4/18/2005EE5621 EE562 ARTIFICIAL INTELLIGENCE FOR ENGINEERS Lecture 5, 4/18/2005 University of Washington, Department of Electrical Engineering Spring.

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4/18/2005EE5621 EE562 ARTIFICIAL INTELLIGENCE FOR ENGINEERS Lecture 5, 4/18/2005 University of Washington, Department of Electrical Engineering Spring 2005 Instructor: Professor Jeff A. Bilmes

4/18/2005EE5622 Material We will spend a bit more time on CSP since it is an important problem, starting with chapter 5. Read all of chapter 5 Read Fahiem Bacchus “Constraints” Tutorial on the web (dated Oct 25 th, 2001). Reminder: Homework: Due Wed, April 20 th. –Do: Problems 3.4, , 4.7, and for 4.16, do both 8-puzzle & 8-queens, and also implement the two simple heuristics h1 and h2 given in the book. Compare all of them. Also for 4.16, devise your own novel heuristics for A* for the 8-puzzle & 8-queens problem.

4/18/2005EE5623 Outline For Today Chapter 5, Sections 1-3. Constraint Satisfaction Problems (CSP) Backtracking search for CSPs Local search for CSPs

4/18/2005EE5624 Thought Question Let us assume that there are five houses of different colors next to each other on the same road. In each house lives a man of a different nationality. Every man has his favorite drink, his favorite brand of cigarettes, and keeps pets of a particular kind. –The Englishman lives in the red house. –The Swede keeps dogs. –The Dane drinks tea. –The green house is just to the left of the white one. –The owner of the green house drinks coffee. –The Pall Mall smoker keeps birds. –The owner of the yellow house smokes Dunhills. –The man in the center house drinks milk. –The Norwegian lives in the first house. –The Blend smoker has a neighbor who keeps cats. –The man who smokes Blue Masters drinks bier. –The man who keeps horses lives next to the Dunhill smoker. –The German smokes Prince. –The Norwegian lives next to the blue house. –The Blend smoker has a neighbor who drinks water. Question for you to answer: Who keeps the fish?

4/18/2005EE5625 Constraint satisfaction problems (CSPs) Standard search problem: –state is a "black box“ – any data structure that supports successor function, heuristic function, and goal test CSP: –state is defined by variables X i with values from domain D i –goal test is a set of constraints specifying allowable combinations of values for subsets of variables This is a simple example of a formal representation language Allows useful general-purpose algorithms with more power than standard search algorithms (because of the special nature of the search space)

4/18/2005EE5626 Example: Map-Coloring Variables WA, NT, Q, NSW, V, SA, T Domains D i = {red,green,blue} Constraints: adjacent regions must have different colors e.g., WA ≠ NT, or (WA,NT) in {(red,green),(red,blue),(green,red), (green,blue),(blue,red),(blue,green)}

4/18/2005EE5627 Example: Map-Coloring Solutions are complete and consistent assignments, e.g., WA = red, NT = green,Q = red,NSW = green,V = red,SA = blue,T = green

4/18/2005EE5628 Constraint graph Binary CSP: each constraint relates two variables Constraint graph: nodes are variables, arcs are constraints

4/18/2005EE5629 Varieties of CSPs Discrete variables –finite domains: n variables, domain size d  O(d n ) complete assignments e.g., Boolean CSPs, incl.~Boolean satisfiability (NP-complete) –infinite domains: integers, strings, etc. e.g., job scheduling, variables are start/end days for each job need a constraint language in general –e.g., StartJob ≤ StartJob 3 Continuous variables –e.g., start/end times for Hubble Space Telescope observations –linear constraints solvable in polynomial time by linear programming

4/18/2005EE56210 Varieties of constraints Unary constraints involve a single variable, –e.g., SA ≠ green Binary constraints involve pairs of variables, –e.g., SA ≠ WA Higher-order constraints involve 3 or more variables, –e.g., cryptarithmetic column constraints

4/18/2005EE56211 Example: Cryptarithmetic Variables: F,T, U, W, R, O, X 1, X 2, X 3 Domains: {0,1,2,3,4,5,6,7,8,9} Constraints: Alldiff (F,T,U,W,R,O) –O + O = R + 10 · X 1 –X 1 + W + W = U + 10 · X 2 –X 2 + T + T = O + 10 · X 3 –X 3 = F, T ≠ 0, F ≠ 0

4/18/2005EE56212 Real-world CSPs Assignment problems –e.g., who teaches what class Timetabling problems –e.g., which class is offered when and where? Hardware configuration Spreadsheets Transportation scheduling Factory scheduling Floorplanning Even, Bayesian Belief Propagation!! Notice that many real-world problems involve real-valued variables

