Question: 115 V 132 

66 Summary Graph of Current versus Voltage
A student takes data for a resistor and fits the straight line shown to the data. What is the resistance and the conductance of the resistor? Graph of Current versus Voltage The slope represents the conductance. The reciprocal of the conductance is the resistance:

67 Summary Graph of Current versus Voltage
Notice that the plot of current versus voltage for a fixed resistor is a line with a positive slope. What is the resistance indicated by the graph? 2.7 k What is its conductance? 0.37 mS

68 Summary Question: Graph of Current versus Resistance
If resistance is varied for a constant voltage, the current verses resistance curve plots a hyperbola. Question: What is the curve for a 3 V source?

69 Summary Application of Ohm’s law 26.8 mA
The resistor is green-blue brown-gold. What should the ammeter read?

70 Summary Troubleshooting
Some questions to ask before starting any troubleshooting are: Has the circuit ever worked? If the circuit once worked, under what conditions did it fail? What are the symptoms of the failure? What are the possible causes of the failure?

71 Summary Troubleshooting
Plan the troubleshooting by reviewing pertinent information: Schematics Instruction manuals Review when and how the failure occurred.

72 Summary Troubleshooting
You may decide to start at the middle of a circuit and work in toward the failure. This approach is called half- splitting. Based on the plan of attack, look over the circuit carefully and make measurements as needed to localize the problem. Modify the plan if necessary as you proceed.

73 Selected Key Terms Linear Ohm’s law Troubleshooting
Characterized by a straight-line relationship. A law stating that current is directly proportional to voltage and inversely proportional to current. A systematic process of isolating, identifying, and correcting a fault in a circuit or system.

74 Quiz 1. Holding the voltage constant, and plotting the current against the resistance as resistance is varied will form a a. straight line with a positive slope b. straight line with a negative slope c. parabola d. hyperbola

75 Quiz 2. When the current is plotted against the voltage for a fixed resistor, the plot is a a. straight line with a positive slope b. straight line with a negative slope c. parabola d. hyperbola

76 Quiz 3. For constant voltage in a circuit, doubling the resistance means a. doubling the current b. halving the current c. there is no change in the current d. depends on the amount of voltage

77 Quiz 4. A four-color resistor has the color-code red-violet- orange-gold. If it is placed across a 12 V source, the expected current is a mA b mA c mA d mA

78 Quiz 5. If the current in a 330  resistor is 15 mA, the applied voltage is approximately a. 5.0 V b. 22 V c. 46 V d. 60 V

79 Quiz 6. The current in a certain 4-band resistor is 22 mA when the voltage is 18 V. The color bands on the resistor are a. blue-gray-red-gold b. red-red-brown gold c. gray-red-brown-gold d. white-brown-red-gold

80 Quiz 7. The circuit with the largest current is a. (a) b. (b) c. (c)
d. (d)

81 Quiz 8. The circuit with the smallest current is a. (a) b. (b) c. (c)
d. (d)

82 Quiz 9. Before troubleshooting a faulty circuit you should find out
a. If the circuit ever worked b. The conditions that existed when it failed c. The symptoms of the failure d. All of the above

83 Quiz 10. A troubleshooting method that starts in the middle and works toward a fault is a. short-circuit testing b. comparison testing c. half-splitting d. resistance testing

84 Quiz Answers: 1. d 2. a 3. b 4. b 5. a 6. c 7. a 8. c 9. d 10. c

85 Chapter 4

86 Summary Energy Energy, W, is the ability to do work and is measured in joules. One joule is the work done when a force of one newton is applied through a distance of one meter. 1 m The symbol for energy, W, represents work, but should not be confused with the unit for power, the watt, W.

87 Summary Question: Energy
The kilowatt-hour (kWh) is a much larger unit of energy than the joule. There are 3.6 x 106 J in a kWh. The kWh is convenient for electrical appliances. Question: What is the energy used in operating a W heater for 20 minutes? 1200 W = 1.2 kW 20 min = 1/3 h 1.2 kW X 1/3 h =0.4 kWh

88 Summary Power Power is the rate energy is “used” (actually converted to heat or another form). Power is measured in watts (or kilowatts). Notice that rate always involves time. One watt = one joule/second Three equations for power in circuits that are collectively known as Watt’s law are:

89 Summary Example-1: Solution: Power
What power is dissipated in a 27  resistor is the current is A? Solution: Given that you know the resistance and current, substitute the values into P =I 2R.

90 Summary Example-2: Solution: Power
What power is dissipated by a heater that draws 12 A of current from a 110 V supply? Solution: The most direct solution is to substitute into P = IV.

91 Summary Example-3: Solution: Power
What power is dissipated in a 100  resistor with 5 V across it? Solution: The most direct solution is to substitute into 2 V P R It is useful to keep in mind that small resistors operating in low voltage systems need to be sized for the anticipated power.

92 Summary Resistor failures
Resistor failures are unusual except when they have been subjected to excessive heat. Look for discoloration (sometimes the color bands appear burned). Test with an ohmmeter by disconnecting one end from the circuit to isolate it and verify the resistance. Correct the cause of the heating problem (larger resistor?, wrong value?). Normal Overheated

93 Summary Question: Ampere-hour Rating of Batteries
Expected battery life of batteries is given as the ampere- hours specification. Various factors affect this, so it is an approximation. (Factors include rate of current withdrawal, age of battery, temperature, etc.) How many hours can you expect to have a battery deliver 0.5 A if it is rated at 10 Ah? Question: 20 h

94 Summary Question: Power Supply Efficiency
Efficiency of a power supply is a measure of how well it converts ac to dc. For all power supplies, some of the input power is wasted in the form of heat. As an equation, What is the efficiency of a power supply that converts 20 W of input power to 17 W of output power? Question: 85%

95 Selected Key Terms Ampere-hour rating Efficiency Energy Joule
A number determined by multiplying the current (A) times the length of time (h) that a battery can deliver that current to a load. The ratio of output power to input power of a circuit, usually expressed as a percent. The ability to do work. The SI unit of energy.

96 Selected Key Terms Kilowatt-hour (kWh)
Power Watt A large unit of energy used mainly by utility companies. The rate of energy useage The SI unit of power.

97 Quiz 1. A unit of power is the a. joule b. kilowatt-hour
c. both of the above d. none of the above

98 Quiz 2. The SI unit of energy is the a. volt b. joule c. watt
d. kilowatt-hour

99 Quiz 3. If the voltage in a resistive circuit is doubled, the power will be a. halved b. unchanged c. doubled d. quadrupled

100 Quiz 4. The smallest power rating you should use for a resistor that is 330  with 12 V across it is a. ¼ W b. ½ W c. 1 W d. 2 W

101 Quiz 5. The power dissipated by a light operating on 12 V that has 3 A of current is a. 4 W b. 12 W c. 36 W d. 48 W

102 Quiz 6. The power rating of a resistor is determined mainly by
a. surface area b. length c. body color d. applied voltage

103 Quiz 7. The circuit with the largest power dissipation is a. (a)
b. (b) c. (c) d. (d)

104 Quiz 8. The circuit with the smallest power dissipation is a. (a)
b. (b) c. (c) d. (d)

105 Quiz 9. A battery rated for 20 Ah can supply 2 A for a minimum of
b. 2 h c. 10 h d. 40 h

106 Quiz 10. The efficiency of a power supply is determined by
a. Dividing the output power by the input power. b. Dividing the output voltage by the input voltage. c. Dividing the input power by the output power. d. Dividing the input voltage by the output voltage.

107 Quiz Answers: 1. d 2. b 3. d 4. b 5. c 6. a 7. d 8. a 9. c 10. a

108 Chapter 5

109 Summary Summary Series circuits
All circuits have three common attributes. These are: 1. A source of voltage. 2. A load. 3. A complete path. A series circuit is one that has only one current path.

110 Summary Summary Series circuit rule for current:
Because there is only one path, the current everywhere is the same. 2.0 mA For example, the reading on the first ammeter is 2.0 mA, What do the other meters read? 2.0 mA 2.0 mA 2.0 mA

111 Summary Summary Series circuits
The total resistance of resistors in series is the sum of the individual resistors. For example, the resistors in a series circuit are 680 , 1.5 k, and 2.2 k. What is the total resistance? 4.38 k

112 Summary Summary Summary Series circuit
Tabulating current, resistance, voltage and power is a useful way to summarize parameters in a series circuit. Continuing with the previous example, complete the parameters listed in the Table. I1= R1= 0.68 k V1= P1= I2= R2= 1.50 k V2= P2= I3= R3= 2.20 k V3= P3= IT= RT= 4.38 k VS= 12 V PT= 2.74 mA 1.86 V 5.1 mW 2.74 mA 4.11 V 11.3 mW 2.74 mA 6.03 V 16.5 mW 2.74 mA 32.9 mW

113 Summary Summary Question: Voltage sources in series
Voltage sources in series add algebraically. For example, the total voltage of the sources shown is 27 V What is the total voltage if one battery is reversed? Question: 9 V

114 Summary Summary Kirchhoff’s voltage law is generally stated as:
The sum of all the voltage drops around a single closed path in a circuit is equal to the total source voltage in that closed path. KVL applies to all circuits, but you must apply it to only one closed path. In a series circuit, this is (of course) the entire circuit.

