1. Describe the end behavior of the graph y = 2x 5 – 3x Sketch a graph of 3 rd degree with a zero at -5 (multiplicity 2) and a zero at 0 (multiplicity 1). 1

Real Zeros of Polynomial Functions.

 To solve, you factor the problem, each factor must be factored down to at most a quadratic.  To solve, put each factor equal to zero. 3

1. 2x x = 14x 3 2x 5 – 14x x = 0 2x(x 4 – 7x ) = 0 2x(x 2 – 3)(x 2 – 4) = 0 2x=0 x 2 –3=0 x 2 –4=0 x=0 x 2 =3 x 2 = 4 x=±√3 x = ±2 2. 2y 5 – 18y = 0 2y(y 4 – 9) = 0 2y(y 2 – 3)(y 2 + 3) = 0 2y=0 y 2 –3=0 y 2 +3=0 y=0 y 2 = 3 y 2 = –3 y=±√3 y=±i√3 4

 Long Division  Synthetic Division 5

Divide 3x 3 – 5x x – 3 by 3x + 1 3x + 1 ) 3x 3 – 5x x – 3 6 Algebra II x2x2 3x 3 + x 2 -6x x - 2x -6x 2 - 2x 12x x x + 1 +

Divide 2x 3 – 7x 2 – 17x – 3 by 2x + 3 2x + 3 ) 2x 3 – 7x 2 – 17x – 3 7 x2x2 2x 3 + 3x 2 -10x x - 5x -10x x - 2x x - 3 0

Divide 6x 2 + x – 7 by 2x + 3 2x + 3 ) 6x 2 + x – 7 8 3x 6x 2 + 9x -8x x x + 3 +

Divide 4x 3 + 5x 2 - 3x + 10 by x x 2 + 0x + 3 ) 4x 3 + 5x 2 – 3x x 4x 3 + 0x x 5x 2 – 15x X 2 + 0x x – 5 x 2 + 3

Divide -3x 3 + 4x – 1 by x - 1 x - 1 ) -3x 3 + 0x 2 + 4x – x 2 -3x 3 + 3x 2 -3x 2 + 4x - 3x -3x 2 + 3x 1x x - 1 0

 Divide a polynomial by a binomial  The polynomial must be in standard form  Be sure to add zeros when needed for missing placeholders  The divisor must be a linear binomial with a leading coefficient of 1 and in the form x + k 11 Algebra II

12 Divide x 3 + 2x 2 – 3x - 6 by x + 2. X = times Now solve x 2 – 3 = 0 to find the remaining zeros

13 Divide 6x 3 – 19x x - 4 by x - 2. X = times Now solve 6x 2 – 7x + 2 = 0 +++

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V = x 3 + 9x 2 – x – 105 Given sides: x – 3 and x Algebra II

 Divide 6x x 2 – 12x – 13 by 3x + 1 using long division.  Divide 10x 3 – 10x 2 – 2x + 4 by x + 3 using synthetic division.  Factor 4x 3 – 3x 2 – 25x – 6 using synthetic division given that one zero is -2.  Solve 6x x 2 – 33x + 10 given that one zero is Algebra II