4/18/2005EE56213 Standard search formulation (incremental) Let's start with the straightforward approach, then fix it States are defined by the values assigned so far Initial state: the empty assignment { } Successor function: assign a value to an unassigned variable that does not conflict with current assignment  fail if no legal assignments Goal test: the current assignment is complete 1.This is the same for all CSPs. 2.Every solution appears at depth n with n variables  use depth-first search 3.Path is irrelevant, so can also use complete-state formulation 4.Naive approach: b = (n - l )d at depth l, hence n! · d n leaves 

4/18/2005EE56214 Backtracking search Variable assignments are commutative}, i.e., [ WA = red then NT = green ] same as [ NT = green then WA = red ] Only need to consider assignments to a single variable at each node  b = d and there are d n leaves Depth-first search for CSPs with single-variable assignments is called backtracking search Backtracking search is the basic uninformed algorithm for CSPs Can solve n-queens for n ≈ 25

4/18/2005EE56215 Backtracking search

4/18/2005EE56216 Backtracking example

4/18/2005EE56217 Backtracking example

4/18/2005EE56218 Backtracking example

4/18/2005EE56219 Backtracking example

4/18/2005EE56220 Improving backtracking efficiency General-purpose methods can give huge gains in speed: –Which variable should be assigned next? –In what order should its values be tried? –Can we detect inevitable failure early? –Can we take better advantage of the problem structure?

4/18/2005EE56221 Most constrained variable Most constrained variable: choose the variable with the fewest legal values a.k.a. minimum remaining values (MRV) heuristic

4/18/2005EE56222 Most constraining variable Tie-breaker among most constrained variables Most constraining variable: –choose the variable with the most constraints on remaining variables (degree heuristic)

4/18/2005EE56223 Least constraining value Given a variable, choose the least constraining value: –the one that rules out the fewest values in the remaining variables (useful when we want only to find one set of sat. values, not all) Combining these heuristics makes 1000 queens feasible

4/18/2005EE56224 Forward checking Idea: –Keep track of remaining legal values for unassigned variables –Terminate search when any variable has no legal values

4/18/2005EE56225 Forward checking Idea: –Keep track of remaining legal values for unassigned variables –Terminate search when any variable has no legal values

4/18/2005EE56226 Forward checking Idea: –Keep track of remaining legal values for unassigned variables –Terminate search when any variable has no legal values

4/18/2005EE56227 Forward checking Idea: –Keep track of remaining legal values for unassigned variables –Terminate search when any variable has no legal values

4/18/2005EE56228 Constraint propagation Forward checking propagates information from assigned to unassigned variables, but doesn't provide early detection for all failures: NT and SA cannot both be blue! Constraint propagation repeatedly enforces constraints locally

4/18/2005EE56229 Arc consistency Simplest form of propagation makes each arc consistent X  Y is consistent iff for every value x of X there is some allowed y We have that SA  NSW

4/18/2005EE56230 Arc consistencyd Simplest form of propagation makes each arc consistent X  Y is consistent iff for every value x of X there is some allowed y We do not have that NSW  SA

4/18/2005EE56231 Arc consistency Simplest form of propagation makes each arc consistent X  Y is consistent iff for every value x of X there is some allowed y If X loses a value, neighbors of X need to be rechecked Removing blue from NSW means that we no longer have that V  NSW

4/18/2005EE56232 Arc consistency Simplest form of propagation makes each arc consistent X  Y is consistent iff for every value x of X there is some allowed y If X loses a value, neighbors of X need to be rechecked Arc consistency detects failure earlier than forward checking Can be run as a preprocessor or after each assignment

4/18/2005EE56233 Arc consistency algorithm AC-3 Time complexity: O(n 2 d 3 ) (AC-4 is O(n 2 d 2 ))

4/18/2005EE56234 Local search for CSPs Hill-climbing, simulated annealing typically work with "complete" states, i.e., all variables assigned To apply to CSPs: –allow states with unsatisfied constraints –operators reassign variable values (perhaps even randomly change state) Variable selection: randomly select any conflicted variable and change its value. Value selection by min-conflicts heuristic: –choose value that violates the fewest constraints –i.e., hill-climb with h(n) = total number of violated constraints

4/18/2005EE56235 Example: 4-Queens States: 4 queens in 4 columns (4 4 = 256 states) Actions: move queen in column Goal test: no attacks Evaluation: h(n) = number of attacks Given random initial state, can solve n-queens in almost constant time for arbitrary n with high probability (e.g., n = 10,000,000)

4/18/2005EE56236 Summary CSPs are a special kind of problem: –states defined by values of a fixed set of variables –goal test defined by constraints on variable values Backtracking = depth-first search with one variable assigned per node Variable ordering and value selection heuristics help significantly Forward checking prevents assignments that guarantee later failure Constraint propagation (e.g., arc consistency) does additional work to constrain values and detect inconsistencies Iterative min-conflicts is usually effective in practice