115 Summary Summary Kirchhoff’s voltage law
Notice in the series example given earlier that the sum of the resistor voltages is equal to the source voltage. I1= R1= 0.68 k V1= P1= 2.74 mA 1.86 V 5.1 mW I2= R2= 1.50 k V2= P2= 2.74 mA 4.11 V 11.3 mW I3= R3= 2.20 k V3= P3= 2.74 mA 6.03 V 16.5 mW IT= RT= 4.38 k VS= 12 V PT= 2.74 mA 32.9 mW

116 Summary Summary Question: Voltage divider rule
The voltage drop across any given resistor in a series circuit is equal to the ratio of that resistor to the total resistance, multiplied by source voltage. Assume R1 is twice the size of R2. What is the voltage across R1? Question: 8 V

117 Summary Summary Example: Solution: Voltage divider
What is the voltage across R2? Solution: Notice that 40% of the source voltage is across R2, which represents 40% of the total resistance. The total resistance is 25 k Applying the voltage divider formula:

118 Summary Summary Question: Voltage divider
Voltage dividers can be set up for a variable output using a potentiometer. In the circuit shown, the output voltage is variable. Question: What is the largest output voltage available? 5.0 V

119 Power in Series Circuits
Summary Summary Power in Series Circuits Example: Use the voltage divider rule to find V1 and V2. Then find the power in R1 and R2 and PT. Solution: Applying the voltage divider rule: The power dissipated by each resistor is: PT = 0.5 W }

120 Summary Summary Question: Circuit Ground
The term “ground” typically means a common or reference point in the circuit. Voltages that are given with respect to ground are shown with a single subscript. For example, VA means the voltage at point A with respect to ground. VB means the voltage at point B with respect to ground. VAB means the voltage between points A and B. Question: What are VA, VB, and VAB for the circuit shown? VA = 12 V VB = 8 V VAB = 4 V

121 Key Terms Circuit ground
Kirchhoff’s voltage law Open A method of grounding whereby the metal chassis that houses the assembly or a large conductive area on a printed circuit board is used as a common or reference point; also called chassis ground. A law stating that (1) the sum of the voltage drops around a closed loop equals the source voltage in that loop or (2) the algebraic sum of all of the voltages (drops and source) is zero. A circuit condition in which the current path is broken.

122 Key Terms Series Short Voltage divider In an electric circuit, a relationship of components in which the components are connected such that they provide a single path between two points. A circuit condition in which there is zero or an abnormally low resistance between two points; usually an inadvertent condition. A circuit consisting of series resistors across which one or more output voltages are taken.

123 Quiz 1. In a series circuit with more than one resistor, the current is a. larger in larger resistors b. smaller in larger resistors c. always the same in all resistors d. there is not enough information to say

124 Quiz 2. In a series circuit with more than one resistor, the voltage is a. larger across larger resistors b. smaller across larger resistors c. always the same across all resistors d. there is not enough information to say

125 Quiz 3. If three equal resistors are in series, the total resistance is a. one third the value of one resistor b. the same as one resistor c. three times the value of one resistor d. there is not enough information to say

126 Quiz 4. A series circuit cannot have a. more than two resistors
b. more than one voltage source c. more than one path d. all of the above

127 Quiz 5. In a closed loop, the algebraic sum of all voltages (both sources and drops) a. is 0 b. is equal to the smallest voltage in the loop c. is equal to the largest voltage in the loop d. depends on the source voltage

128 Quiz 6. The current in the 10 k resistor is a. 0.5 mA b. 2 mA
c. 2.4 mA d. 10 mA

129 Quiz 7. The output voltage from the voltage divider is a. 2 V b. 4 V
c. 12 V d. 20 V

130 Quiz 8. The smallest output voltage available from the voltage divider is a. 0 V b. 1.5 V c. 5.0 V d. 7.5 V

131 Quiz 9. The total power dissipated in a series circuit is equal to the
a. power in the largest resistor b. power in the smallest resistor c. average of the power in all resistors d. sum of the power in all resistors

132 Quiz 10. The meaning of the voltage VAB is the voltage at
a. Point A with respect to ground b. Point B with respect to ground c. The average voltage between points A and B. d. The voltage difference between points A and B.

133 Quiz Answers: 1. c 2. a 3. c 4. c 5. a 6. b 7. b 8. a 9. d 10. d

134 Chapter 6

135 Summary Summary Resistors in parallel
Resistors that are connected to the same two points are said to be in parallel.

136 Summary Summary Parallel circuits
A parallel circuit is identified by the fact that it has more than one current path (branch) connected to a common voltage source.

137 Summary Summary Parallel circuit rule for voltage
Because all components are connected across the same voltage source, the voltage across each is the same. For example, the source voltage is 5.0 V. What will a volt- meter read if it is placed across each of the resistors?

138 Summary Summary Parallel circuit rule for resistance
The total resistance of resistors in parallel is the reciprocal of the sum of the reciprocals of the individual resistors. For example, the resistors in a parallel circuit are 680 , 1.5 k, and 2.2 k. What is the total resistance? 386 

139 Summary Summary Parallel circuit
Tabulating current, resistance, voltage and power is a useful way to summarize parameters in a parallel circuit. Continuing with the previous example, complete the parameters listed in the Table. I1= R1= 0.68 k V1= P1= I2= R2= 1.50 k V2= P2= I3= R3= 2.20 k V3= P3= IT= RT= 386  VS= 5.0 V PT= 7.4 mA 5.0 V 36.8 mW 3.3 mA 5.0 V 16.7 mW 2.3 mA 5.0 V 11.4 mW 13.0 mA 64.8 mW

140 Summary Summary Kirchhoff’s current law is generally stated as:
The sum of the currents entering a node is equal to the sum of the currents leaving the node. Notice in the previous example that the current from the source is equal to the sum of the branch currents. I1= R1= 0.68 k V1= P1= I2= R2= 1.50 k V2= P2= I3= R3= 2.20 k V3= P3= IT= RT= 386  VS= 5.0 V PT= 5.0 V 13.0 mA 2.3 mA 3.3 mA 7.4 mA 36.8 mW 16.7 mW 11.4 mW 64.8 mW

141 Summary Summary Question:
Special case for resistance of two parallel resistors The resistance of two parallel resistors can be found by either: or Question: What is the total resistance if R1 = 27 k and R2 = 56 k? 18.2 k

142 Summary Summary Question: Parallel current sources
Current sources in parallel can be combined algebraically into a single equivalent source. The two current sources shown are aiding, so the net current in the resistor is their sum (2.5 mA). Question: (a) What is the current in R if the 1.5 mA source is reversed? 0.5 mA (b) Which end of R will be positive? The bottom

143 Summary Summary Current divider
When current enters a junction it divides with current values that are inversely proportional to the resistance values. and The most widely used formula for the current divider is the two-resistor equation. For resistors R1 and R2, Notice the subscripts. The resistor in the numerator is not the same as the one for which current is found.

144 Summary Summary Question: Power in parallel circuits
Power in each resistor can be calculated with any of the standard power formulas. Most of the time, the voltage is known, so the equation is most convenient. As in the series case, the total power is the sum of the powers dissipated in each resistor. Question: What is the total power if 10 V is applied to the parallel combination of R1 = 270  and R2 = 150 ? 1.04 W

145 Key Terms Branch One current path in a parallel circuit.
Current divider Junction Kirchhoff’s current law Parallel One current path in a parallel circuit. A parallel circuit in which the currents divide inversely proportional to the parallel branch resistances. A point at which two or more components are connected. Also known as a node. A law stating the total current into a junction equals the total current out of the junction. The relationship in electric circuits in which two or more current paths are connected between two separate points (nodes).

