6.4 Application of Linear Systems

Slides:



Advertisements
Similar presentations
Warm-Up Tyler is catering a banquet for 250 people. Each person will be served either a chicken dish that costs $5 each or a beef dish that costs $7.
Advertisements

Section 6.4 Applications of Linear System
Unit 2: Solving Systems of Equations
7.2, 7.3 Solving by Substitution and Elimination
Solve Linear Systems by Substitution
Section 7-4: Applications of Linear Systems
3.5 Solving Systems of Equations in Three Variables
Part 2.  Review…  Solve the following system by elimination:  x + 2y = 1 5x – 4y = -23  (2)x + (2)2y = 2(1)  2x + 4y = 2 5x – 4y = -23  7x = -21.
Warm Up #4 1. Evaluate –3x – 5y for x = –3 and y = 4. –11 ANSWER
Chapter 6.1 Common Core – A.REI.6 Solve systems of linear equations exactly and approximately, focusing on pairs of liner equations in two variables. Objectives.
7.1 SOLVING SYSTEMS BY GRAPHING The students will be able to: Identify solutions of linear equations in two variables. Solve systems of linear equations.
Solving Linear Equations
Graphing Systems of Equations Graph of a System Intersecting lines- intersect at one point One solution Same Line- always are on top of each other,
Chapter 6.  Pg. 364 – 369  Obj: Learn how to solve systems of equations by graphing and analyze special systems.  Content Standard: A.REI.6.
Substitution. There are 3 different ways to solve linear equations: 1. Substitution 2. Elimination 3. Graphing We will focus on a new one each day. Today.
6-5 Applying Systems of Linear Equation
Applications of Systems of Equations Lesson 6-4 Day 1 Nov. 7, 2014.
3-D Systems Yay!. Review of Linear Systems Solve by substitution or elimination 1. x +2y = 11 2x + 3y = x + 4y = -1 2x + 5y = 4.
Unit 2: Solving Systems of Equations Key Ideas. Summary of Methods 1)Substitution: Requires that one of the variables be isolated on one side of the equation.
 Solve one of the equations for one of the variables.  Isolate one of the variables in one of the equations.  Choose whichever seems easiest.  Substitute.
Solve by using the ELIMINATION method The goal is to eliminate one of the variables by performing multiplication on the equations. Multiplication is not.
Substitution Method: 1. Solve the following system of equations by substitution. Step 1 is already completed. Step 2:Substitute x+3 into 2 nd equation.
Warm up 12/6 or 7 1) Write the equation of a line that is parallel to y = -3x –5 and goes through the point (6,10). 2) Write the equation of a line that.
Chapter 4 Section 4.1 Solving Systems of Equations in Two Variables.
Lesson 6-4 Warm-Up.
Lesson 7.4A Solving Linear Systems Using Elimination.
SECONDARY ONE 6.1b Solving Linear Systems by Graphing.
Solving Linear Systems by Substitution
6.2 Solve a System by Using Linear Combinations
5-5A Determine the Best Method Algebra 1 Glencoe McGraw-HillLinda Stamper.
SYSTEMS OF EQUATIONS. SYSTEM OF EQUATIONS -Two or more linear equations involving the same variable.
System of Equations Solve by Substitution. A System of Equations:  Consists of two linear equations  We want to find out information about the two lines:
Notes 6.5, Date__________ (Substitution). To solve using Substitution: 1.Solve one equation for one variable (choose the variable with a coefficient of.
OBJ: Solve Linear systems graphically & algebraically Do Now: Solve GRAPHICALLY 1) y = 2x – 4 y = x - 1 Do Now: Solve ALGEBRAICALLY *Substitution OR Linear.
Algebra 1 Foundations, pg 407  Students will be able to choose the best method for solving a system of linear equations.
6-4: Applications of Linear Systems Algebra 1. Solving a System Graphing: When you want a __________ display of when you want to estimate the solution.
Applications of Linear Systems Objective: To choose the best method for solving a system of linear equations.
Ch. 7 – Matrices and Systems of Equations Elimination.
20 Solving Equations To solve ONE step equations you must use the INVERSE OPERATION. OPPOSITE OperationInverse Operation Addition Multiplication EX: V.
6.1 Solving by Graphing: Remember: To graph a line we use the slope intercept form: y = mx +b STARING POINT (The point where it crosses the y-axis)
6.3 Solving Systems of Linear Equations by the Addition Method
Ch. 7 – Matrices and Systems of Equations
Systems of Equations: Substitution
Solving Systems of Linear Equations
Solving Systems of Linear Equations in 3 Variables.
3.4 Solving Systems with 3 variables
Warm-Up Graph Solve for y: Graph line #2.
Algebra 1 Section 7.3 Solve linear systems by linear combinations
Homework Review: Sect 6.4 # 8 – 18 even
Bellwork Solve using any method.
Solving Systems of Equations
Solving Linear Systems Algebraically
Solve a system of linear equation in two variables
Lesson 7-4 part 3 Solving Systems by Elimination
Solve Systems of Equations by Elimination
Lesson 7-4 part 2 Solving Systems by Elimination
3.2a – Solving Systems algebraically
Lesson 7-4 part 3 Solving Systems by Elimination
Another method for solving systems of linear equations
Solving Systems of Equation by Substitution
Solve Linear Systems by Substitution
7.4 Applications of Linear Systems
Solving systems using substitution
Solving Systems of Linear Equations in 3 Variables.
Systems of Equations.
Systems of Equations Solve by Graphing.
Warm Up Check to see if the point is a solution for the
Section 1 – Solving Systems of Equations in Two Variables
6-3 Solving Systems Using Elimination (Combination)
Solving Systems of Linear Equations by Elimination
Presentation transcript:

6.4 Application of Linear Systems I can choose the best method for solving a system of linear equations

When to Use Graphing: When you want a visual display of the equations, or when you want to estimate a solution. Substitution: When one equation is already solved for one of the variables, or when it is easy to solve for one of the variables. Elimination: When the coefficients of one variable are the same or opposites, or when it is not convenient to use graphing or substitution.

Modeling Problems A break-even point is where a business’ expenses equal its income Ex:

Practice A fashion designer makes and sells hats. The material for each hat costs $5.50 and the hats sell for $12.50 each. If the designer spends $1400 on advertising, how many hats must be sold for the designer to break even? Let x = # of hats and y = amount of money Expenses: y = 5.50x + 1400 Income: y = 12.50x Use substitution: 12.50x = 5.50x +1400 7x = 1400 x = 200 After selling 200 hats

Constraints and Viable Solutions The local zoo is filling two water tanks for the elephant exhibit. One has 50 gallons in it and is being filled at a rate of 10 gal/h while the other has 29 gallons and is being filled at a rate of 3 gal/h when will they have the same amount? Let x = # of hours and y = # of gallons 1st tank: y = 10x + 50 2nd tank: y = 3x + 29 Substitute: 10x + 50 = 3x + 29 7x = -21 x = -3 Since x is the number of hours and the solution is negative, we know the tanks will never have the same amount.

Wind or Current Tailwind: air speed + wind speed = ground speed Headwind: air speed – wind speed = ground speed Ex: LA to Charlotte: a + w = 550 Charlotte to LA: a – w = 495 Use Elimination: 2a = 1045 a = 522.5 mi/h Plug a in to find w = 27.5 mi/h

Assignment P.390 odds #7-25