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Prof. David R. Jackson ECE Dept. Spring 2016 Notes 10 ECE 6341 1.

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Presentation on theme: "Prof. David R. Jackson ECE Dept. Spring 2016 Notes 10 ECE 6341 1."— Presentation transcript:

1 Prof. David R. Jackson ECE Dept. Spring 2016 Notes 10 ECE 6341 1

2 Dielectric Rod a z This serves as a model for a fiber-optic guide. 2

3 Fiber Optic Guides 3 Two types of fiber-optic guides: 1) Single-mode fiber 2) Multi-mode fiber This fiber carries a single mode (HE 11 ). This requires the fiber diameter to be on the order of a wavelength. It has less loss, dispersion, and signal distortion. It is often used for long-distances (e.g., greater than 1 km). The diameter is typically 8  m. It requires more expensive electro-optic equipment. This fiber has a diameter that is large relative to a wavelength (e.g., 10 wavelengths). It operates on the principle of total internal reflection (critical-angle effect). It can handle more power than the single-mode fiber, but has more dispersion. The diameter is typically 50  m. It is often used for LANs, etc.

4 4 It usually has a yellow jacket. Single-mode Fiber

5 Multi-mode Fiber 5 http://en.wikipedia.org/wiki/Multi-mode_fiber A 1.25 Gbit/s multi-mode fiber

6 Fiber-optic Cable 6 Cable Types : (L to R): Zipcord, Distribution, Loose Tube, Breakout http://www.thefoa.org/tech/ref/basic/cable.html Fibers (single-mode or multi-mode) may be bundled together into a “fiber optic cable” that has one or more fibers. Simplex: single fiber in a cable Duplex: two fibers in a cable

7 7 Single-mode Fiber: Operation HE 11 mode A single mode (HE 11 mode) propagates on the dielectric rod. The mode is similar to the TM 0 mode on a grounded slab. It has a zero cutoff frequency. Fields decay away from the rod

8 8 http://en.wikipedia.org/wiki/Optical_fiber Higher index core region A multimode fiber can be explained using geometrical optics and internal reflection. The “ray” of light is actually a superposition of many waveguide modes (hence the name “multimode”). A laser bouncing down an acrylic rod, illustrating the total internal reflection of light in a multi-mode optical fiber Multi-mode Fiber: Operation

9 Single-mode vs. Multi-mode Fibers 9 Graded index

10 Dielectric Rod Modes are hybrid unless For example, assume TM z : a z 1 0 10 Note: We can have TE 0p, TM 0p modes

11 Dielectric Rod (cont.) At  = a : so Hence, for n > 0 we have (Not true in general!) 11

12 where ( k z is unknown)  < a: Dielectric Rod (cont.) 12 Representation of potentials inside the rod:

13 To see choice of sin/cos, examine the field components (for example E  ): The field E  is assumed (arbitrarily) to vary as sin(n  ) for our choice of potentials. We then have for the field components: Dielectric Rod (cont.) 13

14 where  > a: Note:   0 is interpreted as a positive real number in order to have decay radially in the air region, for a bound (non-leaky) mode. Use Dielectric Rod (cont.) 14 Representation of potentials outside the rod:

15 K n ( x ) = Modified Bessel function of the second kind. Useful identity: Another useful identity: Dielectric Rod (cont.) 15

16 Modified Bessel function of the second kind Dielectric Rod (cont.) 16

17 The modified Bessel function of the first kind grows exponentially, so we don’t want this one. Dielectric Rod (cont.) 17

18 Hence, we choose Dielectric Rod (cont.) 18

19 Summary of potentials: Dielectric Rod (cont.) 19

20 Match E z, H z, E , H  at  = a: Dielectric Rod (cont.) Example: so 20

21 To have a non-trivial solution, we require that Dielectric Rod (cont.) 21 k z = unknown (for a given frequency  )

22 Set Dielectric Rod (cont.) Cutoff frequency: Then 22 Note: This is an open structure, so cutoff means the boundary between proper and improper behavior ( k z = k 0 ). The unknown is now  c.

23 Dominant mode (lowest cutoff frequency): HE 11 (f c = 0) The field shape is somewhat similar to the TE 11 circular waveguide mode. Dielectric Rod (cont.) Note: The notation HE means that the mode is hybrid, and has both E z and H z, although H z is stronger. (For an EH mode, E z would be stronger.) The physical properties of the fields are similar to those of the TM 0 surface wave on a slab (For example, at low frequency the field is loosely bound to the rod.) 23

24 When will the next mode be at cutoff? This determines the upper frequency limit for the single-mode fiber. Dielectric Rod (cont.) 24 Cutoff: The next mode (i.e., with the next lowest cutoff frequency) is the TM 01 mode. The tangential field in the air region at the boundary becomes zero at the cutoff frequency: the rod acts like a circular waveguide with a PEC wall. (Recall: For n = 0, the modes are TM z and TE z.)

25 Dielectric Rod (cont.) 25 TM 01 mode at cutoff: or Hence, to have only the HE 11 mode, we have the following frequency restriction: n 1 = index of refraction of rod

26 A round wire made of conducting material is examined. The wire has a conductivity of . Impedance of Wire 26 a  z We neglect the z variation of the fields inside the wire. (The wire is short compared with a wavelength.) Goal: Determine the impedance per unit length (in the z direction).

27 Inside the wire: Impedance of Wire (cont.) 27 a  z (The field must be finite on the z axis.)

28 Hence, we have Impedance of Wire (cont.) 28 a  z where (skin depth) We can also write the field as

29 Impedance of Wire (cont.) 29 a  z Therefore, we can write Definition of Kelvin functions:

30 Impedance of Wire (cont.) 30 a  z The current flowing in the wire is Hence

31 Impedance of Wire (cont.) 31 a  z The internal impedance per unit length is defined as: Hence, Note: The internal impedance accounts for the internal stored energy and power dissipation.

32 Impedance of Wire (cont.) 32 a  z We also have the following helpful integration identity: where Hence

33 Impedance of Wire (cont.) 33 a  z Hence, we have where

34 Impedance of Wire (cont.) 34 a  z At low frequency ( a <<  ): where At high frequency ( a >>  ):

35 Impedance of Wire (cont.) 35 An extra impedance per unit length Z i is added to the TL model in order to account for the internal impedance of the conductors. R  z C zC z G  z L 0  z Z i  z Transmission Line Model The external inductance per unit length L 0 is calculated assuming perfectly conducting wires. Note: The form of Z i will depend on the shape of the conductors: we have only analyzed the case of a round wire.

36 Impedance of Wire (cont.) 36 For a twin lead (two wires running parallel) we have: Transmission Line Model + - We assume that the wires are far enough apart so that the current is uniform inside each one.


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