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Equations with Perimeter and Area

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Presentation on theme: "Equations with Perimeter and Area"— Presentation transcript:

1 Equations with Perimeter and Area
Objective: SWBAT solve application problems to include perimeter and area of rectangles.

2 Vocabulary: Perimeter the perimeter is the sum of ALL the lengths of the sides of a two dimensional shape Area the amount of space (two dimensional) inside a shape expressed in square units

3 Equation - _____________________ 2x - 4
Practice Problems: Solve for the missing sides of the rectangle by creating an equation through the process of combining like-terms. The perimeter is 64 in. Equation - _____________________ 2x - 4 x + 6 x = _______ The sides are: _____ _____ _____ _____ 2x – 4 x + 6 + x + 6 6x + 4 6x + 4 = 64 = 64 2(10) – 4 20 – 4 16 6x + 4 = 64 6x = 60 x = 10 10 + 6 16 10 16 in 16 in 16 in 16 in

4 Equation - _____________________
The perimeter is 42 cm. Equation - _____________________ 3x x + 2 3x + 2 x = _______ The sides are: _____ _____ _____ 9x + 6 = 42 3x + 2 + 3x + 2 9x + 6 3(4) + 2 12 + 2 14 = 42 9x + 6 = 42 9x = 36 x = 4 4 14 cm 14 cm 14 cm

5 Equation - _____________________ 3x - 2 4
Practice Problems: Solve for the missing sides of the rectangle by creating an equation through the process of using the distributive property. The area is 52 ft2 Equation - _____________________ 3x - 2 4 x = _______ The sides are: _____ _____ _____ _____ 4(3x – 2) = 52 12x – 8 = 52 12x = 60 x = 5 4(3x – 2) = 52 3(5) - 2 15 - 2 13 5 4 ft 4 ft 13 ft 13 ft

6 Equation - _____________________ x + 3
The area is 42 in2 Equation - _____________________ x + 3 3 x = _______ The sides are: _____ _____ _____ _____ 3(x + 3) = 42 11 + 3 14 3(x + 3) = 42 3x + 9 = 42 3x = 33 x = 11 11 3 in 3 in 14 in 14 in


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