Section 1Chapter 3. 1 Copyright © 2012, 2008, 2004 Pearson Education, Inc. Objectives 2 6 7 5 3 4 The Rectangular Coordinate System Interpret a line graph.

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Presentation transcript:

Section 1Chapter 3

1 Copyright © 2012, 2008, 2004 Pearson Education, Inc. Objectives The Rectangular Coordinate System Interpret a line graph. Plot ordered pairs. Find ordered pairs that satisfy a given equation. Graph lines. Find x- and y-intercepts. Recognize equations of horizontal and vertical lines and lines passing through the origin. Use the midpoint formula. 3.1

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Interpret a line graph. Objective 1 Slide

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Slide Interpret a line graph. The line graph in the figure to the right presents information based on a method for locating a point in a plane developed by René Descartes, a 17 th -century French mathematician. Today, we still use this method to plot points and graph linear equations in two variables whose graphs are straight lines.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Plot ordered pairs. Objective 2 Slide

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Each of the pair of numbers (3, 2), (  5, 6), and (4,  1) is an example of an ordered pair. An ordered pair is a pair of numbers written within parentheses, consisting of a first component and a second component. We graph an ordered pair by using two perpendicular number lines that intersect at their 0 points, as shown in the plane in the figure to the right. The common 0 point is called the origin. The first number in the ordered pair indicates the position relative to the x-axis, and the second number indicates the position relative to the y-axis. Slide Plot ordered pairs.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. The position of any point in this plane is determined by referring to the horizontal number line, or x-axis, and the vertical number line, or y-axis. The x-axis and the y-axis make up a rectangular (or Cartesian) coordinate system. The four regions of the graph, shown below, are called quadrants I, II, III, and IV, reading counterclockwise from the upper right quadrant. The points on the x-axis and y-axis to not belong to any quadrant. Slide Plot ordered pairs.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Find ordered pairs that satisfy a given equation. Objective 3 Slide

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Complete the table of ordered pairs for 3x – 4y = 12. xy 0 0 22 66 33 a. (0, __) Replace x with 0 in the equation to find y. 3x – 4y = 12 3(0) – 4y = 12 0 – 4y = 12 –4y = 12 y = –3 Slide CLASSROOM EXAMPLE 1 Completing Ordered Pairs and Making a Table Solution:

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Complete the table of ordered pairs for 3x – 4y = 12. xy 0 0 22 66 b. (__, 0) Replace y with 0 in the equation to find x. 3x – 4y = 12 3x – 4(0) = 12 3x – 0 = 12 3x = 12 x = 4 4 Slide CLASSROOM EXAMPLE 1 Completing Ordered Pairs and Making a Table (cont’d) Solution: 33

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Complete the table of ordered pairs for 3x – 4y = 12. xy 0 0 22 66 c. (__,  2) Replace y with  2 in the equation to find x. 3x – 4y = 12 3x – 4(  2) = 12 3x + 8 = 12 3x = 4 Slide CLASSROOM EXAMPLE 1 Completing Ordered Pairs and Making a Table (cont’d) Solution: 33 4

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Complete the table of ordered pairs for 3x – 4y = 12. xy 0 0 22 66 d. (  6, __) Replace x with  6 in the equation to find y. 3x – 4y = 12 3(  6) – 4y = 12  18 – 4y = 12 –4y = 30 Slide CLASSROOM EXAMPLE 1 Completing Ordered Pairs and Making a Table (cont’d) Solution: 33 4

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Graph lines. Objective 4 Slide

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Linear Equation in Two Variables A linear equation in two variables can be written in the form Ax + By = C, where A, B, and C are real numbers and A and B not both 0. This form is called standard form. The graph of an equation is the set of points corresponding to all ordered pairs that satisfy the equation. It gives a “picture” of the equation. Slide Graph lines.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Find x- and y-intercepts. Objective 5 Slide

Copyright © 2012, 2008, 2004 Pearson Education, Inc. A straight line is determined if any two different points on a line are known. Therefore, finding two different points is enough to graph the line. The x-intercept is the point (if any) where the line intersects the x- axis; likewise, the y-intercept is the point (if any) where the line intersects the y-axis. Slide Find x- and y- intercepts.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Finding Intercepts When graphing the equation of a line, find the intercepts as follows. Let y = 0 to find the x-intercept. Let x = 0 to find the y-intercept. Slide Find x- and y- intercepts. While two points, such as the two intercepts are sufficient to graph a straight line, it is a good idea to use a third point to guard against errors.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Find the x-and y-intercepts and graph the equation 2x – y = 4. x-intercept: Let y = 0. 2x – 0 = 4 2x = 4 x = 2 (2, 0) y-intercept: Let x = 0. 2(0) – y = 4 –y = 4 y = –4 (0, –4) Slide CLASSROOM EXAMPLE 2 Finding Intercepts Solution:

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Recognize equations of horizontal and vertical lines and lines passing through the origin. Objective 6 Slide

Copyright © 2012, 2008, 2004 Pearson Education, Inc. A line parallel to the x-axis will not have an x-intercept. Similarly, a line parallel to the y-axis will not have a y-intercept. Slide Recognize equations of horizontal and vertical lines and lines passing through the origin.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Graph y = 3. Writing y = 3 as 0x + 1y = 3 shows that any value of x, including x = 0, gives y = 3. Since y is always 3, there is no value of x corresponding to y = 0, so the graph has no x-intercepts. xy The graph y = 3 is a line not a point. Slide CLASSROOM EXAMPLE 3 Graphing a Horizontal Line Solution: The horizontal line y = 0 is the x-axis.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Graph x + 2 = 0. 1x + 0y =  2 shows that any value of y, leads to x =  2, making the x-intercept (  2, 0). No value of y makes x = 0. xy 22 0 22 2 The graph x + 2 = 0 is not just a point. The graph is a line. Slide CLASSROOM EXAMPLE 4 Graphing a Vertical Line Solution: The vertical line x = 0 is the y-axis.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Graph 3x  y = 0. Find the intercepts. x-intercept: Let y = 0. 3x – 0 = 0 3x = 0 x = 0 y-intercept: Let x = 0. 3(0) – y = 0 –y = 0 y = 0 The x-intercept is (0, 0). The y-intercept is (0, 0). Slide CLASSROOM EXAMPLE 5 Graphing a Line That Passes through the Origin Solution:

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Use the midpoint formula. Objective 7 Slide

Copyright © 2012, 2008, 2004 Pearson Education, Inc. If the coordinates of the endpoints of a line segment are known, then the coordinates of the midpoint (M) of the segment can be found by averaging the coordinates of the endpoints. Slide Use the midpoint formula.

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Midpoint Formula If the endpoints of a line segment PQ are (x 1, y 1 ) and (x 2, y 2 ), its midpoint M is Slide Use the midpoint formula. In the midpoint formula, the small numbers 1 and 2 in the ordered pairs are called subscripts, read as “x-sub-one and y-sub-one.”

Copyright © 2012, 2008, 2004 Pearson Education, Inc. Find the coordinates of the midpoint of line segment PQ with endpoints P(–5, 8) and Q(2, 4). Use the midpoint formula with x 1 = –5, x 2 = 2, y 1 = 8, and y 2 = 4: Slide CLASSROOM EXAMPLE 6 Finding the Coordinates of a Midpoint Solution: