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Hao Zhu Dept. of Electrical & Computer Engineering University of Illinois, Urbana-Champaign ECE 498HZ: Power Distribution System Analysis.

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Presentation on theme: "Hao Zhu Dept. of Electrical & Computer Engineering University of Illinois, Urbana-Champaign ECE 498HZ: Power Distribution System Analysis."— Presentation transcript:

1 Hao Zhu Dept. of Electrical & Computer Engineering University of Illinois, Urbana-Champaign haozhu@illinois.edu ECE 498HZ: Power Distribution System Analysis Chapter 6: Distribution Line Models February 16, 2016

2 Clean Power Plan 2

3 Line Parameters 3

4 Special cases 4

5 Line Model 5

6 Circuit Analysis  At node m  At node n  Voltage diff 6

7 Generalized Line Matrices 7

8 Matrix form 8

9 Additional Line Matrices 9

10 Same to transmission, but 10

11 Example 6.1 11 microSiemens (1e-6)

12 Example 6.1  Calculating generalized matrices 12 Because shunt is too small

13 Example 6.1  Since load voltage is rated and balanced  At node m  At node n 13 Very close to I m Again, because of tiny shunt effects ~ 1.047p.u.

14 Voltage Unbalance  ANSI/NEMA standards  Note that all values are magnitudes  For Example 6.1, 14

15 Modified Line Models 15

16 Three-wire Delta Lines 16 Primitive impedance values No neutral line

17 Neutral and Ground Currents  To recover the neutral line current, recall the neutral transformation  From flow conservation 17

18 Example 6.2  Change Ex 6.1 to that node n is balanced, not the load node m  To solve for node m, compute  Equivalently no shunt 18

19 Example 6.2  Line-to-line voltage  Voltage unbalance  Load complex power 19

20 Example 6.3  Neutral transformation matrix  Neutral current  Ground current 20

21 Approximation using Sequence Matrix  Assuming transposed lines with balanced loads  Corresponding phase impedance matrix  So the voltage diff 21

22 Approximate Line Model  For phase a of node n  In addition, 22

23 Example 6.3 23

24 Example 6.4 24

25 Distribution Network Power Flow 25 ……

26 Forward sweep 26 Node n Node m

27 Backward sweep 27 Node n Node m

28 Iterative Ladder 28

29 Example 6.5  So far we only consider a single line segmant  Given the unbalanced load and source voltage 12.47kV –Phase a: 2500 kVA and PF = 0.9 lagging –Phase b: 2000 kVA and PF = 0.85 lagging –Phase c: 1500 kVA and PF = 0.95 lagging 29


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