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4.2 Implicit Differentiation

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Presentation on theme: "4.2 Implicit Differentiation"β€” Presentation transcript:

1 4.2 Implicit Differentiation

2 Folium of Descartes (1638)-the graph of the equation x3 + y3 -9xy = 0 has a well-defined slope at nearly every point. But how can we find the slope when we cannot conveniently solve the equation?

3 Implicit Differentiation
The process we use to find 𝑑𝑦 𝑑π‘₯ is called implicit differentiation. The phrase derives from the fact that the equation x3 + y3 -9xy = 0 defines functions f1,f2, and f3 implicitly (hidden inside the equation) without giving explicit formulas to work with.

4 Ex. Find 𝑑𝑦 𝑑π‘₯ if y2 = x. The derivative appears as a function of y. This is quite useful. The curve y2 = x has two different tangent lines when x =4: one at (4,2) and the other at (4, -2).

5 Ex. 2 Implicit differentiation will frequently yield a derivative that is expressed in terms of both x and y. Find the slope of the circle π‘₯ 2 +𝑦2=25 at the point (3,-4).

6 Implicit Differentiation Process
1. Differentiate both sides of the equation with respect to x. 2. Collect the terms with 𝑑𝑦 𝑑π‘₯ on one side of the equation. 3. Factor out 𝑑𝑦 𝑑π‘₯ . 4. Solve for 𝑑𝑦 𝑑π‘₯ .

7 Ex. 3 Show that the slope 𝑑𝑦 𝑑π‘₯ is defined at every point on the graph of 2y = x2 + sin y.

8 Lenses, Tangents, and Normal Lines
In the law that describes how light changes direction as it enters a lens, the important angles are the angles the light makes with the line perpendicular to the surface of the lens at the point of entry. This is the normal to the surface at the point of entry. The normal line is perpendicular to the tangent to the profile at the point of entry.

9 Ex. 4 Tangent and normal to an ellipse
Find the tangent and normal to the ellipse π‘₯ 2 βˆ’π‘₯𝑦+ 𝑦 2 = at the point (-1,2).

10 Ex. Derivatives of Higher Order
Find 𝑑 2 𝑦 𝑑π‘₯ 2 if 2π‘₯ 3 βˆ’ 3𝑦 2 =8.

11 Rational Powers of Differentiable Functions
The power rule ( 𝑑 𝑑π‘₯ π‘₯ 𝑛 =𝑛 π‘₯ π‘›βˆ’1 ) holds when n is any rational number. If n <1, then the derivative does not exist at x = 0. We combine this rule with the Chain Rule to produce: 𝑑 𝑑π‘₯ 𝑒 𝑛 = 𝑛𝑒 π‘›βˆ’1 𝑑𝑒 𝑑π‘₯ provided that uβ‰ 0 𝑖𝑓 𝑛<1.

12 Ex. Using the Rational Power Rule
𝑑 𝑑π‘₯ ( π‘₯ )

13 3 MC questions most students get wrong.

14 Homework


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