10.3 Properties of Fluids  A fluid is defined as any matter that flows when force is applied.  Liquids like water or silver are kinds of fluid.

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Presentation transcript:

10.3 Properties of Fluids  A fluid is defined as any matter that flows when force is applied.  Liquids like water or silver are kinds of fluid.

10.3 Forces in fluids  Forces in fluids are more complicated than forces in solids because fluids can change shape.

10.3 Pressure  A force applied to a fluid creates pressure.  Pressure acts in all directions, not just the direction of the applied force.

10.3 Units of pressure  The units of pressure are force divided by area.  One psi is one pound per square inch.

10.3 Units of pressure  The S.I. unit of force is the pascal.  One pascal (unit of force) is one newton of force per square meter of area (N/m 2 ).

10.3 Pressure  On the microscopic level, pressure comes from collisions between atoms.  Every surface can experience a force from the constant impact of trillions of atoms.  This force is what we measure as pressure.

10.3 Pressure  If your car tires are inflated to 35 pounds per square inch (35 psi), then a force of 35 pounds acts on every square inch of area inside the tire. What might happen if you over-inflate a tire?

10.3 Boyle’s Law  When you squeeze a fixed quantity of gas into a smaller volume the pressure goes up.  This rule is known as Boyle’s law.

10.3 Boyle’s Law  The formula for Boyle’s law relates the pressure and volume of gas.  If the mass and temperature are kept constant, the product of the pressure multiplied by the volume stays the same.

Solving Problems A kit used to fix flat tires consists of an aerosol can containing compressed air and a patch to seal the hole in the tire. Suppose 5 liters of air at atmospheric pressure (1 atm) is compressed into a 0.5 liter aerosol can. What is the pressure of the compressed air in the can? Assume no change in temperature or mass.

 Looking for:  …final pressure in atmospheres (P 2 )  Given  …V 1 = 5 L, P 1 = 1 atm, V 2 =.5 L  Relationships:  Boyle’s Law: P 1 V 1 = P 2 V 2  Solution  Rearrange equation so P 2 = P 1 V 1 / V 2  P 2 = 1atm x 5.0 L/ 0.5 L = 10 atm. Solving Problems

10.3 Viscosity  Viscosity is the property of fluids that causes friction.  Viscosity is determined in large part by the shape and size of the particles in a liquid.

10.3 Viscosity and temperature  As the temperature of a liquid increases, the viscosity of a liquid decreases.  Increasing the kinetic energy of the substance allows the particles to slide past one another more easily.