Chapter 8 The Mole Part 2 What is Avogadro’s Favorite Music.

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Presentation transcript:

Chapter 8 The Mole Part 2

What is Avogadro’s Favorite Music

a

Why 6.02 x Take the gram formula mass of any substance. Convert grams into amu. Convert amu to particles.

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol) g C mol

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol). Convert grams into amu (1.66 x g = 1amu) 12.0 g C mol g

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol). Convert grams into amu (1.66 x g = 1amu) 12.0 g C amu atom mol g

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol). Convert grams into amu (1.66 x g = 1amu) 12.0 g C1 amu mol 1.66 x g

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol). Convert grams into amu (1.66 x g = 1amu) Convert amu to particles g C1 amu mol 1.66 x g amu

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol). Convert grams into amu (1.66 x g = 1amu) Convert amu to particles g C1 amu C atom mol 1.66 x g amu

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol). Convert grams into amu (1.66 x g = 1amu) Convert amu to particles g C1 amu C atom mol 1.66 x g12.0 amu = 6.02 x C atoms/mol

Why 6.02 x Take the gram formula mass of any substance (example H 2 O = 18.0g/mol). Convert grams into amu (1.66 x g = 1amu) Convert amu to particles g H 2 O1 amu H 2 O molecules mol 1.66 x g 18.0 amu = 6.02 x H 2 O molecules/mol

Why 6.02 x Take the gram formula mass of any substance (example C = 12.0g/mol and H 2 O = 18.0g/mol). Use the conversion factor 1.66 x g/amu. Determine the number of particles in 1 mole g C1 amu C atom mol 1.66 x g12.0 amu = 6.02 x C atoms/mol 18.0 g H 2 O1 amu H 2 O molecules mol 1.66 x g 18.0 amu = 6.02 x H 2 O molecules/mol

Why 6.02 x It turns out that whenever we take an amount of a substance equal to it’s formula mass in grams we will have 6.02 x particles of that substance. This number was named Avogadro’s number and is called a mole g C1 amu C atom mol 1.66 x g12.0 amu = 6.02 x C atoms/mol 18.0 g H 2 O1 amu H 2 O molecules mol 1.66 x g 18.0 amu = 6.02 x H 2 O molecules/mol

Converting Moles and Grams Aluminum is often used for the structure of light-weight bicycle frames. How many grams of Al are in 3.62 moles of Al? a

1 mole Al = ?

1 mole Al = 27.0 g Al

What are the conversion factors?

1 mole Al = 27.0 g Al 27.0g Al or 1 mol Al 1 mol Al 27.0 g Al What are the conversion factors?

1 mole Al = 27.0 g Al 27.0g Al or 1 mol Al 1 mol Al 27.0 g Al What are the conversion factors? Aluminum is often used for the structure of light- weight bicycle frames. How many grams of Al are in 3.62 moles of Al?

1 mole Al = 27.0 g Al Conversion factors for Al 27.0g Al or 1 mol Al 1 mol Al 27.0 g Al 3.62 moles Al

1 mole Al = 27.0 g Al Conversion factors for Al 27.0g Al or 1 mol Al 1 mol Al 27.0 g Al 3.62 moles Al 27.0 g Al 1 mole Al = 97.7g Al

A can of diet cola contains about mg of the artificial sweetener aspartame (Nutra-Sweet) formula C 14 H 18 N 2 O 5. It is used to sweeten diet foods, coffee and soft drinks. How many moles of aspartame are present in a can of diet cola?

200.0 mg

A can of diet cola contains about mg of the artificial sweetener aspartame (Nutra-Sweet) formula C 14 H 18 N 2 O 5. It is used to sweeten diet foods, coffee and soft drinks. How many moles of aspartame are present in a can of diet cola? mg mg 0.001g

A can of diet cola contains about mg of the artificial sweetener aspartame (Nutra-Sweet) formula C 14 H 18 N 2 O 5. It is used to sweeten diet foods, coffee and soft drinks. How many moles of aspartame are present in a can of diet cola? 14(12.0) + 18(1.0) + 2(14.0) + 5(16.0) = g/mol mg mg 0.001g g mol

A can of diet cola contains about mg of the artificial sweetener aspartame (Nutra-Sweet) formula C 14 H 18 N 2 O 5. It is used to sweeten diet foods, coffee and soft drinks. How many moles of aspartame are present in a can of diet cola? 14(12.0) + 18(1.0) + 2(14.0) + 5(16.0) = g/mol mg mg 0.001g g mol x mol C 14 H 18 N 2 O 5

How many aspartame molecules would you consume for each can of diet cola that you drank?

6.803 x mol C 14 H 18 N 2 O 5

How many aspartame molecules would you consume for each can of diet cola that you drank? x mol C 14 H 18 N 2 O 5 mol

How many aspartame molecules would you consume for each can of diet cola that you drank? x mol C 14 H 18 N 2 O 5 mol molecules

How many aspartame molecules would you consume for each can of diet cola that you drank? x mol C 14 H 18 N 2 O 5 mol 6.02 x molecules = 4.10 x C 14 H 18 N 2 O 5 molecules 410,000,000,000,000,000, million trillion aspartame molecules

1mol of C 14 H 18 N 2 O 5 How many C 14 H 18 N 2 O 5 ’s? –6.02 x C 14 H 18 N 2 O 5 molecules How many carbon atoms? –14(6.02 x ) C atoms How many hydrogen atoms? –18(6.02 x ) H atoms How many nitrogen atoms? –2(6.02 x ) N atoms How many oxygen atoms? –5(6.02 x ) O atoms How many total atoms? –39(6.02 x ) atoms What does it weigh? –294.0 g

How many carbon atoms would be contained in 145g of aspartame? 4.16 x C atoms

How many grams of aspartame contain 8.74 x oxygen atoms? 8.54 g of aspartame

Homework Mole Worksheet 2 –there is a front and a back to this worksheet.