Stoichiometry Introduction to laws in chemistry 1/28/2016Dr Seemal Jelani Chem-1001.

Slides:



Advertisements
Similar presentations
Stoichiometry AP Chemistry Mr. Martin. Topics Law of Conservation of Matter Balancing Chem Eq Mass Relationships in rxn’s Limiting Reagents Theoretical,
Advertisements

Chemical Equations Chemical Reaction: Interaction between substances that results in one or more new substances being produced Example: hydrogen + oxygen.
Calculations with Chemical Formulas and Equations
Chemical Stoichiometry
What is a reactant? What is a product?.
Stoichiometry of Chemical Equations and Formulas.
Section Percent Composition and Chemical Formulas
Chemical Formulas & Equations 8 th Grade Science 2010 H 2 O NaCl CO 2 2H 2 + O 2 = 2H 2 O.
% = ( portion / total ) 100 PERCENTAGE CALCULATIONS % = ( portion / total ) 100 u What is the percent of salt in a saltwater solution if g of sodium.
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed.
 Apply “Law of Conservation” to chemical equations What is stoichiometry?
Percent Composition, Empirical Formulas, Molecular Formulas.
Percentage Composition
Percent Composition, Empirical Formulas, Molecular Formulas.
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Mass Conservation in Chemical Reactions Mass and atoms are conserved in every chemical reaction. Molecules, formula units, moles and volumes are not always.
CHAPTER 3b Stoichiometry.
Lavoisier: The Law of Conservation of Mass
Chemical Reactions and Stoichiometry
CHEMISTRY The Central Science 9th Edition
Ch. 3 Stoichiometry: Calculations with Chemical Formulas.
Conservation of Mass (again) I think it must be important? I think it must be important? Lavoisier- observed that the total mass of a substance present.
Chapter 3 Stoichiometry
LAW OF DEFINITE PROPORTIONS
Stoichiopardy Holy Moley Do the 2 or 3 step Random Limit my Percent Q $100 Q $200 Q $300 Q $400 Q $500 Q $100 Q $200 Q $300 Q $400 Q $500 Final Chempardy.
Stoichiometry Jeopardy Percen t Yield Limiting Reactan ts “Stoiche d” About Chemist ry Q $100 Q $200 Q $300 Q $400 Q $ Q $100 Q $200 Q $300 Q $400.
Chapter 12 Stoichiometry. What is Stoichiometry? Stoichiometry is at the heart of the production of many things you use in your daily life. Soap, tires,
Stoichiometry Calculations with Chemical Formulas and Equations.
Early Early Atomic ideas 400 BC, Democritus – said world was made up of two things air and a basic particle called an atom. Atom was the smallest piece.
Prentice Hall © 2003Chapter 3 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations FAYETTEVILLE STATE UNIVERSITY COLLEGE OF BASIC.
Lab Questions Mole Conversions Vocabulary Multiple-Step.
Definite Proportions, Multiple Proportions and Atomic Theory
Chapter 12 Review “Stoichiometry”
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed.
UNIT FOUR UNIT FOUR Stoichiometry: Calculations with Chemical Formulas and Equations CHEMISTRY The Central Science 9th Edition.
Pure Substances Elements
Daily Science (Sept 18) List an example of a physical property and tell why it is a physical property List a chemical property and tell why it is a chemical.
STAAR Ladder to Success Rung 8. How do chemists define a mole? Example #1: A sample consists of 6.85 x atoms of carbon. How many moles does the.
Percent Composition. Percent Composition – the percentage by mass of each element in a compound Percent = _______ Part Whole x 100% Percent composition.
Chemical Reactions Law of Conservation of Mass Balancing Chemical Equations.
Changes In Matter. Physical Change ◦When a substance undergoes changes that result in a dramatically different appearance but same chemical composition.
Investigating Chemical Reactions!
Agenda: 3/27 Objective: to predict products in a chemical reaction Warm-up: Formative Assessment Chemical Reactions.
John A. Schreifels Chem Chapter 3 Calculations involving Chemical Formulae and Equations.
Stoichiometry! The heart of chemistry. The Mole The mole is the SI unit chemists use to represent an amount of substance. 1 mole of any substance = 6.02.
Chapter 7 Reactions. Chemical Changes Substances react and form a new substance. Reactants go in. Products come out. Reactants Products Represented by.
Prentice Hall © 2003Chapter 3 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations CHEMISTRY The Central Science 9th Edition David.
Yield Noadswood Science, Yield Monday, January 25, 2016  To be able to calculate the yield from chemical reactions.
Stoichiometry Introduction to Stoichiometry. Stoichiometry  Objectives  Define stoichiometry  Describe the importance of the mole ratio in stoichiometric.
LAW OF DEFINITE PROPORTIONS In a compound, the ratios by mass of the elements in that compound are fixed independent of the origins or preparation of that.
Chemical Equations. Chemical Reactions - OVERVIEW change that occurs when atoms rearrange themselves Can absorb or release energy  Heat  Light  Sound.
Describing Chemical Reactions
Percent Composition, Empirical Formulas, Molecular Formulas
Prentice Hall © 2003Chapter 3 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations CHEMISTRY The Central Science 9th Edition.
Law of Conservation of Matter The Law of Conservation of Matter states that matter can neither be created nor destroyed.The Law of Conservation of Matter.
Chemical Reaction A process in which one or more substances are converted into new substances with different physical and chemical properties.
Warm Up Name the two kinds of mixtures List three different separation techniques Is iron rusting a chemical or physical change? If 2g of potassium (K)
Stoichiometry. The study of quantitative relationships between amounts of reactants used and products formed by a chemical reaction is called Stoichiometry.
Stoichiometry Introduction.
CHEMISTRY The Central Science 9th Edition
Law of Conservation of Matter
Stoichiometry Review.
Chapter 7 Reactions.
Introduction to laws in chemistry
Introduction to laws in chemistry
Chapter 9 Key Terms Mole Molar Mass Avogadro's Number Percent Composition Stoichiometry Limiting Reactant Excess Reactant Actual Yield Theoretical Yield.
CHEMISTRY The Central Science 9th Edition
Presentation transcript:

Stoichiometry Introduction to laws in chemistry 1/28/2016Dr Seemal Jelani Chem-1001

Lavoisier: The Law of Conservation of Mass INTRODUCTION 1/28/2016Dr Seemal Jelani Chem-1002

What Do You See? n Look closely! n What is its purpose? n When the pans are both at the same height, what does that mean if you have masses on both pans? n Keep this in mind as we continue 1/28/2016Dr Seemal Jelani Chem-1003

n LCM can neither be created nor destroyed n Matter is converted from one kind to another during a chemical reaction n Atoms are neither created nor destroyed during chemical change 1/28/2016Dr Seemal Jelani Chem-1004

n Chemical Reactions involve a rearrangement of atoms into different combinations 1/28/2016Dr Seemal Jelani Chem-1005

Lavoisier: The Law of Conservation of Mass Early 1700’s Lavoisier: Law of Conservation of Mass During a chemical change, matter is neither created nor destroyed. 1/28/20166Dr Seemal Jelani Chem-100

LAW OF CONSERVATION OF MASS n In every chemical operation an equal quantity of matter exists before and after the operation n That is, the amount of matter before a reaction must equal the amount of matter after a reaction n No matter is lost. The total mass of reactants = total mass of products 1/28/20167Dr Seemal Jelani Chem-100

Conclusion n Matter is neither created nor destroyed during a chemical reactions but changes from one form to another 1/28/2016Dr Seemal Jelani Chem-1008

LAW OF CONSERVATION OF MASS n When g of magnesium was heated in air, g of magnesium oxide (MgO) was produced. a) what is the mass of oxygen needed to produce g MgO? 1/28/20169Dr Seemal Jelani Chem-100

Using the LCM: Total mass reactants = total mass products mass of Mg + mass O = mass of MgO g Mg + mass O = g MgO g O mass O = g = g O 1/28/2016Dr Seemal Jelani Chem-10010

n 1799, Proust: Law of Definite Proportions u A compound always contains the same elements in certain definite proportions. Proust: The Law of Definite Proportions 1/28/201611Dr Seemal Jelani Chem-100

Water n Chemical analysis revealed that as long as it is pure i.e. its composition is always one mole of oxygen to two moles of hydrogen 1/28/2016Dr Seemal Jelani Chem-10012

LAW OF DEFINITE PROPORTIONS In a compound, the ratios by mass of the elements in that compound are fixed independent of the origins or preparation of that compound 1/28/201613Dr Seemal Jelani Chem-100

n CaCO 3 n NaOH n H 2 SO 4 n KMNO 4 n NH 3 1/28/2016Dr Seemal Jelani Chem-10014

1/28/2016Dr Seemal Jelani Chem A compound is unique because of the specific arrangement and weights of the elements which make up that compound

1/28/2016Dr Seemal Jelani Chem That is, elements combine in whole numbers Also it is not possible to have a compound with portion an atom.