146 Quiz 1. The total resistance of parallel resistors is equal to
a. the sum of the resistances b. the sum of the reciprocals of the resistances c. the sum of the conductances d. none of the above

147 Quiz 2. The number of nodes in a parallel circuit is a. one b. two
c. three d. can be any number

148 Quiz 3. The total resistance of the parallel resistors is a. 2.52 k
b k c. 5.1 k d k

149 Quiz 4. If three equal resistors are in parallel, the total resistance is a. one third the value of one resistor b. the same as one resistor c. three times the value of one resistor d. there is not enough information to say

150 Quiz 5. In any circuit the total current entering a junction is
a. less than the total current leaving the junction b. equal to the total current leaving the junction c. greater than the total current leaving the junction d. can be any of the above, depending on the circuit

151 Quiz 6. The current divider formula to find I1 for the special case of two resistors is a. b. c. d.

152 Quiz 7. The total current leaving the source is a. 1.0 mA b. 1.2 mA
c. 6.0 mA d. 7.2 mA

153 Quiz 8. The current in R1 is a. 6.7 mA b mA c. 20 mA d mA

154 Quiz 9. The voltage across R2 is a. 0 V b V c V d. 4.0 V

155 Quiz 10. The total power dissipated in a parallel circuit is equal to the a. power in the largest resistor b. power in the smallest resistor c. average of the power in all resistors d. sum of the power in all resistors

156 Quiz Answers: 1. d 2. b 3. a 4. a 5. b 6. c 7. d 8. b 9. c 10. d

157 Chapter 7

158 Summary Summary Combination circuits
Most practical circuits have combinations of series and parallel components. You can frequently simplify analysis by combining series and parallel components. An important analysis method is to form an equivalent circuit. An equivalent circuit is one that has characteristics that are electrically the same as another circuit but is generally simpler.

159 Summary Summary Combination circuits For example: is equivalent to
There are no electrical measurements that can distinguish the boxes.

160 Summary Summary Combination circuits Another example: is equivalent to
There are no electrical measurements that can distinguish the boxes.

161 Summary Summary is equivalent to is equivalent to
There are no electrical measurements that can distinguish between the three boxes.

162 Summary Summary Combination circuits
Kirchhoff’s voltage law and Kirchhoff’s current law can be applied to any circuit, including combination circuits. So will this path! For example, applying KVL, the path shown will have a sum of 0 V.

163 Summary Summary Kirchoff’s current law can also be applied to the same circuit. What are the readings for node A?

164 Summary Summary Combination circuit
Tabulating current, resistance, voltage and power is a useful way to summarize parameters. Solve for the unknown quantities in the circuit shown. I1= R1= 270  V1= P1= 21.6 mA 5.82 V 126 mW I2= R2= 330  V2= P2= 12.7 mA 4.18 V 53.1 mW I3= R3= 470  V3= P3= 8.9 mA 4.18 V 37.2 mW IT= RT= VS= 10 V PT= 21.6 mA 464  216 mW

165 Summary Summary Kirchhoff’s laws can be applied as a check on the answer. equal to the sum of the branch currents in R2 and R3. Notice that the current in R1 is The sum of the voltages around the outside loop is zero. I1= R1= 270  V1= P1= 21.6 mA 5.82 V 126 mW I2= R2= 330  V2= P2= 12.7 mA 4.18 V 53.1 mW I3= R3= 470  V3= P3= 8.9 mA 4.18 V 37.2 mW IT= RT= VS= 10 V PT= 21.6 mA 464  216 mW

166 Summary Summary 4.04 V 10 V Loading effect of a voltmeter 4.04 V
Assume VS = 10 V, but the meter reads only 4.04 V when it is across either R1 or R2. Can you explain what is happening? All measurements affect the quantity being measured. A voltmeter has internal resistance, which can change the resistance of the circuit under test. In this case, a 1 M internal resistance of the meter accounts for the readings.

167 Summary Summary Wheatstone bridge
The Wheatstone bridge consists of four resistive arms forming two voltage dividers and a dc voltage source. The output is taken between the dividers. Frequently, one of the bridge resistors is adjustable. When the bridge is balanced, the output voltage is zero, and the products of resistances in the opposite diagonal arms are equal.

168 Summary Summary Summary Wheatstone bridge
Example: What is the value of R2 if the bridge is balanced? 330  470  12 V 384  270 

169 Key Terms Balanced bridge
Bleeder current Load A bridge circuit that is in the balanced state is indicated by 0 V across the output. The current left after the load current is subtracted from the total current into the circuit. An element (resistor or other component) connected across the output terminals of a circuit that draws current from the circuit.

170 Key Terms Unbalanced bridge
Wheatstone bridge A bridge circuit that is in the unbalanced state is indicated by a voltage across the output that is proportional to the amount of deviation from the balanced state. A 4-legged type of bridge circuit with which an unknown resistance can be accurately measured using the balanced state. Deviations in resistance can be measured using the unbalanced state.

171 Quiz 1. Two circuits that are equivalent have the same
a. number of components b. response to an electrical stimulus c. internal power dissipation d. all of the above

172 Quiz 2. If a series equivalent circuit is drawn for a complex circuit, the equivalent circuit can be analyzed with a. the voltage divider theorem b. Kirchhoff’s voltage law c. both of the above d. none of the above

173 Quiz 3. For the circuit shown, a. R1 is in series with R2
b. R1 is in parallel with R2 c. R2 is in series with R3 d. R2 is in parallel with R3

174 Quiz 4. For the circuit shown, a. R1 is in series with R2
b. R4 is in parallel with R1 c. R2 is in parallel with R3 d. none of the above

175 Quiz 5. The total resistance, RT, of the group of resistors is
a. 1.0 k b. 2.0 k c. 3.0 k d. 4.0 k

176 Quiz 6. For the circuit shown, Kirchhoff's voltage law
a. applies only to the outside loop b. applies only to the A junction. c. can be applied to any closed path. d. does not apply.

177 Quiz 7. The effect of changing a measured quantity due to connecting an instrument to a circuit is called a. loading b. clipping c. distortion d. loss of precision

178 Quiz 8. An unbalanced Wheatstone bridge has the voltages shown. The voltage across R4 is a. 4.0 V b. 5.0 V c. 6.0 V d. 7.0 V

179 Quiz 9. Assume R2 is adjusted until the Wheatstone bridge is balanced. At this point, the voltage across R4 is measured and found to be 5.0 V. The voltage across R1 will be a. 4.0 V b. 5.0 V c. 6.0 V d. 7.0 V

180 Quiz 10. For the circuit shown, if R3 opens, the voltage at point A will a. decrease b. stay the same. c. increase.

181 Quiz Answers: 1. b 2. c 3. d 4. d 5. b 6. c 7. a 8. a 9. d 10. c

182 Chapter 7

183 Summary Summary Combination circuits
Most practical circuits have combinations of series and parallel components. You can frequently simplify analysis by combining series and parallel components. An important analysis method is to form an equivalent circuit. An equivalent circuit is one that has characteristics that are electrically the same as another circuit but is generally simpler.

184 Summary Summary Combination circuits For example: is equivalent to
There are no electrical measurements that can distinguish the boxes.

185 Summary Summary Combination circuits Another example: is equivalent to
There are no electrical measurements that can distinguish the boxes.

186 Summary Summary is equivalent to is equivalent to
There are no electrical measurements that can distinguish between the three boxes.

187 Summary Summary Combination circuits
Kirchhoff’s voltage law and Kirchhoff’s current law can be applied to any circuit, including combination circuits. So will this path! For example, applying KVL, the path shown will have a sum of 0 V.

188 Summary Summary Kirchoff’s current law can also be applied to the same circuit. What are the readings for node A?

189 Summary Summary Combination circuit
Tabulating current, resistance, voltage and power is a useful way to summarize parameters. Solve for the unknown quantities in the circuit shown. I1= R1= 270  V1= P1= 21.6 mA 5.82 V 126 mW I2= R2= 330  V2= P2= 12.7 mA 4.18 V 53.1 mW I3= R3= 470  V3= P3= 8.9 mA 4.18 V 37.2 mW IT= RT= VS= 10 V PT= 21.6 mA 464  216 mW

190 Summary Summary Kirchhoff’s laws can be applied as a check on the answer. equal to the sum of the branch currents in R2 and R3. Notice that the current in R1 is The sum of the voltages around the outside loop is zero. I1= R1= 270  V1= P1= 21.6 mA 5.82 V 126 mW I2= R2= 330  V2= P2= 12.7 mA 4.18 V 53.1 mW I3= R3= 470  V3= P3= 8.9 mA 4.18 V 37.2 mW IT= RT= VS= 10 V PT= 21.6 mA 464  216 mW

191 Summary Summary 4.04 V 10 V Loading effect of a voltmeter 4.04 V
Assume VS = 10 V, but the meter reads only 4.04 V when it is across either R1 or R2. Can you explain what is happening? All measurements affect the quantity being measured. A voltmeter has internal resistance, which can change the resistance of the circuit under test. In this case, a 1 M internal resistance of the meter accounts for the readings.

192 Summary Summary Wheatstone bridge
The Wheatstone bridge consists of four resistive arms forming two voltage dividers and a dc voltage source. The output is taken between the dividers. Frequently, one of the bridge resistors is adjustable. When the bridge is balanced, the output voltage is zero, and the products of resistances in the opposite diagonal arms are equal.

