Circular Orbits and Weightlessness © 2015 Pearson Education, Inc.

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Presentation transcript:

Circular Orbits and Weightlessness © 2015 Pearson Education, Inc.

Slide 6-2 Orbital Motion The force of gravity on a projectile is directed toward the center of the earth. © 2015 Pearson Education, Inc.

Slide 6-3 Orbital Motion If the launch speed of a projectile is sufficiently large, there comes a point at which the curve of the trajectory and the curve of the earth are parallel. Such a closed trajectory is called an orbit. An orbiting projectile is in free fall. © 2015 Pearson Education, Inc.

Slide 6-4 Orbital Motion The force of gravity is the force that causes the centripetal acceleration of an orbiting object: An object moving in a circle of radius r at speed v orbit will have this centripetal acceleration if That is, if an object moves parallel to the surface with the speed (This is also the speed at which apparent weightlessness will occur n=mg) © 2015 Pearson Education, Inc.

Slide 6-5 Orbital Motion: A couple of Definitions and Reminders (Very Busy Slide) Apparent Weight: the upward force (normal force) that opposes a supported object from falling (What a scale reads) Object true weight: Force exerted by gravity or mg. Remember: W apparent = Actual Weight except: Object has acceleration with a vertical component (i.e y direction) Some force other than earth’s gravity is acting on the object: Magnetic, buoyant, centripetal or gravitational force of another body Free Fall: A free falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. There are two important motion characteristics that are true of free-falling objects: So objects in orbit…are in free fall and have no apparent weight (normal force =0). If object apparent weight does not equal 0 it will either fly off (n…v> ) or be pulled by gravity (mg>n…v< )

Slide 6-6 Orbital Motion The orbital speed of a projectile just skimming the surface of a smooth, airless earth is We can use v orbit to calculate the period of the satellite’s orbit: © 2015 Pearson Education, Inc.

Slide 6-7 Weightlessness in Orbit Astronauts and their spacecraft are in free fall. © 2015 Pearson Education, Inc.

Slide 6-8 Question 1 Astronauts on the International Space Station are weightless because A.There’s no gravity in outer space. B.The net force on them is zero. C.The centrifugal force balances the gravitational force. D. g is very small, although not zero. E.They are in free fall. © 2015 Pearson Education, Inc.

Slide 6-9 Question 1 Astronauts on the International Space Station are weightless because A.There’s no gravity in outer space. B.The net force on them is zero. C.The centrifugal force balances the gravitational force. D. g is very small, although not zero. E.They are in free fall. © 2015 Pearson Education, Inc.

Slide 6-10 Orbital Motion The force of gravity on a projectile is directed toward the center of the earth. © 2015 Pearson Education, Inc.

Slide 6-11 Orbital Motion If the launch speed of a projectile is sufficiently large, there comes a point at which the curve of the trajectory and the curve of the earth are parallel. Such a closed trajectory is called an orbit. An orbiting projectile is in free fall. The escape velocity from earth is about 25,020 mph (40,270 km/h) © 2015 Pearson Education, Inc.

Slide 6-12 Orbital Motion The force of gravity is the force that causes the centripetal acceleration of an orbiting object: An object moving in a circle of radius r at speed v orbit will have this centripetal acceleration if That is, if an object moves parallel to the surface with the speed © 2015 Pearson Education, Inc.

Slide 6-13 Orbital Motion: A couple of Definitions and Reminders (Very Busy Slide) Apparent Weight: the upward force (normal force) that opposes a supported object from falling (What a scale reads) Object true weight: Force exerted by gravity or mg. Remember: W apparent = Actual Weight except: Object has acceleration with a vertical component (i.e y direction) Some force other than earth’s gravity is acting on the object: Magnetic, buoyant, centripetal or gravitational force of another body Free Fall: A free falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. There are two important motion characteristics that are true of free-falling objects: So objects in orbit…are in free fall and have no apparent weight (normal force =0). If object apparent weight does not equal 0 it will either fly off (n…v> or mg>n…v< ) or be pulled by gravity © 2015 Pearson Education, Inc.

Slide 6-14 Orbital Motion The orbital speed of a projectile just skimming the surface of a smooth, airless earth is We can use v orbit to calculate the period of the satellite’s orbit: © 2015 Pearson Education, Inc.

Slide 6-15 Weightlessness in Orbit Astronauts and their spacecraft are in free fall. © 2015 Pearson Education, Inc.

Slide 6-16 Question 1 Astronauts on the International Space Station are weightless because A.There’s no gravity in outer space. B.The net force on them is zero. C.The centrifugal force balances the gravitational force. D. g is very small, although not zero. E.They are in free fall. © 2015 Pearson Education, Inc.

Slide 6-17 Question 1 Astronauts on the International Space Station are weightless because A.There’s no gravity in outer space. B.The net force on them is zero. C.The centrifugal force balances the gravitational force. D. g is very small, although not zero. E.They are in free fall. © 2015 Pearson Education, Inc.

