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Stoichiometry Notes Part II Multi-Step Problems. From yesterday… Why are mole/mole problems impractical in a laboratory setting? We don’t ever measure.

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Presentation on theme: "Stoichiometry Notes Part II Multi-Step Problems. From yesterday… Why are mole/mole problems impractical in a laboratory setting? We don’t ever measure."— Presentation transcript:

1 Stoichiometry Notes Part II Multi-Step Problems

2 From yesterday… Why are mole/mole problems impractical in a laboratory setting? We don’t ever measure directly in moles!

3 Steps to solve every problem: 1)Write a balanced equation. 2)Put what you have over 1. 3)Convert into moles. 4)Compare using the mole to mole ratio from the equation. 5)Convert into the unit the question asks for.

4 Al + Cl 2  AlCl 3 How many grams of aluminum are needed to produce 22.7g aluminum chloride? Balance the equation first!!!

5 2 Al + 3 Cl 2  2 AlCl 3 How many grams of aluminum are needed to produce 22.7g aluminum chloride?

6 2 Al + 3 Cl 2  2 AlCl 3 How many liters of chlorine gas are needed to react with 23.1g aluminum? 23.1 g Al x 1 mole Al x 3 moles Cl 2 x 22.4 L Cl 2 = 28.7 L Cl 2 27.0 g Al 2 moles Al 1 mole Cl 2

7 How many grams of iron (III) oxide can be produced with 17.2g Fe? Balance the equation first!!! Fe + O 2  Fe 2 O 3

8 How many grams of iron (III) oxide can be produced with 17.2g Fe? 17.2 g Fe x 1 mole Fe x 2 moles Fe 2 O 3 x 159.6 g Fe 2 O 3 = 24.6 g Fe 2 O 3 55.8 g Fe 4 moles Fe 1 mole Fe 2 O 3 4 Fe + 3 O 2  2 Fe 2 O 3

9 How many grams of iron will react with 5.25 liters of O 2 (@STP)? 5.25 L O 2 x 1 mole O 2 x 4 moles Fe x 55.8 g Fe = 17.4 g Fe 22.4 L O 2 3 moles O 2 1 mole Fe


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