193 Summary Summary Summary Wheatstone bridge
Example: What is the value of R2 if the bridge is balanced? 330  470  12 V 384  270 

194 Key Terms Balanced bridge
Bleeder current Load A bridge circuit that is in the balanced state is indicated by 0 V across the output. The current left after the load current is subtracted from the total current into the circuit. An element (resistor or other component) connected across the output terminals of a circuit that draws current from the circuit.

195 Key Terms Unbalanced bridge
Wheatstone bridge A bridge circuit that is in the unbalanced state is indicated by a voltage across the output that is proportional to the amount of deviation from the balanced state. A 4-legged type of bridge circuit with which an unknown resistance can be accurately measured using the balanced state. Deviations in resistance can be measured using the unbalanced state.

196 Quiz 1. Two circuits that are equivalent have the same
a. number of components b. response to an electrical stimulus c. internal power dissipation d. all of the above

197 Quiz 2. If a series equivalent circuit is drawn for a complex circuit, the equivalent circuit can be analyzed with a. the voltage divider theorem b. Kirchhoff’s voltage law c. both of the above d. none of the above

198 Quiz 3. For the circuit shown, a. R1 is in series with R2
b. R1 is in parallel with R2 c. R2 is in series with R3 d. R2 is in parallel with R3

199 Quiz 4. For the circuit shown, a. R1 is in series with R2
b. R4 is in parallel with R1 c. R2 is in parallel with R3 d. none of the above

200 Quiz 5. The total resistance, RT, of the group of resistors is
a. 1.0 k b. 2.0 k c. 3.0 k d. 4.0 k

201 Quiz 6. For the circuit shown, Kirchhoff's voltage law
a. applies only to the outside loop b. applies only to the A junction. c. can be applied to any closed path. d. does not apply.

202 Quiz 7. The effect of changing a measured quantity due to connecting an instrument to a circuit is called a. loading b. clipping c. distortion d. loss of precision

203 Quiz 8. An unbalanced Wheatstone bridge has the voltages shown. The voltage across R4 is a. 4.0 V b. 5.0 V c. 6.0 V d. 7.0 V

204 Quiz 9. Assume R2 is adjusted until the Wheatstone bridge is balanced. At this point, the voltage across R4 is measured and found to be 5.0 V. The voltage across R1 will be a. 4.0 V b. 5.0 V c. 6.0 V d. 7.0 V

205 Quiz 10. For the circuit shown, if R3 opens, the voltage at point A will a. decrease b. stay the same. c. increase.

206 Quiz Answers: 1. b 2. c 3. d 4. d 5. b 6. c 7. a 8. a 9. d 10. c

207 Chapter 8

208 Summary Summary Voltage sources
An ideal voltage source plots a vertical line on the VI characteristic as shown for the ideal 6.0 V source. Actual voltage sources include the internal source resistance, which can drop a small voltage under load. The characteristic of a non- ideal source is not vertical.

209 Summary Summary Voltage sources
A practical voltage source is drawn as an ideal source in series with the source resistance. When the internal resistance is zero, the source reduces to an ideal one.

210 Summary Summary Example: Solution: Voltage sources
If the source resistance of a 5.0 V power supply is 0.5 , what is the voltage across a 68  load? Solution: Use the voltage-divider equation

211 Summary Summary Current sources
An ideal current source plots a horizontal line on the VI characteristic as shown for the ideal 4.0 mA source. Practical current sources have internal source resistance, which takes some of the current. The characteristic of a practical source is not horizontal.

212 Summary Summary Current sources
A practical current source is drawn as an ideal source with a parallel source resistance. When the source resistance is infinite, the current source is ideal.

213 Summary Summary Example: Solution: Current sources
If the source resistance of a 10 mA current source is 4.7 k, what is the voltage across a 100  load? Solution: Use the current-divider equation

214 Summary Summary Source conversions
Any voltage source with an internal resistance can be converted to an equivalent current source and vice- versa by applying Ohm’s law to the source. The source resistance, RS, is the same for both. To convert a voltage source to a current source, To convert a current source to a voltage source,

215 Summary Summary Example: Superposition theorem
The superposition theorem is a way to determine currents and voltages in a linear circuit that has multiple sources by taking one source at a time and algebraically summing the results. Example: What does the ammeter read for I2? (See next slide for the method and the answer).

216 Summary Summary What does the ammeter read for I2?
Source 1: RT(S1)= I1= I2= Source 2: RT(S2)= I3= I2= Both sources I2= Set up a table of pertinent information and solve for each quantity listed: 6.10 k 1.97 mA 0.98 mA 8.73 k 2.06 mA 0.58 mA 1.56 mA The total current is the algebraic sum.

217 Summary Summary Thevenin’s theorem
Thevenin’s theorem states that any two-terminal, resistive circuit can be replaced with a simple equivalent circuit when viewed from two output terminals. The equivalent circuit is:

218 Summary Summary Thevenin’s theorem
the open circuit voltage between the two output terminals of a circuit. VTH is defined as the total resistance appearing between the two output terminals when all sources have been replaced by their internal resistances. RTH is defined as

219 Summary Summary Thevenin’s theorem
What is the Thevenin voltage for the circuit? 8.76 V What is the Thevenin resistance for the circuit? 7.30 k Output terminals Remember, the load resistor has no affect on the Thevenin parameters.

220 Summary Summary Thevenin’s theorem
Thevenin’s theorem is useful for solving the Wheatstone bridge. One way to Thevenize the bridge is to create two Thevenin circuits  from A to ground and from B to ground. The resistance between point A and ground is R1||R3 and the resistance from B to ground is R2||R4. The voltage on each side of the bridge is found using the voltage divider rule.

221 Summary Summary Example: Thevenin’s theorem
For the bridge shown, R1||R3 = and R2||R4 = The voltage from A to ground (with no load) is and from B to ground (with no load) is 165  179  7.5 V 6.87 V The Thevenin circuits for each of the bridge are shown on the following slide.

222 Summary Summary Thevenin’s theorem
Putting the load on the Thevenin circuits and applying the superposition theorem allows you to calculate the load current. The load current is: 1.27 mA

223 Summary Summary Norton’s theorem
Norton’s theorem states that any two-terminal, resistive circuit can be replaced with a simple equivalent circuit when viewed from two output terminals. The equivalent circuit is:

224 Summary Summary Norton’s theorem
the output current when the output terminals are shorted. IN is defined as the total resistance appearing between the two output terminals when all sources have been replaced by their internal resistances. RN is defined as

225 Summary Summary Norton’s theorem
What is the Norton current for the circuit? 17.9 mA What is the Norton resistance for the circuit? 359  Output terminals The Norton circuit is shown on the following slide.

226 Summary Summary Norton’s theorem
The Norton circuit (without the load) is: 17.9 mA 359 

227 Summary Summary Maximum power transfer
The maximum power is transferred from a source to a load when the load resistance is equal to the internal source resistance. The maximum power transfer theorem assumes the source voltage and resistance are fixed.

228 Summary Summary Example: Solution: Maximum power transfer
What is the power delivered to the matching load? Solution: The voltage to the load is 5.0 V. The power delivered is

229 Summary Summary -to-Y and Y-to- conversion
The -to-Y and Y-to- conversion formulas allow a three terminal resistive network to be replaced with an equivalent network. For the -to-Y conversion, each resistor in the Y is equal to the product of the resistors in the two adjacent  branches divided by the sum of all three  resistors.

230 Summary Summary -to-Y and Y-to- conversion
The -to-Y and Y-to- conversion formulas allow a three terminal resistive network to be replaced with an equivalent network. For the Y-to- conversion, each resistor in the  is equal to the sum of all products of Y resistors, taken two at a time divided by the opposite Y resistor.

231 Key Terms Current source
Maximum power transfer Norton’s theorem Superposition theorem A device that ideally provides a constant value of current regardless of the load. Transfer of maximum power from a source to a load occurs when the load resistance equals the internal source resistance. A method for simplifying a two-terminal linear circuit to an equivalent circuit with only a current source in parallel with a resistance. A method for analysis of circuits with more than one source.

232 Key Terms Terminal equivalency
Thevenin’s theorem Voltage source The concept that when any given load is connected to two sources, the same load voltage and current are produced by both sources. A method for simplifying a two-terminal linear circuit to an equivalent circuit with only a voltage source in series with a resistance. A device that ideally provides a constant value of voltage regardless of the load.