Newton’s Law of Gravity © 2015 Pearson Education, Inc.

Slide 6-19 Gravity Obeys an Inverse-Square Law Gravity is a universal force that affects all objects in the universe. Newton proposed that the force of gravity has the following properties: 1.The force is inversely proportional to the square of the distance between the objects. 2.The force is directly proportional to the product of the masses of the two objects. © 2015 Pearson Education, Inc.

Slide 6-20 Gravity Obeys an Inverse-Square Law Newton’s law of gravity is an inverse-square law. Doubling the distance between two masses causes the force between them to decrease by a factor of 4. © 2015 Pearson Education, Inc.

Slide 6-21 Question 2: Varying gravitational force The gravitational force between two giant lead spheres is N when the centers of the spheres are 20 m apart. What is the distance between their centers when the gravitational force between them is N? -Gravity is an inverse-square relationship -The distance is = 5.0 m. © 2015 Pearson Education, Inc.

Slide 6-22 Question 3 Gravitational force between two people You are seated in your physics class next to another student 0.60 m away. Estimate the magnitude of the gravitational force between you. Assume that you each have a mass of 65 kg. © 2015 Pearson Education, Inc.

Slide 6-23 Question 3: Gravitational force between two people (cont.) SOLVE The gravitational force is given by: ASSESS The force is quite small, roughly the weight of one hair on your head. This seems reasonable; you don’t normally sense this attractive force! © 2015 Pearson Education, Inc.

Slide 6-24 The force of Planet Y on Planet X is ___ the magnitude of. A.One quarter B.One half C.The same as D.Twice E.Four times Question 4 © 2015 Pearson Education, Inc. 2M2M M Planet XPlanet Y

Slide 6-25 The force of Planet Y on Planet X is ___ the magnitude of. A.One quarter B.One half C.The same as D.Twice E.Four times Question 4 © 2015 Pearson Education, Inc. 2M2M M Planet XPlanet Y Newton’s third law

Slide 6-26 Question 5 The gravitational force between two asteroids is 1,000,000 N. What will the force be if the distance between the asteroids is doubled? A. 250,000 N B. 500,000 N C.1,000,000 N D.2,000,000 N E.4,000,000 N © 2015 Pearson Education, Inc.

Slide 6-27 Question 5 The gravitational force between two asteroids is 1,000,000 N. What will the force be if the distance between the asteroids is doubled? A. 250,000 N B. 500,000 N C.1,000,000 N D.2,000,000 N E.4,000,000 N © 2015 Pearson Education, Inc.

Slide 6-28 If you traveled to another planet, your mass would be the same but your weight would vary. The weight of a mass m on the moon is given by Using Newton’s law of gravity the weight is given by: Since these are two expressions for the same force, they are equal and Gravity on Other Worlds © 2015 Pearson Education, Inc.

Slide 6-29 Gravity on Other Worlds If we use values for the mass and the radius of the moon, we compute g moon = 1.62 m/s 2. A 70-kg astronaut wearing an 80-kg spacesuit would weigh more than 330 lb on the earth but only 54 lb on the moon. © 2015 Pearson Education, Inc.

Slide 6-30 Question 7 Planet X has free-fall acceleration 8 m/s 2 at the surface. Planet Y has twice the mass and twice the radius of planet X. On Planet Y A. g = 2 m/s 2 B. g = 4 m/s 2 C. g = 8 m/s 2 D. g = 16 m/s 2 E. g = 32 m/s 2 © 2015 Pearson Education, Inc.

Slide 6-31 Question 7 Planet X has free-fall acceleration 8 m/s 2 at the surface. Planet Y has twice the mass and twice the radius of planet X. On Planet Y A. g = 2 m/s 2 B. g = 4 m/s 2 C. g = 8 m/s 2 D. g = 16 m/s 2 E. g = 32 m/s 2 © 2015 Pearson Education, Inc.

Slide 6-32 Question 8 A 60-kg person stands on each of the following planets. On which planet is his or her weight the greatest? © 2015 Pearson Education, Inc.

Slide 6-33 Question 8 A 60-kg person stands on each of the following planets. On which planet is his or her weight the greatest? © 2015 Pearson Education, Inc. A

Slide 6-34 Question 9 Finding the speed to orbit Deimos Mars has two moons, each much smaller than the earth’s moon. The smaller of these two bodies, Deimos, isn’t quite spherical, but we can model it as a sphere of radius 6.3 km. Its mass is 1.8 × kg. At what speed would a projectile move in a very low orbit around Deimos? © 2015 Pearson Education, Inc.

Slide 6-35 Question 9: Finding the speed to orbit Deimos (cont.) SOLVE The free-fall acceleration at the surface of Deimos is small: © 2015 Pearson Education, Inc.

