Chapter 1B (modified)

Give an explanation of the midpoint formula and WHY it works to find the midpoint of a segment.

Quadrant I (+,+) Quadrant II (-,+) Quadrant IV (+,-) Quadrant III (-,-)

A B D E Find the length of AB, BD, and DE:

The distance between any two points with coordinates (x 1,y 1 ) and (x 2,y 2 ) is given by the formula:

Find the distance of LM is L(-6,4) and M(2,3).

Find the distance of AB if A(-11,-1) and B(2,5)

A B D E Find the midpoint of AB, BD, and DE:

In a coordinate plane the coordinates of the midpoint of a segment whose endpoints have coordinates (x 1,y 1 ) and (x 2,y 2 ) is given by the formula:

Find the coordinates of the midpoint M of QS with endpoints Q(3,5) and S(7,-9)

The midpoint of AB is M. If the coordinates of M are (3,-4) and A(2,3) what are the coordinates of B?

Homework: Lesson #1 – The Coordinate Plane (on Moodle)

Explain why a horizontal line has a slope of 0, yet a vertical line has a slope that is undefined.

The ratio of the vertical change to the horizontal change between any two points on a line. Rise Run Positive Slope Negative Slope

Zero Slope Horizontal Line Undefined Slope Vertical Line

Find the slope of the line.

Rise y 2 – y 1 Run x 2 – x 1 =

Find the slope of the line that contains the following points. (-3,-4) and (5,-4)(-2,2) and (4,-2) (-3,3) and (-3,1)(3,0) and (0,-5)

A linear equation in the form y = mx + b Slope Rise Run y-intercept Where the graph touches the y-axis x = 0

Graph each equation y = 3x – 4y = -2x - 1

Write an equation for each line

The slopes of parallel lines are equal. Vertical lines are parallel to one another. Horizontal lines are parallel to one another.

Write an equation for each line

The slopes of perpendicular lines are opposite reciprocals of one another. Vertical Lines are perpendicular to horizontal lines.

Determine which lines are parallel and which are perpendicular. a)y = 2x + 1 b)y = -x c)y = x – 4 d)y = 2x e)y = -2x + 3

Determine if AB and CD are parallel, perpendicular, or neither. A(-3,2) B(5,1)A(4.5,5) B(2,5) C(2,7) D(1,-1)C(1.5,-2) D(3,-2)

Homework: Lesson #2a – Parallel and Perpendicular Lines (on Moodle)

A linear equation in the form (y – y 1 ) = m(x – x 1 ) Slope Rise Run Point The coordinates of any point on the line

Example: m = 2 and the line passes through (4,3) 1.Put the slope and the coordinates of one point in the point-slope form 2. Simplify to slope intercept form (y = mx + b)

Write an equation for a line with the given slope and passes through the given point. m = -3 and (5,8)m = 2/3 and (6,9)

Example: A line passes through (9,-2) and (3,4) 1.Calculate slope 2.Put the slope and the coordinates of one point in the point-slope form 3.Simplify to slope intercept form (y = mx + b)

Write an equation for a line that passes through the given points. (1,2) and (3,8)(8,-3) and (4,-4)

Homework: Lesson #2b - Glencoe Algebra 1 Practice Worksheet 4-2 (on Moodle)

Describe two ways to determine which region of the plane should be shaded for linear inequalities.

An expression using >, <, ≥, or ≤. y < 5x + 6 The solution is a region of the coordinate plane, whose coordinate satisfy the given inequality.

Determine if the following points are solutions to the inequality: y < 5x + 6 (4,26)(-1,-5)

1.Solve the inequality for y (slope-intercept form). ~~IF YOU MULTIPLY OR DIVIDE BY A NEGATIVE FLIP THE SIGN~~

Graph the inequality: -2x – 3y ≤ 3

2. Graph the equation. EQUAL- a solid line. ( ≥,≤ ) NOT EQUAL TO- a dotted line (>, <)

Graph the inequality: -2x – 3y ≤ 3

3. Shade the plane. LESS THAN- Shade BELOW the line. ( <,≤ ) GREATER THAN- Shade ABOVE the line. ( >, ≥ )

Graph the inequality: -2x – 3y ≤ 3

Graph the inequality: -2x – 3y ≤ 3

Graph the inequality: y > 3x + 1

Graph the inequality: 2x + y < -2

Homework: Lesson #3 - Glencoe Algebra 1 Skills Practice 5-6 (on Moodle)