GeometryGeometry 6.2 Arcs and Chords Homework: Lesson 6.2/1-12,18 Quiz on Friday on Yin Yang Due Friday

Geometry Geometry Objectives/Assignment Use properties of arcs of circles.. Use properties of chords of circles.

Geometry Geometry Using Arcs of Circles In a plane, an angle whose vertex is the center of a circle is a central angle of the circle. If the measure of a central angle,  APB is less than 180 °, then A and B and the points of P

Geometry Geometry Using Arcs of Circles in the interior of  APB form a minor arc of the circle. The points A and B and the points of P in the exterior of  APB form a major arc of the circle. If the endpoints of an arc are the endpoints of a diameter, then the arc is a semicircle.

Geometry Geometry Naming Arcs Arcs are named by their endpoints. For example, the minor arc associated with  APB above is. Major arcs and semicircles are named by their endpoints and by a point on the arc. 60 ° 180 °

Geometry Geometry Naming Arcs For example, the major arc associated with  APB is. here on the right is a semicircle. The measure of a minor arc is defined to be the measure of its central angle. 60 ° 180 °

Geometry Geometry Naming Arcs For instance, m = m  GHF = 60 °. m is read “the measure of arc GF.” You can write the measure of an arc next to the arc. The measure of a semicircle is always 180°. 60 ° 180 °

Geometry Geometry Naming Arcs The measure of a major arc is defined as the difference between 360° and the measure of its associated minor arc. For example, m = 360° - 60° = 300°. The measure of the whole circle is 360°. 60 ° 180 °

Geometry Geometry Ex. 1: Finding Measures of Arcs Find the measure of each arc of R. a. b. c. 80 °

Geometry Geometry Ex. 1: Finding Measures of Arcs Find the measure of each arc of R. a. b. c. Solution: is a minor arc, so m = m  MRN = 80 ° 80 °

Geometry Geometry Ex. 1: Finding Measures of Arcs Find the measure of each arc of R. a. b. c. Solution: is a major arc, so m = 360 ° – 80 ° = 280 ° 80 °

Geometry Geometry Ex. 1: Finding Measures of Arcs Find the measure of each arc of R. a. b. c. Solution: is a semicircle, so m = 180 ° 80 °

Geometry Geometry Note: Two arcs of the same circle are adjacent if they intersect at exactly one point. You can add the measures of adjacent areas. Arc Addition Conjecture The measure of an arc formed by two adjacent arcs is the sum of the measures of the two arcs. m = m + m

Geometry Geometry Ex. 2: Finding Measures of Arcs Find the measure of each arc. a. b. c. m = m + m = 40 ° + 80° = 120° 40 ° 80 ° 110 °

Geometry Geometry Ex. 2: Finding Measures of Arcs Find the measure of each arc. a. b. c. m = m + m = 120 ° + 110° = 230° 40 ° 80 ° 110 °

Geometry Geometry Ex. 2: Finding Measures of Arcs Find the measure of each arc. a. b. c. m = 360 ° - m = 360 ° - 230° = 130° 40 ° 80 ° 110 °

Geometry Geometry Ex. 3: Identifying Congruent Arcs Find the measures of the blue arcs. Are the arcs congruent? and are in the same circle and m = m = 45 °. So,  45 °

Geometry Geometry Ex. 3: Identifying Congruent Arcs Find the measures of the blue arcs. Are the arcs congruent? and are in congruent circles and m = m = 80 °. So,  80 °

Geometry Geometry m = m = 65°, but and are not arcs of the same circle or of congruent circles, so and are NOT congruent. Ex. 3: Identifying Congruent Arcs Find the measures of the blue arcs. Are the arcs congruent? 65 °

Geometry Geometry Chord Arcs Conjecture In the same circle, or in congruent circles, two minor arcs are congruent if and only if their corresponding chords are congruent.  if and only if 

Geometry Geometry Perpendicular Bisector of a Chord Conjecture If a diameter of a circle is perpendicular to a chord, then the diameter bisects the chord and its arc. , 

Geometry Geometry Perpendicular Bisector to a Chord Conjecture If one chord is a perpendicular bisector of another chord, then the first chord passes through the center of the circle and is a diameter. is a diameter of the circle.

Geometry Geometry Ex. 4: Using Chord Arcs Conj. You can use Theorem 10.4 to find m. Because AD  DC, and . So, m = m 2x = x + 40Substitute x = 40 Subtract x from each side. 2x ° (x + 40) °

Geometry Geometry Ex. 5: Finding the Center of a Circle Theorem 10.6 can be used to locate a circle’s center as shown in the next few slides. Step 1: Draw any two chords that are not parallel to each other.

Geometry Geometry Ex. 5: Finding the Center of a Circle Step 2: Draw the perpendicular bisector of each chord. These are the diameters.

Geometry Geometry Ex. 5: Finding the Center of a Circle Step 3: The perpendicular bisectors intersect at the circle’s center.

Geometry Geometry Ex. 6: Using Properties of Chords Masonry Hammer. A masonry hammer has a hammer on one end and a curved pick on the other. The pick works best if you swing it along a circular curve that matches the shape of the pick. Find the center of the circular swing.

Geometry Geometry Ex. 6: Using Properties of Chords Draw a segment AB, from the top of the masonry hammer to the end of the pick. Find the midpoint C, and draw perpendicular bisector CD. Find the intersection of CD with the line formed by the handle. So, the center of the swing lies at E.

Geometry Geometry In the same circle, or in congruent circles, two chords are congruent if and only if they are equidistant from the center. AB  CD if and only if EF  EG. Chord Distance to the Center Conjecture

Geometry Geometry Ex. 7: AB = 8; DE = 8, and CD = 5. Find CF.

Geometry Geometry Ex. 7: Because AB and DE are congruent chords, they are equidistant from the center. So CF  CG. To find CG, first find DG. CG  DE, so CG bisects DE. Because DE = 8, DG = =4.

Geometry Geometry Ex. 7: Then use DG to find CG. DG = 4 and CD = 5, so ∆CGD is a right triangle. So CG = 3. Finally, use CG to find CF. Because CF  CG, CF = CG = 3

Geometry Geometry Reminders: Quiz on Friday on Yin Yang Due Friday