1/28/201617Dr Seemal Jelani Chem-100

LAW OF DEFINITE PROPORTIONS n Elements combine in specific ratios to form compounds n Use the Generic equation for percent: % = ( portion / total ) 100 % = ( portion / total ) 100 1/28/201618Dr Seemal Jelani Chem-100

What is the experimental percent of oxygen in CO 2 if 42.0 g of carbon reacted completely with g of oxygen? 1/28/2016Dr Seemal Jelani Chem-10019

% O = (mass of O / mass of CO 2 ) 100 % O= [112.0 g O / (42.0 g g) CO 2 ] % O = 72.7% O 1/28/2016Dr Seemal Jelani Chem-10020

2 What is the theoretical percent of aluminum in aluminum oxide? % Al = (Atomic mass of Al / Formula mass of Al 2 O 3 ) % % Al = (54 amu / 102 amu) 100 = 52.9% 3. What is the percent composition of sodium chloride? % Na = 39.3% % Cl = 60.7% % Na = 39.3% % Cl = 60.7% 1/28/2016Dr Seemal Jelani Chem-10021

Conclusion n All pure samples of a particular compound contain similar elements combined in the same proportion by mass 1/28/2016Dr Seemal Jelani Chem-10022

LAW OF MULTIPLE PROPORTIONS When two elements form a series of compounds, the masses of the one element that combine with a fixed mass of the other element stand to one another in the ratio of small integers. Iron oxide exists in different ratios with different properties FeO and Fe 2 O 3 FeO and Fe 2 O 3 1/28/201623Dr Seemal Jelani Chem-100

n If two elements A and B, combine to form more than one chemical compound, then the various masses of one element, A which combine separately with a fixed mass of the other element, B are in a simple multiple ratio 1/28/2016Dr Seemal Jelani Chem-10024

Examples n Copper and oxygen combine to give black copper(II) oxide, CuO and red copper(I) oxide Cu 2 O n Iron and oxygen combine to give brown iron(II), Fe 2 O 3 and black iron(II) oxide, FeO 1/28/2016Dr Seemal Jelani Chem-10025

Law of conservation of mass & Law of definite proportions n When g of magnesium was heated in air, g of magnesium oxide (MgO) was produced. b) what is the percent of Mg in MgO? % Mg = (mass Mg / Mass MgO) 100 = (0.0976g / g) % = 60.3 % 1/28/201626Dr Seemal Jelani Chem-100

Using only LDP, what mass of oxygen was needed to combine with the magnesium? % O = 100% MgO % Mg = 39.7% O % O = (mass O / mass MgO) % = (mass O / g) g O mass O = ( g) = g O Same as using the LCM!! 1/28/2016Dr Seemal Jelani Chem-10027

PRACTICE PROBLEMS Practicing Law of conservation of mass: ________1. Aluminum metal combines with oxygen to produce aluminum oxide. If 141.0g of aluminum yields g of aluminum oxide, how many grams of oxygen were needed? ________2. Sodium metal reacts with chlorine gas to produce the salt, sodium chloride. If 15.0 g of chlorine yields 26.5 g of salt, how much sodium metal is needed? Practicing the law of definite proportions: ________3. What is the experimental percent of oxygen in a copper oxide if 10.0 g of copper reacted completely with 2.52 g of oxygen? _______ 4. Based on question #1, what is the experimental percent composition of aluminum oxide? _______ 5. Calculate the theoretical percent composition for aluminum chloride and sodium oxide. 1/28/201628Dr Seemal Jelani Chem-100

PRACTICE PROBLEMS Practicing percents: ________1. Pure gold is too soft a metal for many uses, so it is alloyed to give it more mechanical strength. One particular alloy is made by mixing g of gold, 3.81 grams of silver, and 5.91 g of copper. What is the percent of gold in this mixture? ________2. If 255 g of a meat sample contains 21.9 g of fat, what percentage of fat is present? Using the LAWS: ________3. How many grams of CuO can be obtained from 1.80 g of copper (use the theoretical percent composition)? 4. When aluminum combines with bromine gas, they produce the substance aluminum bromide, AlBr 3. Write a chemical equation describing this reaction. _______ If g of aluminum bromide is formed from 5.75 g of aluminum, how many grams of bromine was needed? 75.0% 8.6% 2.25 g 2Al + 3Br 2  2AlBr g 1/28/201629Dr Seemal Jelani Chem-100