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Graphing Quadratic Functions

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Presentation on theme: "Graphing Quadratic Functions"— Presentation transcript:

1 Graphing Quadratic Functions

2 Quadratic Function A function of the form y=ax2+bx+c where a≠0 making a u-shaped graph called a parabola. Example quadratic equation:

3 The vertical line through the vertex of the parabola.
The lowest or highest point of a parabola. Vertex Axis of symmetry- The vertical line through the vertex of the parabola. Axis of Symmetry

4 Standard Form Equation
y=ax2 + bx + c If a is positive, u opens up If a is negative, u opens down The x-coordinate of the vertex is at To find the y-coordinate of the vertex, plug the x-coordinate into the given eqn. The axis of symmetry is the vertical line x= Choose 2 x-values on either side of the vertex x-coordinate. Use the eqn to find the corresponding y-values. Graph and label the 5 points and axis of symmetry on a coordinate plane. Connect the points with a smooth curve.

5 Vertex Form Equation y=a(x-h)2+k If a is positive, parabola opens up
If a is negative, parabola opens down. The vertex is the point (h,k). The axis of symmetry is the vertical line x=h. Don’t forget about 2 points on either side of the vertex! (5 points total!)

6 Intercept Form Equation
y=a(x-p)(x-q) The x-intercepts are the points (p,0) and (q,0). The axis of symmetry is the vertical line x= The x-coordinate of the vertex is To find the y-coordinate of the vertex, plug the x-coord. into the equation and solve for y. If a is positive, parabola opens up If a is negative, parabola opens down.

7 Example 1: Graph y=2x2-8x+6 Axis of symmetry is the vertical line x=2
Table of values for other points: x y 0 6 1 0 2 -2 3 0 4 6 * Graph! a=2 Since a is positive the parabola will open up. Vertex: use b=-8 and a=2 Vertex is: (2,-2) x=2

8 Now you try one. y=-x2+x+12. Open up or down. Vertex. Axis of symmetry
Now you try one! y=-x2+x+12 * Open up or down? * Vertex? * Axis of symmetry? * Table of values with 5 points?

9 (.5,12) (-1,10) (2,10) (-2,6) (3,6) X = .5

10 Example 2: Graph y=-.5(x+3)2+4
a is negative (a = -.5), so parabola opens down. Vertex is (h,k) or (-3,4) Axis of symmetry is the vertical line x = -3 Table of values x y -1 2 -3 4 -5 2 Vertex (-3,4) (-4,3.5) (-2,3.5) (-5,2) (-1,2) x=-3

11 Table of values with 5 points?
Now you try one! y=2(x-1)2+3 Open up or down? Vertex? Axis of symmetry? Table of values with 5 points?


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