Complex Numbers (and the imaginary number i)

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Presentation transcript:

Complex Numbers (and the imaginary number i) Standard 6.0 Complex Numbers (and the imaginary number i) Complex numbers are composed of two parts a real part and an imaginary part. We call this standard form. Examples 5 + 4i Real Part Imaginary Part Try to figure out the following:

Complex Numbers (adding and subtracting) Standard 6.0 Complex Numbers (adding and subtracting) When adding or subtracting complex numbers we must add/subtract the real parts of both complex numbers. And then add/subtract the imaginary parts of both complex numbers Example: (2 + 3i) + ( -3 – 4i ) = (2-3) + (3i – 4i) = -1 - i Example: (2 + 3i) - ( -3 – 4i ) = ( 2 + 3i ) + 3 + 4i (2 + 3) + (3i + 4i) = 5 + 7i

Add and subtract complex numbers Standard 6.0 Add and subtract complex numbers Write the expression as a complex number in standard form. a. (8 – i) + (5 + 4i) b. (7 – 6i) – (3 – 6i) c. 10 – (6 + 7i) + 4i SOLUTION a. (8 – i) + (5 + 4i) = Definition of complex addition (8 + 5) + (–1 + 4)i = 13 + 3i Write in standard form. b. (7 – 6i) – (3 – 6i) = Definition of complex subtraction (7 – 3) + (–6 + 6)i = 4 + 0i Simplify. = 4 Write in standard form.

Add and subtract complex numbers EXAMPLE 2 Add and subtract complex numbers c. 10 – (6 + 7i) + 4i = Definition of complex subtraction [(10 – 6) – 7i] + 4i = (4 – 7i) + 4i Simplify. = 4 + (–7 + 4)i Definition of complex addition = 4 – 3i Write in standard form.

GUIDED PRACTICE for Example 2 Write the expression as a complex number in standard form. 7. (9 – i) + (–6 + 7i) ANSWER 3 + 6i 8. (3 + 7i) – (8 – 2i) ANSWER –5 + 9i 9. –4 – (1 + i) – (5 + 9i) ANSWER –10 – 10i

Multiply complex numbers Standard 6.0 Multiply complex numbers Write the expression as a complex number in standard form. a. 4i(–6 + i) b. (9 – 2i)(–4 + 7i) SOLUTION a. 4i(–6 + i) = –24i + 4i2 Distributive property = –24i + 4(–1) Use i2 = –1. = –24i – 4 Simplify. = –4 – 24i Write in standard form.

Multiply complex numbers EXAMPLE 4 Multiply complex numbers b. (9 – 2i)(–4 + 7i) = –36 + 63i + 8i – 14i2 Multiply using FOIL. = –36 + 71i – 14(–1) Simplify and use i2 = – 1 . = –36 + 71i + 14 Simplify. = –22 + 71i Write in standard form.

Divide complex numbers Standard 6.0 Divide complex numbers Before we can divide we must understand what a conjugate is. Conjugate- Is an identical complex number but, in the imaginary part the sign changes. Why is the conjugate important? It is important because when we multiply a complex number by its conjugate the imaginary part disappears. (think of it as the difference of two squares) Examples of conjugates: -3 + 2 i - 3 – 2 i 4 – i 4 + i

Divide complex numbers Standard 6.0 Divide complex numbers Write the quotient in standard form. 7 + 5i 1  4i 7 + 5i 1 – 4i = 1 + 4i Multiply numerator and denominator by 1 + 4i, the complex conjugate of 1 – 4i. 7 + 28i + 5i + 20i2 1 + 4i – 4i – 16i2 = Multiply using FOIL. 7 + 33i + 20(–1) 1 – 16(–1) = Simplify and use i2 = -1. –13 + 33i 17 = Simplify.

Divide complex numbers EXAMPLE 5 Divide complex numbers 13 17 – = + 33 i Write in standard form.

GUIDED PRACTICE for Examples 3, 4 and 5 Write the expression as a complex number in standard form. 5 1 + i 11. i(9 – i) 13. 5 2 – i ANSWER 1 + 9i ANSWER 14. 5 + 2i 12. (3 + i)(5 – i) 3 – 2i 11 13 + 16 i ANSWER 16 + 2i ANSWER