Slide 6-36 Question 9: Finding the speed to orbit Deimos (cont.) Given this, we can use Equation 6.13 to calculate the orbital speed: This is quite slow. With a good jump, you could easily launch yourself into an orbit around Deimos! © 2015 Pearson Education, Inc.

Slide 6-37 Example Problem A typical bowling ball is spherical, weighs 16 pounds, and has a diameter of 8.5 in. Suppose two bowling balls are right next to each other in the rack. What is the gravitational force between the two—magnitude and direction? © 2015 Pearson Education, Inc. Answer: The gravitational force between the two balls is directed toward the center of each ball. The force is given by Newton’s law of gravity. The mass of each ball is 7.3 kg and the separation between the two balls is equal to the diameter of one ball or 8.5 inches = 0.22 m. The force on each ball is thus 2*10^(-8) N.

Gravity and Orbits © 2015 Pearson Education, Inc.

Slide 6-39 Gravity and Orbits Newton’s second law tells us that F M on m = ma, where F M on m is the gravitational force of the large body on the satellite and a is the satellite’s acceleration. Because it’s moving in a circular orbit, Newton’s second law gives © 2015 Pearson Education, Inc.

Slide 6-40 Gravity and Orbits A satellite must have this specific speed in order to maintain a circular orbit of radius r about the larger mass M. © 2015 Pearson Education, Inc.

Slide 6-41 Gravity and Orbits For a planet orbiting the sun, the period T is the time to complete one full orbit. The relationship among speed, radius, and period is the same as for any circular motion: v = 2πr/T Combining this with the value of v for a circular orbit from Equation 6.21 gives If we square both sides and rearrange, we find the period of a satellite: © 2015 Pearson Education, Inc. This also called “Keplers 3 rd Law”.

Slide 6-42 Question 10 Two satellites have circular orbits with the same radius. Which has a higher speed? A.The one with more mass. B.The one with less mass. C.They have the same speed. © 2015 Pearson Education, Inc.

Slide 6-43 Question 11 Two identical satellites have different circular orbits. Which has a higher speed? A.The one in the larger orbit B.The one in the smaller orbit C.They have the same speed. © 2015 Pearson Education, Inc.

Slide 6-44 Question 12 A satellite orbits the earth. A Space Shuttle crew is sent to boost the satellite into a higher orbit. Which of these quantities increases? A.Speed B.Angular speed C.Period D.Centripetal acceleration E.Gravitational force of the earth © 2015 Pearson Education, Inc.

Slide 6-45 Question 10 Two satellites have circular orbits with the same radius. Which has a higher speed? A.The one with more mass. B.The one with less mass. C.They have the same speed. © 2015 Pearson Education, Inc.

Slide 6-46 Question 11 Two identical satellites have different circular orbits. Which has a higher speed? A.The one in the larger orbit B.The one in the smaller orbit C.They have the same speed. © 2015 Pearson Education, Inc.

Slide 6-47 Question 12 A satellite orbits the earth. A Space Shuttle crew is sent to boost the satellite into a higher orbit. Which of these quantities increases? A.Speed B.Angular speed C.Period D.Centripetal acceleration E.Gravitational force of the earth © 2015 Pearson Education, Inc.

Slide 6-48 Qeustion13: Locating a geostationary satellite Communication satellites appear to “hover” over one point on the earth’s equator. A satellite that appears to remain stationary as the earth rotates is said to be in a geostationary orbit. What is the radius of the orbit of such a satellite? H INT : For the satellite to remain stationary with respect to the earth, the satellite’s orbital period must be 24 hours; in seconds this is T = 8.64 × 10 4 s. Mass of the earth M e =5.98x10 24 kg G=6.67 x N-m 2 /kg And:

Slide 6-49 Example 6.15 Locating a geostationary satellite (cont.) Rearranging. The mass at the center of the orbit is the earth: © 2015 Pearson Education, Inc.

Slide 6-50 Example 6.15 Locating a geostationary satellite (cont.) ASSESS This is a high orbit, and the radius is about 7 times the radius of the earth. (26,221 miles) Radius of the International Space Station’s orbit is only about 5% larger than that of the earth. © 2015 Pearson Education, Inc.

Slide 6-51 Gravity on a Grand Scale No matter how far apart two objects may be, there is a gravitational attraction between them. Galaxies are held together by gravity. All of the stars in a galaxy are different distances from the galaxy’s center, and so orbit with different periods. © 2015 Pearson Education, Inc.

Slide 6-52 Summary: General Principles © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-53 Summary: General Principles © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-54 Summary: Important Concepts © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-55 Summary: Important Concepts © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-56 Summary: Applications © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-57 Summary: Applications © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-58 Summary © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-59 Summary © 2015 Pearson Education, Inc. Text: p. 182

Slide 6-60 Summary © 2015 Pearson Education, Inc. Text: p. 182