233 Quiz 1. The source resistance from a 1.50 V D-cell is 1.5 . The voltage that appears across a 75  load will be a V b V c V d V

234 Quiz 2. The internal resistance of an ideal current source a. is 0 
b. is 1  c. is infinite d. depends on the source

235 Quiz 3. The superposition theorem cannot be applied to
a. circuits with more than two sources b. nonlinear circuits c. circuits with current sources d. ideal sources

236 Quiz 4. A Thevenin circuit is a
a. resistor in series with a voltage source b. resistor in parallel with a voltage source c. resistor in series with a current source d. resistor in parallel with a current source

237 Quiz 4. A Norton circuit is a
a. resistor in series with a voltage source b. resistor in parallel with a voltage source c. resistor in series with a current source d. resistor in parallel with a current source

238 Quiz 5. A signal generator has an output voltage of 2.0 V with no load. When a 600  load is connected to it, the output drops to 1.0 V. The Thevenin resistance of the generator is a. 300  b. 600  c. 900  d .

239 Quiz 6. A signal generator has an output voltage of 2.0 V with no load. When a 600  load is connected to it, the output drops to 1.0 V. The Thevenin voltage of the generator is a. 1.0 V b. 2.0 V c. 4.0 V d. not enough information to tell.

240 Quiz 7. A Wheatstone bridge is shown with the Thevenin circuit as viewed with respect to ground. The total Thevenin resistance (RTH + RTH’) is a. 320  b. 500  c. 820  d k.

241 Quiz 8. The Norton current for the circuit is a. 5.0 mA b. 6.67 mA
c mA d. 10 mA

242 Quiz 9. The Norton resistance for the circuit is a. 500  b. 1.0 k
c. 1.5 k d. 2.0 k

243 Quiz 10. Maximum power is transferred from a fixed source when
a. the load resistor is ½ the source resistance b. the load resistor is equal to the source resistance c. the load resistor is twice the source resistance d. none of the above

244 Quiz Answers: 1. a 2. c 3. b 4. d 5. b 6. b 7. c 8. d 9. a 10. b

245 Chapter 9

246 Summary Summary Simultaneous Equations
Circuit analysis methods in Chapter 9 require use of simultaneous equations. To simplify solving simultaneous equations, they are usually set up in standard form. Standard form for two equations with two unknowns is constants coefficients variables

247 Summary Summary Example: Solution: Simultaneous Equations
A circuit has the following equations. Set up the equations in standard form. Solution: Rearrange so that variables and their coefficients are in order and put constants on the right.

248 Summary Summary Solving Simultaneous Equations
Three methods for solving simultaneous equations are Algebraic substitution The determinant method Using a calculator

249 Summary Summary Example: Solution: Solving Simultaneous Equations
Solve for IA using substitution. Solution: Solve for IB in the first equation: Substitute for IB into the second equation: Rearrange and solve for IA. IA =  mA

250 Summary Summary Solving Simultaneous Equations
If you wanted to find IB in the previous example, you can substitute the result of IA back into one of the original equations and solve for IB. Thus, 2.10 mA

251 Summary Summary Example: Solution: Solving Simultaneous Equations
The method of determinants is another approach to finding the unknowns. The characteristic determinant is formed from the coefficients of the unknowns. Write the characteristic determinant for the equations. Calculate its value. Example: Solution: 1.134

252 Summary Summary Solving Simultaneous Equations
To solve for an unknown by determinants, form the determinant for a variable by substituting the constants for the coefficients of the unknown. Divide by the characteristic determinant. To solve for x2: Constants Unknown variable Characteristic determinant

253 Summary Summary Example: Solution: Solving Simultaneous Equations
Solve the same equations using determinants: Solution:  mA  mA

254 Summary Summary Solving Simultaneous Equations
Many scientific calculators allow you to enter a set of equations and solve them “automatically”. The calculator method will depend on your particular calculator, but you will always write the equations in standard form first and then input the number of equations, the coefficients, and the constants. Pressing the Solve key will show the values of the unknowns.

255 Summary Summary Branch current method
In the branch current method, you can solve for the currents in a circuit using simultaneous equations. Steps: Assign a current in each branch in an arbitrary direction. Show polarities according to the assigned directions. Apply KVL in each closed loop. Apply KCL at nodes such that all branches are included. Solve the equations from steps 3 and 4.

256 Summary Summary Example: Solution: Branch current method
Solve the equations from steps 3 and 4 (see next slide). Apply KVL in each closed loop. Resistors are entered in k in this example. Apply KCL at nodes such that all branches are included. Show polarities according to the assigned directions. Assign a current in each branch in an arbitrary direction. Solution: A + + +

257 Summary Summary Solution: Branch current method
In standard form, the equations are (Continued) Solving: I1 = 9.53 mA, I2 = 7.43 mA, I3 = 2.10 mA The negative result for I3 indicates the actual current direction is opposite to the assumed direction.

258 Summary Summary Loop current method
In the loop current method, you can solve for the currents in a circuit using simultaneous equations. Steps: Assign a current in each nonredundant loop in an arbitrary direction. Show polarities according to the assigned direction of current in each loop. Apply KVL around each closed loop. Solve the resulting equations for the loop currents.

259 Summary Summary Example: Solution: Loop current method
Apply KVL around each closed loop. Resistors are entered in k in this example. Solve the resulting equations for the loop currents (see following slide). Show polarities according to the assigned direction of current in each loop. Assign a current in each nonredundant loop in an arbitrary direction. Solution: Notice that the polarity of R3 is based on loop B and is not the same as in the branch current method. + + + Loop A Loop B +

260 Summary Summary Solution: Loop current method
Rearranging the loop equations into standard form: (Continued) I1=IA = 9.53 mA I2= IAIB = 7.43 mA I3=IB = 2.10 mA + + + Loop A Loop B +

261 Summary Summary Loop current method applied to circuits with more than two loops The loop current method can be applied to more complicated circuits, such as the Wheatstone bridge. The steps are the same as shown previously. The advantage to the loop method for the bridge is that it has only 3 unknowns. Loop A Loop B Loop C

262 Summary Summary Example:
Write the loop current equation for Loop A in the Wheatstone bridge: Loop A Loop B Loop C

263 Summary Summary Node voltage method
In the node voltage method, you can solve for the unknown voltages in a circuit using KCL. Steps: Determine the number of nodes. Select one node as a reference. Assign voltage designations to each unknown node. Assign currents into and out of each node except the reference node. Apply KCL at each node where currents are assigned. Express the current equations in terms of the voltages and solve for the unknown voltages using Ohm’s law.

264 Summary Summary Example: Solution: Node voltage method
Solve the same problem as before using the node voltage method. Solution: Write KCL in terms of the voltages (next slide). Apply KCL at node A (for this case). There are 4 nodes. A is the one unknown node. Currents are assigned into and out of node A. B is selected as the reference node. A B

265 Summary Summary Node voltage method Solution: (Continued) A B

266 Key Terms Branch One current path that connects two nodes. Determinant
Loop Matrix Node Simultaneous equations One current path that connects two nodes. The solution of a matrix consisting of an array of coefficients and constants for a set of simultaneous equations. A closed current path in a circuit. An array of numbers. The junction of two or more components. A set of n equations containing n unknowns, where n is a number with a value of 2 or more.

267 Quiz In a set of simultaneous equations, the coefficient that is written a1,2 appears in a. the first equation b. the second equation c. both of the above d. none of the above

268 Quiz In standard form, the constants for a set of simultaneous equations are written a. in front of the first variable b. in front of the second variable c. on the right side of the equation d. all of the above

269 Quiz To solve simultaneous equations, the minimum number of independent equations must be at least a. two b. three c. four d. equal to the number of unknowns

270 Quiz In the equation a1,1x1 +a1,2x2 = b1, the quantity b1 represents
a. a constant b. a coefficient c. a variable d. none of the above

271 Quiz 5. The value of the determinant is a. 4 b. 14 c. 24 d. 34

272 Quiz The characteristic determinant for a set of simultaneous equations is formed using a. only constants from the equations b. only coefficients from the equations c. both constants and coefficients from the equations d. none of the above

273 Quiz A negative result for a current in the branch method means
a. there is an open path b. there is a short circuit c. the result is incorrect d. the current is opposite to the assumed direction

274 Quiz To solve a circuit using the loop method, the equations are first written for each loop by applying a. KCL b. KVL c. Ohm’s law d. Thevenin’s theorem

275 Quiz A Wheatstone bridge can be solved using loop equations. The minimum number of nonredundant loop equations required is a. one b. two c. three d. four

276 Quiz In the node voltage method, the equations are developed by first applying a. KCL b. KVL c. Ohm’s law d. Thevenin’s theorem

277 Quiz Answers: 1. a 2. c 3. d 4. a 5. b 6. b 7. d 8. b 9. c 10. a

278 Chapter 10

279 Summary Magnetic Quantities
Magnetic fields are described by drawing flux lines that represent the magnetic field. Where lines are close together, the flux density is higher. Where lines are further apart, the flux density is lower.

