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Chapter 4 Quadratic Equations

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1 Chapter 4 Quadratic Equations

2 4.1 Graphical Solutions of Quadratic Equations
You can solve a quadratic equation of the form ax2 + bx + c = 0 by graphing the corresponding quadratic function, f(x) = ax2 + bx + c. The solutions to a quadratic equation are called the roots of the equation. You can find the roots by determining the x-intercepts of the graph, or the zeros of the quadratic function. The zeros of a function are the values of x for which f(x) = 0. The graph of a quadratic function can have zero, one, or two real x-intercepts. Therefore, a quadratic equation has zero, one, or two real roots.

3 4.2 Factoring Quadratic Equations
Another way of solving a quadratic equation is by factoring. To solve the equation: first write the equation in the form of ax2 + bx + c = 0 then factor the left side Next, set each factor to zero and solve for the unknown Ex. x2 + 8x = -12 x2 + 8x + 12 = 0 (x + 6)(x + 2) = 0 x + 2 = 0 or x + 6 = 0 x = or x = - 6 Check both answers by substituting the x value: (-2)2 + 8(-2) = (-6)2 + 8(-6) = -12 = = -12 -12 = - 12 ✓ = -12 ✓

4 4.3 Solving the Quadratic Equation by Completing the Square
As recalled, completing the square is the process of rewriting a quadratic polynomial from the standard form ax2 + bx + c, to the vertex form, a(x - p)2 + q. You can use this method to determine the roots of a quadratic equation. Ex. 2x2 - 4x - 2 = 0 x2 - 2x - 1 = 0 Divide both sides by a common factor of 2 x2 - 2x = 1 Isolate the variable terms on the left side x2 - 2x + 1 = Complete the square on both sides (x - 1)2 = 2 √(x - 1)2 = √ 2 Take the square root of both sides x - 1 = ±√2 x = ±√2 + 1 +√2 + 1 ≈ √2 + 1 ≈ -0.41 x ≈ x ≈ -0.41

5 4.4 The Quadratic Formula An alternate method to solve a quadratic equation is using the quadratic formula in the form of ax2 + bx + c = 0. The formula is: x = -b2 ± √ b2 - 4ac 2a There is also the discriminant which is the expression b2 - 4ac located under the radical sign in the formula. You can use the discriminant to determine the nature of the roots for a quadratic equation. when the value of the discriminant is positive, b2 - 4ac > 0, there are two distinct roots when the value of the discriminant is zero, b2 - 4ac = 0, there is one distinct root when the value of the discriminant is negative, b2 - 4ac < 0, there are no real roots

6 Example: Use the quadratic formula to solve 6x2 - 14x + 8 = 0
x = -b2 ± √ b2 - 4ac 2a x = -(-14) ± √ (-14)2 - 4(6)(8) 2(8) x = 14 ± √ 4 16 x = 14 ± 2 x = or x = x = x = 12 x = 1 x = 3 4


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