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CHE 106: General Chemistry

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1 CHE 106: General Chemistry
CHAPTER ONE Copyright © James T. Spencer All Rights Reserved

2 Matter What is Chemistry Benefits of Chemistry Why Study Chemistry
Study of the “Physical” Properties Matter (Form and Function) Study of How Matter Changes (Reactivity) Benefits of Chemistry Pharmaceuticals Enhanced food production (fertilizers, herbicides, etc...) Plastics and Polymers Why Study Chemistry Core requirement (?) Central Science Employment Many fields BIO Physics Medicine GEO Engr CHEM Law also: environmental economics electronics agriculture politics etc... S.U. B.S. Chapt. 1.1

3 Chemistry; Common Chemicals
acetic acid vinegar calcium hypochloride bleaching powder calcium sulfate plaster of paris carbon tetrachloride cleaning fluid ferric oxide iron rust graphite pencil lead magnesium sulfate Epsom salts naphthalene mothballs silicon dioxide sand sodium bicarbonate baking soda sodium borate borax sodium hydroxide lye sulfuric acid battery acid sucrose cane sugar

4 Chemistry; Chemical Production
H2SO4 1995 Chemical and Engineering News N2 O2 C2H4 CaO NH3 H3PO4 C3H6 NaOH Cl2

5 Nanoscale Chemistry Use simpler molecular units are molecular-architectural elements

6 Nanoscale Chemistry

7 Nanosystems

8 Nanomachines Interstellar Space Travel - Significant concepts in this area include: launch vehicles, the space elevator, interplanetary transportation, the swarm concept, smart dust, extraterrestrial materials utilization, terraforming, suspended animation, space telescopes and virtual sample return. Human Therapeutics - Nanotechnology has caused scientists to re-examine the problems of the human body from the perspective of atomic- engineering. By assuming a nanotechnological red blood cell point of view, the resolution of therapeutic ailments becomes simple. Nano-Robots and Nano-Computers with advanced Artificial Intelligence - Nanotechnology will operate under the control of nano-sized computers which will manage the process of Molecular Manufacturing. In order to achieve this, it will be necessary to devise advanced Artificial Intelligence that will be able to automate and regulate Molecular Manufacturing systems.

9 Matter; A Review Definition of Matter States Forms Properties
anything that occupies space and has mass States gas (vapor); no fixed volume or shape, compressable liquid; fixed volume no fixed shape, mostly incompressable solid; fixed volume and shape, incompressable Forms Substances (pure or single); has a fixed composition and distinct properties. Most things encountered are mixtures of substances. Properties Physical Properties; can be measured without changing the substance, i.e., color, density, melting point, etc... Chemical Properties; the way a substance changes (reacts), i.e., combustion Chapt. 1.1

10 Matter; A Review Chemical Changes Physical Changes burning melting
Physical - Changes in appearance but not identity, i.e., evaporation, melting (all changes of state) Chemical - transformation into a different substance Chemical Changes Physical Changes burning melting C6H12O6 + 6O CO2 + 6H2O H2O(s) H2O(l) chemical reactions sublimation NaOH + HCl H2O + NaCl H2O(s) H2O(g) corrosion dissolution 4Fe + 3O Fe2O H2O(l ) + NaCl(s) NaCl(aq) Chapt. 1.1

11 Matter; A Review Mixtures; combinations of substances
Mixture- combination of two or more substances in which each retains its own chemical identity (and properties). Vary widely by composition (infinite possibilities of combining ratios), can be separated using the different physical properties of the component substances. Homogeneous - appears the same throughout (solutions), liquid, gas and solid solutions are possible. Heterogeneous - mixtures which do not have the same (uniform) appearance throughout. Chapt. 1.1

12 Matter; A Review Salt and Sand Mixture Ink from Cabbage Juice
solubility and filtration chromatography Water from Salt Water Iron and Gold Mixture distillation magnetic properties melting point differences chem. reactivity (acids) Iodine from Copper Chloride solubility and filtration Separating Mixtures using Physical Properties How would you separate; Chapt. 1.1

13 Matter; A Review Filtration Sand from Salt
Separating Mixtures using Physical Properties How would you separate; Flow Filter Everyday Examples; Auto Oil Filter Auto Air Filter Aquarium Water Filter Spaghetti Strainer Window Screens Registrar Chapt. 1.1

14 Matter; A Review NaCl(s) + H2O(l) NaCl(aq) Distillation
Water from Salt Water Separating Mixtures using Physical Properties How would you separate; NaCl(s) + H2O(l) NaCl(aq) Chapt. 1.1

15 Matter; A Review Chromatograpgy Dyes from M&M’s
Separating Mixtures using Physical Properties How would you separate; Before After Dyes Chapt. 1.1

16 Matter; Elements and Compounds
Substances Elements - substances which cannot be decomposed into simpler substances (see periodic table) Compounds- substances which can be separated into two or more elements Elements 110 Known (periodic table to be revisited) make up all matter and composed of “subatomic particles” symbols used for abbreviations (from older or common names) Compounds Elements combined in a definite proportion by mass (law of definite proportion) properties different than consititutent elements Water; example of mixtures, compound and elements? Chapt. 1.2

17 Matter; Elements and Periodic Table
See Website:

18 Matter Matter Uniform ? Heterogeneous Mixture Homogeneous
No Yes Uniform ? Heterogeneous Mixture Homogeneous No Can be separated by physical methods Pure Substance Yes Decomposed ? Homogeneous Mixture (solution) No Yes Element Compound

19 Scientific Method Theory Form and test hypothesis Patterns and Trends
Observations and Experiments

20 Observations to Theory
Observations Theory

21 Observations to Theory
Observations Theory

22 Observations to Theory
Observations Theory

23 Matter; Measurement A B Which is True? A = B A > B A < B

24 Matter; Measurement A B Which is True? A = B A > B A < B

25 Matter; Measurement A B Which is True? A = B A > B A < B

26 Matter; Measurement Systems Metric - base 10
SI- international scientific system mass Kilogram length Meter time Second electric current Ampere temperature Kelvin light Candela Amount Mole Factor label method for conversions Chapt. 1.3

27 Matter; Measurement Kilo k 103 Deci d 10-1 Centi c 10-2 Milli m 10-3
Prefixes Mega M 106 Kilo k 103 Deci d 10-1 Centi c 10-2 Milli m 10-3 Micro  10-6 Nano n 10-9 Chapt. 1.3

28 Matter; Measurement Sample exercise: What fraction of a second is a picosecond, ps? Chapt. 1.3

29 Matter; Measurement Sample exercise: What fraction of a second is a picosecond, ps? 10-12 second Chapt. 1.3

30 Matter; Measurement Common Units: Length and Mass
Length - unit of distance measured in meters Mass - measures the amount of matter in an object in grams Temperature Kelvin Celsius °C = 5/9 (°F -32) K = °C Chapt. 1.3

31 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F Chapt. 1.3

32 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F K = °C = Chapt. 1.3

33 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F K = °C = = K Chapt. 1.3

34 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F K = °C = = K = K Chapt. 1.3

35 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F °C = 5/9 (°F -32) Chapt. 1.3

36 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F °C = 5/9 (°F - 32) -11.5 = 5/9(x - 32) Chapt. 1.3

37 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F °C = 5/9 (°F - 32) -11.5 = 5/9(x - 32) 9(-11.5) = x 5 Chapt. 1.3

38 Matter; Measurement Sample exercise: Ethylene glycol, the major ingredient in antifreeze, freezes at -11.5°C. What is the freezing point in a) K b) °F °C = 5/9 (°F - 32) -11.5 = 5/9(x - 32) 9(-11.5) = x 5 11.3°F = x Chapt. 1.3

39 Matter; Measurement Derived Units: Volume Length x length x length
measured in cm3, which is equal to mL Chapt. 1.3

40 Matter; Measurement Derived Units: Density
amount of mass per unit volume measured in g/cm3, or g/mL Chapt. 1.3

41 Matter; Measurement Sample exercise: A student needs 15.0 g of ethanol (ethyl alcohol) for an experiment. If the density of the alcohol is g/mL, how many milliliters of alcohol are needed? Chapt. 1.3