280 Summary Magnetic Quantities
Magnetic flux lines are invisible, but the effects can be visualized with iron filings sprinkled in a magnetic field.

281 Magnetic Materials Ferromagnetic materials such as iron, nickel and cobalt have randomly oriented magnetic domains, which become aligned when placed in a magnetic field, thus they effectively become magnets.

282 Summary Magnetic Quantities
The unit of flux is the weber. The unit of flux density is the weber/square meter, which defines the unit tesla, (T), which is a very large unit. Flux density is given by the equation where B = flux density (T)  = flux (Wb) A = area (m2)

283 Summary Magnetic Quantities
Example: What is the flux density in a rectangular core that is 8 mm by 10 mm if the flux is 4 mWb?

284 Summary Magnetic Quantities
Magnetic flux lines surround a current carrying wire. The field lines are concentric circles as shown in Figure of the text. Current-carrying wire Iron filings As in the case of bar magnets, the effects of electrical current can be visualized with iron filings around the wire – the current must be large to see this effect.

285 Summary Magnetic Quantities
Permeability () defines the ease with which a magnetic field can be established in a given material. It is measured in units of the weber per ampere-turn meter. The permeability of a vacuum (0) is 4 x 10-7 weber per ampere-turn meter, which is used as a reference. Relative Permeability (r) is the ratio of the absolute permeability to the permeability of a vacuum.

286 Summary Magnetic Quantities
Reluctance (R) is the opposition to the establishment of a magnetic field in a material. R= reluctance in A-t/Wb l = length of the path  = permeability (Wb/A-t m). A = area in m2

287 Summary Magnetic Quantities
Recall that magnetic flux lines surround a current-carrying wire. A coil reinforces and intensifies these flux lines. The cause of magnetic flux is called magnetomotive force (mmf), which is related to the current and number of turns of the coil. Fm = NI Fm = magnetomotive force (A-t) N = number of turns of wire in a coil I = current (A)

288 Summary Problem: Magnetic Quantities
Ohm’s law for magnetic circuits is flux () is analogous to current magnetomotive force (Fm) is analogous to voltage reluctance (R) is analogous to resistance. Problem: What flux is in a core that is wrapped with a 300 turn coil with a current of 100 mA if the reluctance of the core is 1.5 x 107 A-t/Wb? 2.0 Wb

289 Summary Magnetic Quantities
The magnetomotive force (mmf) is not a true force in the physics sense, but can be thought of as a cause of flux in a core or other material. Current in the coil causes flux in the iron core. Iron core What is the mmf if a 250 turn coil has 3 A of current? 750 A-t

290 Summary Solenoids A solenoid produces mechanical motion from an electrical signal. One application is valves that can remotely control a fluid in a pipe, such as in sprinkler systems.

291 Summary Relays A relay is an electrically controlled switch; a small control voltage on the coil can control a large current through the contacts. Alternate schematic symbol Structure Schematic symbol

292 Summary Magnetic field intensity is the magnetomotive force per unit length of a magnetic path. or H= Magnetic field intensity (Wb/A-t m) Fm = magnetomotive force (A-t) l = average length of the path (m) N = number of turns I = current (A) Magnetic field intensity represents the effort that a given current must put into establishing a certain flux density in a material.

293 Summary Magnetic Quantities
If a material is permeable, then a greater flux density will occur for a given magnetic field intensity. The relation between B (flux density) and H (the effort to establish the field) is B = H  = permeability (Wb/A-t m). H= Magnetic field intensity (Wb/A-t m) This relation between B and H is valid up to saturation, when further increase in H has no affect on B.

294 Summary As the graph shows, the flux density depends on both the material and the magnetic field intensity.

295 Summary As H is varied, the magnetic hysteresis curve is developed.

296 Summary Magnetization Curve
A B-H curve is referred to as a magnetization curve for the case where the material is initially unmagnetized. Annealed iron

297 Summary Magnetization Curve
A B-H curve can be read to determine the flux density in a given core. The next slide shows how to read the graph to determine the flux density in an annealed iron core. Annealed iron

298 Summary Example: Solution: Magnetization Curve What is B for the core?
Reading the graph, Annealed iron B = 1.63 T

299 Relative motion When a wire is moved across a magnetic field, there is a relative motion between the wire and the magnetic field. When a magnetic field is moved past a stationary wire, there is also relative motion. In either case, the relative motion results in an induced voltage in the wire.

300 Summary Induced voltage
The induced voltage due to the relative motion between the conductor and the magnetic field when the motion is perpendicular to the field is given by vind = Blv B = flux density in T l = length of the conductor in the magnetic field in m v = relative velocity in m/s (motion is perpendicular)

301 Summary Faraday’s law Faraday experimented with generating current by relative motion between a magnet and a coil of wire. The amount of voltage induced across a coil is determined by two factors: The rate of change of the magnetic flux with respect to the coil. Voltage is indicated only when magnet is moving.

302 Summary Faraday’s law Faraday also experimented generating current by relative motion between a magnet and a coil of wire. The amount of voltage induced across a coil is determined by two factors: The rate of change of the magnetic flux with respect to the coil. The number of turns of wire in the coil. Voltage is indicated only when magnet is moving.

303 Summary Magnetic field around a coil
Just as a moving magnetic field induces a voltage, current in a coil causes a magnetic field. The coil acts as an electromagnet, with a north and south pole as in the case of a permanent magnet.

304 Summary DC Motor A dc motor includes a rotating coil, which receives current through a split ring, called the commutator. The commutator is connected to fixed brushes, which are connected to an external circuit. The magnetic core is not shown for simplicity. Small motors may use a fixed magnet, as shown.

305 Selected Key Terms Magnetic field
Magnetic flux Weber (Wb) Permeability Reluctance A force field radiating from the north pole to the south pole of a magnet. The lines of force between the north pole and south pole of a permanent magnet or an electromagnet. The SI unit of magnetic flux, which represents 108 lines. The measure of ease with which a magnetic field can be established in a material. The opposition to the establishment of a magnetic field in a material.

306 Magnetic units It is useful to review the key magnetic units from this chapter: Quantity SI Unit Symbol Magnetic flux density Tesla Weber Weber/ampere-turn-meter Ampere-turn/Weber Ampere-turn Ampere-turn/meter B R Fm H Flux Permeability Reluctance Magnetomotive force Magnetizing force

307 Selected Key Terms Magnetomotive force (mmf)
Solenoid Hysteresis Retentivity The cause of a magnetic field, measured in ampere-turns. An electromagnetically controlled device in which the mechanical movement of a shaft or plunger is activated by a magnetizing current. A characteristic of a magnetic material whereby a change in magnetism lags the application of the magnetic field intensity. The ability of a material, once magnetized, to maintain a magnetized state without the presence of a magnetizing current.

308 Selected Key Terms Induced voltage (vind)
Faraday’s law Lenz’s law Voltage produced as a result of a changing magnetic field. A law stating that the voltage induced across a coil of wire equals the number of turns in the coil times the rate of change of the magnetic flux. A law stating that when the current through a coil changes, the polarity of the induced voltage created by the changing magnetic field is such that it always opposes the change in the current that caused it. The current cannot change instantaneously.

309 Quiz 1. A unit of flux density that is the same as a Wb/m2 is the
a. ampere-turn b. ampere-turn/weber c. ampere-turn/meter d. tesla

310 Quiz 2. If one magnetic circuit has a larger flux than a second magnetic circuit, then the first circuit has a. a higher flux density b. the same flux density c. a lower flux density d. answer depends on the particular circuit.

311 Quiz 3. The cause of magnetic flux is a. magnetomotive force
b. induced voltage c. induced current d. hysteresis

312 Quiz 4. The measurement unit for permeability is a. weber/ampere-turn
b. ampere-turn/weber c. weber/ampere-turn-meter d. dimensionless

313 Quiz 5. The measurement unit for relative permeability is
a. weber/ampere-turn b. ampere-turn/weber c. weber/ampere-turn meter d. dimensionless

314 Quiz 6. The property of a magnetic material to behave as if it had a memory is called a. remembrance b. hysteresis c. reluctance d. permittivity

315 Quiz 7. Ohm’s law for a magnetic circuit is a. b. c. d. Fm = NI B = H

316 Quiz 8. The control voltage for a relay is applied to the
a. normally-open contacts b. normally-closed contacts c. coil d. armature

317 Quiz 9. A partial hysteresis curve is shown. At the point indicated, magnetic flux a. is zero b. exists with no magnetizing force c. is maximum d. is proportional to the current

318 Quiz 10. When the current through a coil changes, the induced voltage across the coil will a. oppose the change in the current that caused it b. add to the change in the current that caused it c. be zero d. be equal to the source voltage

319 Quiz Answers: 1. d 2. d 3. a 4. c 5. d 6. b 7. c 8. c 9. b 10. a

320 Chapter 11

321 Summary Sine waves The sinusoidal waveform (sine wave) is the fundamental alternating current (ac) and alternating voltage waveform. Electrical sine waves are named from the mathematical function with the same shape.

