Density of a Gas at STP Lesson # 4. 1.Calculate the density of N 2 at STP. Calculate Density=grams litre Assume that you have 1 mole of N 2.

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Density of a Gas at STP Lesson # 4

1.Calculate the density of N 2 at STP. Calculate Density=grams litre Assume that you have 1 mole of N 2

1.Calculate the density of N 2 at STP. Calculate Density=grams litre 28.0 g = Assume that you have 1 mole of N 2

1.Calculate the density of N 2 at STP. Calculate Density=grams litre 28.0 g = 22.4 L Assume that you have 1 mole of N 2

1.Calculate the density of N 2 at STP. Calculate Density=grams litre 28.0 g =1.25 g/L 22.4 L Assume that you have 1 mole of N 2

2.Calculate the density of CO 2 at STP. Density=grams litre Assume that you have 1 mole of CO 2

2.Calculate the density of CO 2 at STP. Calculate Density=grams litre 44.0 g = Assume that you have 1 mole of CO 2

2.Calculate the density of CO 2 at STP. Calculate Density=grams litre 44.0 g = 22.4 L Assume that you have 1 mole of CO 2

2.Calculate the density of CO 2 at STP. Calculate Density=grams litre 44.0 g =1.96 g/L 22.4 L Assume that you have 1 mole of CO 2

3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O g? L 1212

3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O g? L 12.5 g HgO x 1mole 216.6g

3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O g? L 12.5 g HgO x 1mole x 1 mole O g 2 mole HgO

3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O g? L 12.5 g HgO x 1mole x 1 mole O 2 x 22.4 L 216.6g 2 mole HgO 1 mole

3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O g? L 12.5 g HgO x 1mole x 1 mole O 2 x 22.4 L x g 2 mole HgO 1 mole

3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O g? L 12.5 g HgO x 1mole x 1 mole O 2 x 22.4 L x = L 216.6g 2 mole HgO 1 mole

4.How many litres of CO 2 are produced by the reaction of 100. g of Fe 2 O 3, if the actual yield was 19.0 STP, calculate the percentage yield L 2Fe 2 O 3 +3C  4Fe+3CO g? L 3232

4.How many litres of CO 2 are produced by the reaction of 100. g of Fe 2 O 3, if the actual yield was 19.0 STP, calculate the percentage yield L 2Fe 2 O 3 +3C  4Fe+3CO g? L 100. g Fe 2 O 3 x 1 mole x 3 mole CO 2 x 22.4 L = L g 2 mole Fe 2 O 3 1 mole Percentage yield = 19.0 L x 100% = 90.3 % L 3232