42 Matter; Measurement Sample exercise: A student needs 15.0 g of ethanol (ethyl alcohol) for an experiment. If the density of the alcohol is g/mL, how many milliliters of alcohol are needed? D = m/V so V = m/D Chapt. 1.3

43 Matter; Measurement Sample exercise: A student needs 15.0 g of ethanol (ethyl alcohol) for an experiment. If the density of the alcohol is g/mL, how many milliliters of alcohol are needed? D = m/V so V = m/D = 15.0 g g/mL Chapt. 1.3

44 Matter; Measurement Sample exercise: A student needs 15.0 g of ethanol (ethyl alcohol) for an experiment. If the density of the alcohol is g/mL, how many milliliters of alcohol are needed? D = m/V so V = m/D = 15.0 g g/mL = 19.0 mL Chapt. 1.3

45 Matter; Uncertainty in Measurement
Precision and Accuracy Precision - how closely individual measurements agree Accuracy- how closely the measurements agree with the true value Significant Figures All measurements are inaccurate intrinsically measured quantities are reported such that the last figure is uncertain Chapt. 1.4

46 Matter; Uncertainty in Measurement
Good Precision Poor Accuracy Good Precision Good Accuracy Poor Precision Poor Accuracy

47 Matter; Uncertainty in Measurement
Determining Significant Figures all non zero digits are significant zeros between nonzero digits are significant zeros to the left of first nonzero digit are not significant zeros at the end of a number and to the right of a decimal point are significant when a number ends in a zero but with no decimal point, the zero may or may not be signigicant (use scientific notation) Chapt. 1.4

48 Matter; Uncertainty in Measurement
Determining Significant Figures 3.573 has 4 significant figures 0.073 has 2 significant figures 3.070 has 4 significant figures 0.003 has 1 significant figures - multiplication and division; result can have no more than the figure with the fewest significant figures - addition and subtraction; result can have the same number of decimal places as the term with the least number of decimal places Chapt. 1.4

49 Matter; Uncertainty in Measurement
Sample exercise: A balance has a precision of g. A sample that weighs about 25 g is weighed on this balance. How many significant figures should be reported for this measurement? Chapt. 1.3

50 Matter; Uncertainty in Measurement
Sample exercise: A balance has a precision of g. A sample that weighs about 25 g is weighed on this balance. How many significant figures should be reported for this measurement? 25.XXX Chapt. 1.3

51 Matter; Uncertainty in Measurement
Sample exercise: A balance has a precision of g. A sample that weighs about 25 g is weighed on this balance. How many significant figures should be reported for this measurement? 25.XXX 5 sig figs Chapt. 1.3

52 Matter; Uncertainty in Measurement
Sample exercise: How many significant figures are in each of the following measurements? A) g B) 2.3 x 104 cm C) m3 Chapt. 1.3

53 Matter; Uncertainty in Measurement
Sample exercise: How many significant figures are in each of the following measurements? A) g 4 sig figs B) 2.3 x 104 cm C) m3 Chapt. 1.3

54 Matter; Uncertainty in Measurement
Sample exercise: How many significant figures are in each of the following measurements? A) g 4 sig figs B) 2.3 x 104 cm 2 sig figs C) m3 Chapt. 1.3

55 Matter; Uncertainty in Measurement
Sample exercise: How many significant figures are in each of the following measurements? A) g 4 sig figs B) 2.3 x 104 cm 2 sig figs C) m3 3 sig figs Chapt. 1.3

56 Matter; Uncertainty in Measurement
Sample exercise: There are exactly m in a mile. How many meters are in a distance of 1.35 mi? Chapt. 1.3

57 Matter; Uncertainty in Measurement
Sample exercise: There are exactly m in a mile. How many meters are in a distance of 1.35 mi? 1.35 mi = mi x m Chapt. 1.3

