Graphing Parabolas Using the Vertex Axis of Symmetry & y-Intercept By: Jeffrey Bivin Lake Zurich High School

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Presentation transcript:

Graphing Parabolas Using the Vertex Axis of Symmetry & y-Intercept By: Jeffrey Bivin Lake Zurich High School

Graphing Parabolas y = x 2 + 4x - 7 With your graphing calculator, graph each of the following quadratic equations and identify the vertex and axis of symmetry. y = 2x x + 4 y = -3x 2 + 5x + 9

Graph the following parabola y = x 2 + 4x - 7 axis of symmetry: vertex: y-intercept:

Graph the following parabola y = 2x x + 4 axis of symmetry: vertex: y-intercept:

Graph the following parabola y = -3x 2 + 5x + 9 axis of symmetry: vertex: y-intercept:

Graphing Parabolas y = x 2 + 4x - 7 Now look at the coefficients of the equation and the value of the axis of symmetry – especially a and b y = ax 2 + bx + c y = 2x x + 4 y = -3x 2 + 5x + 9

Graphing Parabolas y = ax 2 + bx + c Vertex: Axis of symmetry:

Graph the following parabola y = x 2 + 4x - 7 axis of symmetry: vertex: y-intercept:

Graph the following parabola y = 2x x + 4 axis of symmetry: vertex: y-intercept:

Graph the following parabola y = -3x 2 + 5x + 9 axis of symmetry: vertex: y-intercept: Why did this parabola open downward instead of upward as did the previous two?

Graph the following parabola y = x 2 + 6x - 8 Axis of symmetry: Vertex: y-intercept:

Graph the following parabola y = -2x 2 + 7x + 12 Axis of symmetry: Vertex: y-intercept:

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