322 Summary A wave is a disturbance. Unlike water waves, electrical waves cannot be seen directly but they have similar characteristics. All periodic waves can be constructed from sine waves, which is why sine waves are fundamental.

323 Summary Example Sine waves
Sine waves are characterized by the amplitude and period. The amplitude is the maximum value of a voltage or current; the period is the time interval for one complete cycle. Example A The amplitude (A) of this sine wave is 20 V T The period is 50.0 s

324 Summary Sine waves The period of a sine wave can be measured between any two corresponding points on the waveform. T T T T A T T By contrast, the amplitude of a sine wave is only measured from the center to the maximum point.

325 Summary Summary Example Frequency
Frequency ( f ) is the number of cycles that a sine wave completes in one second. Frequency is measured in hertz (Hz). Example If 3 cycles of a wave occur in one second, the frequency is 3.0 Hz 1.0 s

326 Summary Summary Example Period and frequency
The period and frequency are reciprocals of each other. and Thus, if you know one, you can easily find the other. (The 1/x key on your calculator is handy for converting between f and T.) Example If the period is 50 s, the frequency is 0.02 MHz = 20 kHz.

327 Summary Summary Sinusoidal voltage sources Generation of a sine wave
Sinusoidal voltages are produced by ac generators and electronic oscillators. When a conductor rotates in a constant magnetic field, a sinusoidal wave is generated. D B C A When the loop is moving perpendicular to the lines of flux, the maximum voltage is induced. When the conductor is moving parallel with the lines of flux, no voltage is induced.

328 AC generator (alternator)
Generators convert rotational energy to electrical energy. A stationary field alternator with a rotating armature is shown. The armature has an induced voltage, which is connected through slip rings and brushes to a load. The armature loops are wound on a magnetic core (not shown for simplicity). Small alternators may use a permanent magnet as shown here; other use field coils to produce the magnetic flux.

329 AC generator (alternator)
By increasing the number of poles, the number of cycles per revolution is increased. A four-pole generator will produce two complete cycles in each revolution.

330 Readout Function generators Typical controls: Function selection Frequency Range Adjust Outputs Output level (amplitude) Duty cycle DC offset CMOS output

331 Example Sine wave voltage and current values
There are several ways to specify the voltage of a sinusoidal voltage waveform. The amplitude of a sine wave is also called the peak value, abbreviated as VP for a voltage waveform. VP Example The peak voltage of this waveform is 20 V.

332 Example Sine wave voltage and current values
The voltage of a sine wave can also be specified as either the peak-to-peak or the rms value. The peak-to- peak is twice the peak value. The rms value is times the peak value. Example The peak-to-peak voltage is Vrms 40 V. VPP The rms voltage is 14.1 V.

333 Example Sine wave voltage and current values
For some purposes, the average value (actually the half- wave average) is used to specify the voltage or current. By definition, the average value is as times the peak value. Example Vavg The average value for the sinusoidal voltage is 12.7 V.

334 Angular measurement Angular measurements can be made in degrees (o) or radians. The radian (rad) is the angle that is formed when the arc is equal to the radius of a circle. There are 360o or 2 radians in one complete revolution.

335 Angular measurement Because there are 2 radians in one complete revolution and 360o in a revolution, the conversion between radians and degrees is easy to write. To find the number of radians, given the number of degrees: To find the number of degrees, given the radians:

336 Example Sine wave equation
Instantaneous values of a wave are shown as v or i. The equation for the instantaneous voltage (v) of a sine wave is where Vp = Peak voltage = Angle in rad or degrees Example If the peak voltage is 25 V, the instantaneous voltage at 50 degrees is 19.2 V

337 Sine wave equation A plot of the example in the previous slide (peak at 25 V) is shown. The instantaneous voltage at 50o is V as previously calculated.

338 Phase shift The phase of a sine wave is an angular measurement that specifies the position of a sine wave relative to a reference. To show that a sine wave is shifted to the left or right of this reference, a term is added to the equation given previously. where  = Phase shift

339 Phase shift Example of a wave that lags the reference
…and the equation has a negative phase shift v = 30 V sin (  45o) Notice that a lagging sine wave is below the axis at 0o

340 Phase shift Example of a wave that leads the reference
Notice that a leading sine wave is above the axis at 0o v = 30 V sin ( + 45o) …and the equation has a positive phase shift

341 Phasors The sine wave can be represented as the projection of a vector rotating at a constant rate. This rotating vector is called a phasor.

342 Phasors Phasors allow ac calculations to use basic trigonometry. The sine function in trigonometry is the ratio of the opposite side of a right triangle to the adjacent side.

343 Phasors The position of a phasor at any instant can be expressed as a positive angle, measured counterclockwise from 0 or as a negative angle equal to   360. positive angle of  negative angle of   360 phasor

344 Angular velocity of a phasor
When a phasor rotates through 360 or 2 radians, one complete cycle is traced out. The velocity of rotation is called the angular velocity ().  = 2f (Note that this angular velocity is expressed in radians per second.) The instantaneous voltage at any point in time is given by v = Vpsin 2f

345 Superimposed dc and ac voltages
Frequently dc and ac voltages are together in a waveform. They can be added algebraically, to produce a composite waveform of an ac voltage “riding” on a dc level.

346 Pulse definitions Ideal pulses

347 Pulse definitions Non-ideal pulses
Notice that rise and fall times are measured between the 10% and 90% levels whereas pulse width is measured at the 50% level.

348 Triangular and sawtooth waves
Triangular and sawtooth waveforms are formed by voltage or current ramps (linear increase/decrease) Triangular waveforms have positive-going and negative- going ramps of equal slope. The sawtooth waveform consists of two ramps, one of much longer duration than the other.

349 Harmonics All repetitive non-sinusoidal waveforms are composed of a fundamental frequency (repetition rate of the waveform) and harmonic frequencies. Odd harmonics are frequencies that are odd multiples of the fundamental frequency. Even harmonics are frequencies that are even multiples of the fundamental frequency.

350 Harmonics A square wave is composed only of the fundamental frequency and odd harmonics (of the proper amplitude).

351 Summary Oscilloscopes
The oscilloscope is divided into four main sections.

352 © Copyright 2006 Prentice-Hall
Principles of Electric Circuits - Floyd © Copyright 2006 Prentice-Hall

353 Summary Oscilloscopes Display Trigger Vertical Horizontal

354 Selected Key Terms Sine wave
Alternating current Period (T) Frequency (f) Hertz A type of waveform that follows a cyclic sinusoidal pattern defined by the formula y = A sin  Current that reverses direction in response to a change in source voltage polarity. The time interval for one complete cycle of a periodic waveform. A measure of the rate of change of a periodic function; the number of cycles completed in 1 s. The unit of frequency. One hertz equals one cycle per second.

355 Selected Key Terms Instantaneous value
Peak value Peak-to-peak value rms value The voltage or current value of a waveform at a given instant in time. The voltage or current value of a waveform at its maximum positive or negative points. The voltage or current value of a waveform measured from its minimum to its maximum points. The value of a sinusoidal voltage that indicates its heating effect, also known as effective value. It is equal to times the peak value. rms stands for root mean square.

356 Selected Key Terms Radian
Phasor Amplitude Pulse Harmonics A unit of angular measurement. There are 2 radians in one complete 360o revolution. A representation of a sine wave in terms of its magnitude (amplitude) and direction (phase angle). The maximum value of a voltage or current. A type of waveform that consists of two equal and opposite steps in voltage or current separated by a time interval. The frequencies contained in a composite waveform, which are integer multiples of the pulse repetition frequency.

