Exponential Notation Using Powers of 10

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Exponential Notation Using Powers of 10 Magnitude Exponential Notation Using Powers of 10

Warm-up Entry Ticket Rewrite as fractions and prove the identity.

Magnitude demands an understanding of the integer powers of 10. What does it mean to say that 10n for large positive integers n are big numbers? What does it mean to say that 10−n for large positive integers n are small numbers? Fact 1:  The numbers 10n for arbitrarily large positive integers n are big numbers; given a number M   (no matter how big it is), there is a power of 10 that exceeds M. Fact 2:  The numbers 10−n  for arbitrarily large positive integers n  are small numbers; given a positive number S   (no matter how small it is), there is a (negative) power of 10 that is smaller than S.  

Examples 1 & 2 (Fact 1) Example 1:  Let M  be the world population as of March 23, 2013.  Approximately, M = 7,073,981,143  It has 10 digits and is, therefore, smaller than any whole number with 11 digits, such as 10,000,000,000.  But 10,000,000,000 = 10 10, so M < 1010     (i.e., the 10th power of 10 exceeds this M).

Examples 1 & 2 (Fact 1) Example 2:  Let M  be the US national debt on March 23, 2013.  M = 16,755,133,009,522  to the nearest dollar.  It has 14 digits.  The largest 14-digit number is 99,999,999,999,999. Therefore, M < 99,999,999,999,999 < 100,000,000,000,000 = 1014     That is, the 14th power of 10 exceeds M  .

Just Do it! Exercise 1 Let M = 993,456,789,098,765 Find the smallest power of 10 that will exceed M. Exercise 2 Let M = 78,491 899 987 Find the smallest power of 10 that will exceed M Find the smallest power of 10 that will exceed M.

Scientific Notation Quiz Write in scientific notation. 1) 34.5 2) 564,200 3) .0076 4) 51.3 • 103 Write in standard form. 5) 2.654 • 10-3 6) 99 • 104 7) 9.65 • 105 8) 6.14 • 10-5

103 10-4 101 100 10-1 Number line example problem #1

Example 3: Case 1 Case 1: Let M be a positive integer with n digits. As we know, the integer 99⋯99   (with n 9s) is ≥ M.  Therefore, 100⋯00   (with n 0s) exceeds M   Since 10n = 100⋯00   (with n 0s), we have 10n  > M Symbolically, M < 99⋯99  < 100⋯0  = 10n   n times n times Therefore, for an n - digit positive integer M, the n-th power of 10 (i.e., 10 n) always exceeds M  .

Case 2 In Case 1, M was a positive integer. For this case, let M be a non-integer.  We know M must lie between two consecutive points on a number line (i.e., there is some integer N  so that M lies between N and N + 1). In other words, N < M < N + 1  (The number 45,572.384 is between 45,572 and 45,573.) The positive integer 𝑁+1: According to the reasoning above, there is a positive integer 𝑛 so that 10𝑛 > 𝑁+1. Since 𝑁+1 > 𝑀, we have 10𝑛 > 𝑀 Consequently, for this number 𝑀, 10𝑛 exceeds it. We have now shown why Fact 1 is correct.

Exercise 3 𝑴=5,678.9 < 5,679 < 10,000 = 104 Let 𝑴 be a positive integer. Explain how to find the smallest power of 𝟏0 that exceeds it. Let m = 5,678.9 If 𝑴 is a positive integer, then the power of 10 that exceeds it will be equal to the number of digits in 𝑴. For example, if 𝑴 were a 10-digit number, then 𝟏𝟎10 would exceed 𝑴. If 𝑴 is a positive number, but not an integer, then the power of 10 that would exceed it would be the same power of 10 that would exceed the integer to the right of 𝑴 on a number line. For example, if 𝑴= 5,678.9, the integer to the right of 𝑴 is 5,679. Then based on the first explanation, 𝟏04 exceeds both this integer and 𝑴; this is because 𝑴=5,678.9 < 5,679 < 10,000 = 104

Example 4 The average ant weighs about 0.0003 grams. This number is less than 1 and is very small. Express this number as a power of 10. We know that 100 = 1, so we must need a power of 10 that is less than zero. Based on our knowledge of decimals and fractions, we can rewrite the weight of the ant as 3 10,000 , which is the same as 3 10 4 Our work with the laws of exponents taught us that 3 10 4 = 3 • 1 10 4 = 3 • 10-4 Therefore, we can express the weight of an average ant as 3 • 10−4 grams.

Example 4 (continued) The mass of a neutron is 0.000 000 000 000 000 000 000 000 001 6749 kilograms We already know that 10−4 takes us to the place value four digits to the right of the decimal point (ten-thousandths). We need a power of 10 that would take us 27 places to the right of the decimal, which means that we can represent the simplified mass of a neutron as 10−27. Numbers with a value less than 1 but greater than 0 can be expressed using a negative power of 10. The closer a number is to zero, the smaller the power of 10 that will be needed to express it.

Exercise 4 The chance of you having the same DNA as another person (other than an identical twin) is approximately 𝟏 in 10 trillion (one trillion is a 𝟏𝟏 followed by 12 zeros). Given the fraction, express this very small number using a negative power of 10. 𝟏 𝟏𝟎,𝟎𝟎𝟎,𝟎𝟎𝟎,𝟎𝟎𝟎,𝟎𝟎𝟎 =

Exercise 5 The chance of winning a big lottery prize is about 10-8, and the chance of being struck by lightning in the U.S. in any given year is about 𝟎.𝟎𝟎𝟎𝟎01. Which do you have a greater chance of experiencing? Explain.

Exercise 6 There are about 𝟏00 million smartphones in the U.S. Your teacher has one smartphone. What share of U.S. smartphones does your teacher have? Express your answer using a negative power of 10.

Exit #1 & 2

Summary No matter what number is given, we can find the smallest power of 10 that exceeds that number. Very large numbers have a positive power of 10 We can use negative powers of 10 to represent very small numbers that are less than one, but greater than zero.