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Conversion Stoich. Moles to Quantity Moles of 1 substance are given and you are asked to find the mass, concentration or volume of another.

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Presentation on theme: "Conversion Stoich. Moles to Quantity Moles of 1 substance are given and you are asked to find the mass, concentration or volume of another."— Presentation transcript:

1 Conversion Stoich

2 Moles to Quantity Moles of 1 substance are given and you are asked to find the mass, concentration or volume of another

3 Example Copper metal reacts with an aqueous solution of silver nitrate to produce silver metal and copper (II) nitrate. What mass of silver can be produced by reacting 0.250mol of copper?

4 Step 1: Write a balanced equation for the reaction Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s)

5 Step 2: Determine the given and unknown Given: 0.250mol of Cu(s) Unknown: #g of Ag(s)

6 Step 3: Set up the mole ratio and change moles to grams #g of Ag(s) = 0.250mol Cu(s) x 2Ag x 107.87g 1Cu mol #g = 53.9g of Ag was produced

7 Example 2 Sulfuric acid is neutralized by sodium hydroxide solution. What mass of sodium sulfate can be produced by reacting 0.350mol of NaOH(aq)?

8 H2SO4(aq) + 2NaOH(aq)  Na2SO4(aq) + 2H2O(l) #g of Na2SO4 = 0.350mol NaOH x 1Na2SO4 x 142.05g 1NaOHmol #g of Na2SO4 = 24.9 grams

9 Example 3 When sulfuric acid reacts with sodium hydroxide, sodium sulfate and water are produced. If 40.00mL of H2SO4(aq) reacts with 0.150mol of NaOH, what is the concentration of the acid?

10 H2SO4(aq) + 2NaOH(aq)  2H2O(l) + 1Na2SO4(aq) mol = 0.150mol NaOH x 1Na2SO4 x 1 L 2NaOH 0.040L Na2SO4 mol/L Na2SO4 = 1.875M

11 Quantity to Moles The quantity of one substance such as mass, volume or concentration is given and you are asked to find the moles of another

12 Example How many moles of water vapor can be produced by reacting 78.4L of oxygen gas at STP with sufficient hydrogen gas? *** remember you must get it to moles to do the mole ratio***

13 2H2(g) + O2(g)  2H2O(g) #mol of H2O = 78.4L O2 x mol x 2H2O 22.4L1O2 #mol of H2O = 7.00mol of H2O

14 Example 2 How many moles of zinc are needed to produce 450.00g of zinc chloride by reacting the zinc with an excess of hydrochloric acid? Zn(s) + 2HCl(aq)  ZnCl2(aq) + H2(g)

15 #mol Zn = 450g ZnCl2 x mol x 1Zn 136.28g 1ZnCl2 #mol Zn = 3.302mol of Zn

16 Example 3: If solid sodium chloride is reacted with 26.9mL of 3.00M H2SO4(aq), aqueous solutions of hydrochloric acid and sodium sulfate are formed. How many moles of sodium sulfate are formed? 2NaCl(s) + H2SO4(aq)  2HCl(aq) + Na2SO4(aq)

17 #mol Na2SO4 = 3.00mol x 26.9L x 1 Na2SO4 L 1H2SO4 #mol Na2SO4 = 80.7mol


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