58 Matter; Uncertainty in Measurement
Sample exercise: There are exactly m in a mile. How many meters are in a distance of 1.35 mi? 1.35 mi = mi x m x = m Chapt. 1.3

59 Matter; Uncertainty in Measurement
Sample exercise: There are exactly m in a mile. How many meters are in a distance of 1.35 mi? 1.35 mi = mi x m 1.35 has 3 sig figs x = m has 7 sig figs is infinitely significant Chapt. 1.3

60 Matter; Uncertainty in Measurement
Sample exercise: There are exactly m in a mile. How many meters are in a distance of 1.35 mi? 1.35 mi = mi x m 1.35 has 3 sig figs x = m has 7 sig figs x = 2170 m is infinitely significant Chapt. 1.3

61 Dimensional Analysis Use Units throughout the calculation (helps “guide” calculation. Should always yield the proper units Uses conversion factors Example; How fast is 50 mph in in/sec.? 50 mi. 1 hour 5280 ft 12 in = in 1 hour 3600 sec. 1 mi. 1 ft sec.

62 Dimensional Analysis Sample exercise: By using a conversion factor from the back inside cover, determine the length in kilometers of a mi automobile race. Chapt. 1.3

63 Dimensional Analysis Sample exercise: By using a conversion factor from the back inside cover, determine the length in kilometers of a mi automobile race. 500.0 mi Chapt. 1.3

64 Dimensional Analysis Sample exercise: By using a conversion factor from the back inside cover, determine the length in kilometers of a mi automobile race. 500.0 mi 1 km mi Chapt. 1.3

65 Dimensional Analysis Sample exercise: By using a conversion factor from the back inside cover, determine the length in kilometers of a mi automobile race. 500.0 mi 1 km = km mi Chapt. 1.3

66 Dimensional Analysis Sample exercise: By using a conversion factor from the back inside cover, determine the length in kilometers of a mi automobile race. 500.0 mi 1 km = km mi * answer can only have 4 sig figs; km Chapt. 1.3

67 Dimensional Analysis Sample exercise: The distance between carbon atoms in a diamond is 154 pm. Convert this distance to millimeters. Chapt. 1.3

68 Dimensional Analysis Sample exercise: The distance between carbon atoms in a diamond is 154 pm. Convert this distance to millimeters. 154 pm Chapt. 1.3

69 Dimensional Analysis Sample exercise: The distance between carbon atoms in a diamond is 154 pm. Convert this distance to millimeters. 154 pm m mm 1012 pm m Chapt. 1.3

70 Dimensional Analysis Sample exercise: The distance between carbon atoms in a diamond is 154 pm. Convert this distance to millimeters. 154 pm m mm = 1.54 x 10-7 mm 1012 pm m Chapt. 1.3

71 Dimensional Analysis Sample exercise: A car travels 28 mi to the gallon of gasoline. How many kilometers per liter will it go? Chapt. 1.3

72 Dimensional Analysis Sample exercise: A car travels 28 mi to the gallon of gasoline. How many kilometers per liter will it go? 28 mi gal Chapt. 1.3

73 Dimensional Analysis Sample exercise: A car travels 28 mi to the gallon of gasoline. How many kilometers per liter will it go? 28 mi km gal mi Chapt. 1.3

74 Dimensional Analysis Sample exercise: A car travels 28 mi to the gallon of gasoline. How many kilometers per liter will it go? 28 mi km gal gal mi L Chapt. 1.3

75 Dimensional Analysis Sample exercise: A car travels 28 mi to the gallon of gasoline. How many kilometers per liter will it go? 28 mi km gal = km gal mi L L Chapt. 1.3

76 Dimensional Analysis Sample exercise: A car travels 28 mi to the gallon of gasoline. How many kilometers per liter will it go? 28 mi km gal = km gal mi L L * 2 sig figs = 12 km L Chapt. 1.3

77 Chapter One; Review Matter: Chemical and Physical Changes
Elements and Compounds Units of Measurement Uncertainty and Significant Figures Precision and Accuracy “Factor Label” Method (Dimensional Analysis)


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