 Momentum  A.K.A. The difference between moving and standing still.

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Presentation transcript:

 Momentum  A.K.A. The difference between moving and standing still.

ASTRONAUT Edward H. White II floats in the zero gravity of space. By firing the gas-powered gun, he gains momentum and maneuverability. Credit: NASA

Definition Mathematical Momentum = Mass (kg) x Velocity (m/s) Or p=mv The units for momentum are kgm/s Verbal Momentum is “inertia in motion”. Remember Newton’s 1 st law. It’s analogous to Inertia.

Momentum = mass x velocity Momentum is a true measure of how difficult it is to stop something.Momentum is a true measure of how difficult it is to stop something. –A charging hippo can do some damage, a hippo charging twice as fast can do twice the damage. –Calculating momentum is easy, just find the mass and the velocity and multiply. p = mv –Notice that mass and velocity both affect momentum equally.

Impulse – where momentum comes from! Only a force can “give” something momentum (or take it away). –Lets say you are a member of a bobsled team. You push the sled to speed it up. The longer the you push the sled the greater the velocity and the greater the momentum you give it so time is also a factor. –Or think about the airbags in your car. They give you more time to slow down so less force is applied to your body. So… a force applied for a certain time leads to a change in momentum. Δp = (Force) x (time) This is called an impulse (J) J = Ft Impulse is a change in momentum ( ∆ mV) ∆ mV = Ft J = m ∆ V = Ft The units for impulse are the same as momentum (kgm/s)

IMPULSE tt F J = F  t Impulse: Impulse J is a force F acting for a small time interval  t.

Example 1: The face of a golf club exerts an average force of 4000 N for s. What is the impulse imparted to the ball? tt F J = F  t Impulse: J = (4000 N)(0.002 s) J = 8.00 N  s The unit for impulse is the Newton-second (N s)

Impulse from a Varying Force Normally, a force acting for a short interval is not constant. It may be large initially and then play off to zero as shown in the graph. F time, t In the absence of calculus, we find the area under the curve

Example 2: Two flexible balls collide. The ball B exerts an average force of 1200 N on ball A. How long were the balls in contact if the impulse is 5 N s?  t = s The impulse is negative; the force on ball A is to the left. Unless told otherwise, treat forces as average forces. BA

Impulse Changes Velocity Consider a mallet hitting a ball: F Impulse = Change in “mv”

Momentum Defined Momentum p is defined as the product of mass and velocity, mv. Units: kg m/s p = mv Momentum m = 1000 kg v = 16 m/s p = (1000 kg)(16 m/s) p = 16,000 kg m/s

Impulse and Momentum Impulse = Change in momentum F  t = mv f - mv o tt F mv A force F acting on a ball for a time  t increases its momentum mv.

Example 3: A 50-g golf ball leaves the face of the club at 20 m/s. If the club is in contact for s, what average force acted on the ball? tt F mv Given: Given: m = 0.05 kg; v o = 0;  t = s; v f = 20 m/s + Choose right as positive. F  t = mv f - mv o F (0.002 s) = (0.05 kg)(20 m/s) Average Force: F = 500 N 0

Vector Nature of Momentum Consider the change in momentum of a ball that is dropped onto a rigid plate: vovo vfvf A 2-kg ball strikes the plate with a speed of 20 m/s and rebounds with a speed of 15 m/s. What is the change in momentum? +  p = mv f - mv o = (2 kg)(15 m/s) - (2 kg)(-20 m/s)  p = 30 kg m/s + 40 kg m/s  p = 70 kg m/s

Directions Are Essential 1. Choose and label a positive direction. + vfvf v0v0 v f – v 0 = (10 m/s) – (-30 m/s) 2. A velocity is positive when with this direction and negative when against it. Assume v 0 is 30 m/s to the left and v f is 10 m/s to the right. What is the change in velocity  v? v f = +10 m/s v 0 = -30 m/s

Example 4: A 500-g baseball moves to the left at 20 m/s striking a bat. The bat is in contact with the ball for s, and it leaves in the opposite direction at 40 m/s. What was average force on ball? 40 m/s tt F 20 m/s m = 0.5 kg F  t = mv f - mv o F(0.002 s) = (0.5 kg)(40 m/s) - (0.5 kg)(-20 m/s) v o = -20 m/s; v f = 40 m/s Continued...

Example Continued: 40 m/s tt F 20 m/s m = 0.5 kg F  t = mv f - mv o F(0.002 s) = (0.5 kg)(40 m/s) - (0.5 kg)(-20 m/s) F(0.002 s) = (20 kg m/s) + (10 kg m/s) F(0.002 s) = 30 kg m/s F = 15,000 N

Summary of Formulas: Momentum p = mv Impulse J = F avg  t Impulse = Change in momentum F  t = mv f - mv o

Impulse and Momentum