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Resistors in Series Req=equivalent resistance.

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Presentation on theme: "Resistors in Series Req=equivalent resistance."— Presentation transcript:

0 ECE 1270: Introduction to Electric Circuits
Lecture 4: Equivalent Networks Chapter 3 Simple Resistive Circuits

1 Resistors in Series Req=equivalent resistance

2 Resistors in Series Req=equivalent resistance

3 Resistors in Parallel Req=equivalent resistance

4 Example 3.1: Find is, i1, i2 3+6=9 in parallel with 18, Find parallel combo of 18||9=6 Now, Is=120/10=12A. Define V1 across 6 ohm. Then V1=Is*6=72V Find I1=V1/18 = 4A, I2=V1/9=8A.

5 AP 3.1 (a) Find the voltage v
(b) power delivered the to the circuit the current source (c) power disspated in the 10 Ω resistor

6 Voltage Divider Circuit
Formulas for V1 and V2

7 Voltage Divider Examples

8 Current Divider Circuit
Formulas

9 Current Divider Examples
Example 3.3: Find power dissipated in 6 Ω resistor AP 3.3: Find R such that 4 A will flow through 80 Ω resistor

10 How do you measure Current and Voltage in a circuit?
Use Ammeter to measure the current: connect it in series Use Voltmeter to measure the voltage: connect it in parallel

11 Delta-to-Y (Pi-to-Tee) Equivalent Circuits
Delta or Pi Configuration Y or Tee Configuration

12 Delta-to-Y Transformation
Example 3.7: Find power supplied by 40V source Wheatstone Bridge

13 How do you measure Resistance?
Wheatstone Bridge The example 3.7 is a wheatstone bridge, which is used to measure resistance When the bridge is balanced, ig=0 and i1=i3 and i2=ix Then, Rx/R3=R2/R1 If R2=R1 then Rx=R3

14 Y-to-Delta Transformation
AP3.8: Use Y-to-Delta transformation to find v


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