357 Quiz 1. In North America, the frequency of ac utility voltage is 60 Hz. The period is a. 8.3 ms b ms c. 60 ms d. 60 s

358 Quiz 2. The amplitude of a sine wave is measured
a. at the maximum point b. between the minimum and maximum points c. at the midpoint d. anywhere on the wave

359 Quiz 3. An example of an equation for a waveform that lags the reference is a. v = 40 V sin () b. v = 100 V sin ( + 35o) c. v = 5.0 V sin (  27o) d. v = 27 V

360 Quiz 4. In the equation v = Vp sin  , the letter v stands for the
a. peak value b. average value c. rms value d. instantaneous value

361 Quiz 5. The time base of an oscilloscope is determined by the setting of the a. vertical controls b. horizontal controls c. trigger controls d. none of the above

362 Quiz 6. A sawtooth waveform has
a. equal positive and negative going ramps b. two ramps - one much longer than the other c. two equal pulses d. two unequal pulses

363 Quiz 7. The number of radians in 90o are a. /2 b.  c. 2/3 d. 2

364 Quiz 8. For the waveform shown, the same power would be delivered to a load with a dc voltage of a V b V c V d V

365 Quiz 9. A square wave consists of a. the fundamental and odd harmonics
b. the fundamental and even harmonics c. the fundamental and all harmonics d. only the fundamental

366 Quiz 10. A control on the oscilloscope that is used to set the desired number of cycles of a wave on the display is a. volts per division control b. time per division control c. trigger level control d. horizontal position control

367 Quiz Answers: 1. b 2. a 3. c 4. d 5. b 6. b 7. a 8. c 9. a 10. b

368 Chapter 12

369 Summary The Capacitor Capacitors are one of the fundamental passive components. In its most basic form, it is composed of two plates separated by a dielectric. The ability to store charge is the definition of capacitance. Conductors Dielectric

370 Summary The Capacitor Initially uncharged Source removed Fully charged
Charging The charging process… A capacitor with stored charge can act as a temporary battery.

371 Example Capacitance Capacitance is the ratio of charge to voltage
Rearranging, the amount of charge on a capacitor is determined by the size of the capacitor (C) and the voltage (V). Example If a 22 F capacitor is connected to a 10 V source, the charge is 220 C

372 Capacitance An analogy:
Imagine you store rubber bands in a bottle that is nearly full. You could store more rubber bands (like charge or Q) in a bigger bottle (capacitance or C) or if you push them in more (voltage or V). Thus,

373 Capacitance A capacitor stores energy in the form of an electric field that is established by the opposite charges on the two plates. The energy of a charged capacitor is given by the equation where W = the energy in joules C = the capacitance in farads V = the voltage in volts

374 Summary Capacitance The capacitance of a capacitor depends on three physical characteristics. C is directly proportional to the relative dielectric constant and the plate area. C is inversely proportional to the distance between the plates

375 Summary Example Capacitance
Find the capacitance of a 4.0 cm diameter sensor immersed in oil if the plates are separated by 0.25 mm. Example The plate area is The distance between the plates is 178 pF

376 Summary Capacitor types Mica
Mica capacitors are small with high working voltage. The working voltage is the voltage limit that cannot be exceeded.

377 Summary Capacitor types Ceramic disk
Ceramic disks are small nonpolarized capacitors They have relatively high capacitance due to high r.

378 Summary Capacitor types Plastic Film
Plastic film capacitors are small and nonpolarized. They have relatively high capacitance due to larger plate area.

379 Summary Capacitor types Electrolytic (two types)
Electrolytic capacitors have very high capacitance but they are not as precise as other types and tend to have more leakage current. Electrolytic types are polarized. Al electrolytic Ta electrolytic Symbol for any electrolytic capacitor

380 Summary Capacitor types Variable
Variable capacitors typically have small capacitance values and are usually adjusted manually. A solid-state device that is used as a variable capacitor is the varactor diode; it is adjusted with an electrical signal.

381 Capacitor labeling Capacitors use several labeling methods. Small capacitors values are frequently stamped on them such as .001 or .01, which have units of microfarads. Electrolytic capacitors have larger values, so are read as F. The unit is usually stamped as F, but some older ones may be shown as MF or MMF).

382 Example Capacitor labeling
A label such as 103 or 104 is read as 10x103 (10,000 pF) or 10x104 (100,000 pF) respectively. (Third digit is the multiplier.) When values are marked as 330 or 6800, the units are picofarads. Example What is the value of each capacitor? Both are 2200 pF.

383 Summary Series capacitors
When capacitors are connected in series, the total capacitance is smaller than the smallest one. The general equation for capacitors in series is The total capacitance of two capacitors is …or you can use the product-over-sum rule

384 Summary Example Series capacitors
If a F capacitor is connected in series with an 800 pF capacitor, the total capacitance is 444 pF

385 Summary Example Parallel capacitors
When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitors. The general equation for capacitors in parallel is Example If a F capacitor is connected in parallel with an 800 pF capacitor, the total capacitance is 1800 pF

386 Summary Capacitors in dc circuits
When a capacitor is charged through a series resistor and dc source, the charging curve is exponential.

387 Summary Capacitors in dc circuits
When a capacitor is discharged through a resistor, the discharge curve is also an exponential. (Note that the current is negative.)

388 Summary Question Capacitors in dc circuits VS
The same shape curves are seen if a square wave is used for the source. VC What is the shape of the current curve? Question VR The current has the same shape as VR.

389 Summary Universal exponential curves
Specific values for current and voltage can be read from a universal curve. For an RC circuit, the time constant is Rising exponential Falling exponential

390 Summary Universal exponential curves
The universal curves can be applied to general formulas for the voltage (or current) curves for RC circuits. The general voltage formula is v =VF + (Vi VF)et/RC VF = final value of voltage Vi = initial value of voltage v = instantaneous value of voltage The final capacitor voltage is greater than the initial voltage when the capacitor is charging, or less that the initial voltage when it is discharging.

391 Summary Example Capacitive reactance
Capacitive reactance is the opposition to ac by a capacitor. The equation for capacitive reactance is Example The reactance of a F capacitor when a frequency of 15 kHz is applied is 226 

392 Summary Capacitive phase shift
When a sine wave is applied to a capacitor, there is a phase shift between voltage and current such that current always leads the voltage by 90o.

393 Summary Power in a capacitor
Energy is stored by the capacitor during a portion of the ac cycle and returned to the source during another portion of the cycle. Voltage and current are always 90o out of phase. For this reason, no true power is dissipated by a capacitor, because stored energy is returned to the circuit. The rate at which a capacitor stores or returns energy is called reactive power. The unit for reactive power is the VAR (volt-ampere reactive).

394 Summary Switched capacitors
Switched capacitors move charge in a specific time interval between two points that are different voltages. The switched capacitors emulate a resistor with a value of R=1/fC. Switched capacitors are widely used in certain types of integrated circuits because they can be made very small, have virtually no drift, and do not dissipate heat.

395 Selected Key Terms Capacitor Dielectric Farad RC time constant
An electrical device consisting of two conductive plates separated by an insulating material and possessing the property of capacitance. The insulating material between the conductive plates of a capacitor. The unit of capacitance. A fixed time interval set by the R and C values, that determine the time response of a series RC circuit. It equals the product of the resistance and the capacitance.

396 Selected Key Terms Capacitive reactance
Instantaneous power (p) True power (Ptrue) Reactive power (Pr ) VAR (volt-ampere reactive) The opposition of a capacitor to sinusoidal current. The unit is the ohm. The value of power in a circuit at a given instant of time. The power that is dissipated in a circuit usually in the form of heat. The rate at which energy is alternately stored and returned to the source by a capacitor. The unit is the VAR. The unit of reactive power.

397 Quiz 1. The capacitance of a capacitor will be larger if
a. the spacing between the plates is increased b. air replaces oil as the dielectric c. the area of the plates is increased d. all of the above

398 Quiz 2. The major advantage of a mica capacitor over other types is
a. they have the largest available capacitances b. their voltage rating is very high c. they are polarized d. all of the above

399 Quiz 3. Electrolytic capacitors are useful in applications where
a. a precise value of capacitance is required b. low leakage current is required c. large capacitance is required d. all of the above

400 Quiz 4. If a F capacitor is in series with a 6800 pF capacitor, the total capacitance is a pF b pF c pF d F

401 Quiz 5. Two capacitors that are initially uncharged are connected in series with a dc source. Compared to the larger capacitor, the smaller capacitor will have a. the same charge b. more charge c. less voltage d. the same voltage

402 Quiz 6. When a capacitor is connected through a resistor to a dc voltage source, the charge on the capacitor will reach 50% of its final charge in a. less than one time constant b. exactly one time constant c. greater than one time constant d. answer depends on the amount of voltage

403 Quiz 7. When a capacitor is connected through a series resistor and switch to a dc voltage source, the voltage across the resistor after the switch is closed has the shape of a. a straight line b. a rising exponential c. a falling exponential d. none of the above

404 Quiz 8. The capacitive reactance of a 100 F capacitor to 60 Hz is
a k b. 265  c  d 

405 Quiz 9. If an sine wave from a function generator is applied to a capacitor, the current will a. lag voltage by 90o b. lag voltage by 45o c. be in phase with the voltage d. none of the above

406 Quiz 10. A switched capacitor emulates a a. smaller capacitor
b. larger capacitor c. battery d. resistor

407 Quiz Answers: 1. c 2. b 3. c 4. b 5. a 6. a 7. c 8. d 9. d 10. d


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